blocks|key|1296618|text|您可以使用简单的AWK方式提取域名，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1296619|echo+http://example.com/index.php+%7C+awk+-F[/:]+'{print+$4}'|code-block|syntax|javascript|1296620|输出：example.com|offset|length|style|CODE|1296621|:-)|1296622|entityMap^0|0|0|3|B|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

You can use simple AWK way to extract the domain name as follows:

<pre><code>echo http://example