blocks|key|1467732|text|我不认为有内置的方法，但我认为最简单的方法是|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1467733|++char[]+alpha+=+"ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray();|code-block|syntax|javascript|1467734|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I don't think there is a built in way, but I think the easiest would be 

<pre><code> char[] alpha = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray();
</code></pre>

blocks|key|1683070|text|C#+3.0：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1683071|char[]+az+=+Enumerable.Range('a',+'z'+-+'a'+%2B+1).Select(i+=>+(Char)i).ToArray();
foreach+(var+c+in+az)
{
++++Console.WriteLine(c);
}|code-block|syntax|javascript|1683072|是的，即使Enumerable.Range的唯一重载接受int参数，它也可以工作;-)|1683073|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

C# 3.0 :

<pre><code>char[] az = Enumerable.Range('a', 'z' - 'a' + 1).Select(i =&gt; (Char)i).ToArray();
foreach (var c in az)
{
 Console.WriteLine(c);
}
</code></pre>

yes it does work even if the only overload of Enumerable.Range accepts int parameters ;-)

blocks|key|1468002|text|for+(char+letter+=+'A';+letter+<=+'Z';+letter%2B%2B)
{
+++++Debug.WriteLine(letter);
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1468003|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>for (char letter = 'A'; letter &lt;= 'Z'; letter++)
{
 Debug.WriteLine(letter);
}
</code></pre>

blocks|key|1468047|text|char[]+alphabet+=+Enumerable.Range('A',+26).Select(x+=>+(char)x).ToArray();|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1468048|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>char[] alphabet = Enumerable.Range('A', 26).Select(x =&gt; (char)x).ToArray();
</code></pre>

blocks|key|1683187|text|我写这个是为了得到MS+excel列代码(A，B，C，...，Z，AA，AB，...，ZZ，AAA，AAB，...)基于基于1的索引。(当然，切换到从零开始只是在一开始就忽略了column--;。)|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1683188|public+static+String+getColumnNameFromIndex(int+column)
{
++++column--;
++++String+col+=+Convert.ToString((char)('A'+%2B+(column+%25+26)));
++++while+(column+>=+26)
++++{
++++++++column+=+(column+/+26)+-1;
++++++++col+=+Convert.ToString((char)('A'+%2B+(column+%25+26)))+%2B+col;
++++}
++++return+col;
}|code-block|syntax|javascript|1683189|entityMap^0|2G|9|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

I wrote this to get the MS excel column code (A,B,C, ..., Z, AA, AB, ..., ZZ, AAA, AAB, ...) based on a 1-based index. (Of course, switching to zero-based is simply leaving off the <code>column--;</code> at the start.)

<pre><code>public static String getColumnNameFromIndex(int column)
{
 column--;
 String col = Convert.ToString((char)('A' + (column % 26)));
 while (column &gt;= 26)
 {
 column = (column / 26) -1;
 col = Convert.ToString((char)('A' + (column % 26))) + col;
 }
 return col;
}
</code></pre>

blocks|key|1683014|text|假设你指的是英文字母表中的字母...|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1683015|++++for+(+int+i+=+0;+i+<+26;+i%2B%2B+)
++++{
++++++++Console.WriteLine(+Convert.ToChar(+i+%2B+65+)+);
++++}
++++Console.WriteLine(+"Press+any+key+to+continue."+);
++++Console.ReadKey();|code-block|syntax|javascript|1683016|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Assuming you mean the letters of the English alphabet...

<pre><code> for ( int i = 0; i &lt; 26; i++ )
 {
 Console.WriteLine( Convert.ToChar( i + 65 ) );
 }
 Console.WriteLine( "Press any key to continue." );
 Console.ReadKey();
</code></pre>

blocks|key|1683103|text|还要注意，该字符串有一个返回Char的operator[]，并且是一个IEnumerable<char>，因此在大多数情况下，您可以将字符串用作char[]。因此：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1683104|string+alpha+=+"ABCDEFGHIJKLMNOPQRSTUVQXYZ";
for+(int+i+=0;+i+<+26;+%2B%2Bi)
{++
+++++Console.WriteLine(alpha[i]);
}

foreach(char+c+in+alpha)
{++
+++++Console.WriteLine(c);
}|code-block|syntax|javascript|1683105|entityMap^0|Z|H|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Note also, the string has a operator[] which returns a Char, and is an <code>IEnumerable&lt;char&gt;</code>, so for most purposes, you can use a string as a char[]. Hence:

<pre><code>string alpha = "ABCDEFGHIJKLMNOPQRSTUVQXYZ";
for (int i =0; i &lt; 26; ++i)
{ 
 Console.WriteLine(alpha[i]);
}

foreach(char c in alpha)
{ 
 Console.WriteLine(c);
}
</code></pre>

blocks|key|1683340|text|令人惊讶的是，没有人提出一个收益率解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1683341|public+static+IEnumerable<char>+Alphabet()
{
++++for+(char+letter+=+'A';+letter+<=+'Z';+letter%2B%2B)
++++{
++++++++yield+return+letter;
++++}
}|code-block|syntax|javascript|1683342|示例：|1683343|foreach+(var+c+in+Alphabet())
{
++++Console.Write(c);
}|1683344|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Surprised no one has suggested a yield solution:

<pre><code>public static IEnumerable&lt;char&gt; Alphabet()
{
 for (char letter = 'A'; letter &lt;= 'Z'; letter++)
 {
 yield return letter;
 }
}
</code></pre>

Example:

<pre><code>foreach (var c in Alphabet())
{
 Console.Write(c);
}
</code></pre>

blocks|key|1468065|text|var+alphabets+=+Enumerable.Range('A',+26).Select((num)+=>+((char)num).ToString()).ToList();|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1468066|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>var alphabets = Enumerable.Range('A', 26).Select((num) =&gt; ((char)num).ToString()).ToList();
</code></pre>

blocks|key|1683124|text|char+alphaStart+=+Char.Parse("A");
char+alphaEnd+=+Char.Parse("Z");
for(char+i+=+alphaStart;+i+<=+alphaEnd;+i%2B%2B)+{
++++string+anchorLetter+=+i.ToString();
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1683125|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>char alphaStart = Char.Parse("A");
char alphaEnd = Char.Parse("Z");
for(char i = alphaStart; i &lt;= alphaEnd; i++) {
 string anchorLetter = i.ToString();
}
</code></pre>

blocks|key|1467882|text|//generate+a+list+of+alphabet+using+csharp
//this+recurcive+function+will+return+you
//a+string+with+position+of+passed+int
//say+if+pass+0+will+return+A+,1-B,2-C,.....,26-AA,27-AB,....,701-ZZ,702-AAA,703-AAB,...

static+string+CharacterIncrement(int+colCount)
{
++++int+TempCount+=+0;
++++string+returnCharCount+=+string.Empty;

++++if+(colCount+<=+25)
++++{
++++++++TempCount+=+colCount;
++++++++char+CharCount+=+Convert.ToChar((Convert.ToInt32('A')+%2B+TempCount));
++++++++returnCharCount+%2B=+CharCount;
++++++++return+returnCharCount;
++++}
++++else
++++{
++++++++var+rev+=+0;

++++++++while+(colCount+>=+26)
++++++++{
++++++++++++colCount+=+colCount+-+26;
++++++++++++rev%2B%2B;
++++++++}

++++++++returnCharCount+%2B=+CharacterIncrement(rev-1);
++++++++returnCharCount+%2B=+CharacterIncrement(colCount);
++++++++return+returnCharCount;
++++}
}

//--------this+loop+call+this+function---------//
int+i+=+0;
while+(i+<>
++++{
++++++++string+CharCount+=+string.Empty;
++++++++CharCount+=+CharacterIncrement(i);

++++++++i%2B%2B;
++++}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1467883|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>//generate a list of alphabet using csharp
//this recurcive function will return you
//a string with position of passed int
//say if pass 0 will return A ,1-B,2-C,.....,26-AA,27-AB,....,701-ZZ,702-AAA,703-AAB,...

static string CharacterIncrement(int colCount)
{
 int TempCount = 0;
 string returnCharCount = string.Empty;

 if (colCount &lt;= 25)
 {
 TempCount = colCount;
 char CharCount = Convert.ToChar((Convert.ToInt32('A') + TempCount));
 returnCharCount += CharCount;
 return returnCharCount;
 }
 else
 {
 var rev = 0;

 while (colCount &gt;= 26)
 {
 colCount = colCount - 26;
 rev++;
 }

 returnCharCount += CharacterIncrement(rev-1);
 returnCharCount += CharacterIncrement(colCount);
 return returnCharCount;
 }
}

//--------this loop call this function---------//
int i = 0;
while (i &lt;&gt;
 {
 string CharCount = string.Empty;
 CharCount = CharacterIncrement(i);

 i++;
 }
</code></pre>

blocks|key|1683402|text|不幸的是，没有现成的方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1683403|可以使用；char[]+characters+=+"ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray()；|1683404|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

Unfortunately there is no ready-to-use way.

You can use;
char[] characters = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray();

Is there an easy way to generate an array containing the letters of the alphabet in C#? It's not too hard to do it by hand, but I was wondering if there was a built in way to do this.

Generating an array of letters in the alphabet

有没有一种简单的方法可以在C#中生成一个包含字母表的数组？手工操作并不太难，但我想知道是否有内置的方法来做到这一点。

问生成字母表中的字母数组
EN

回答 12

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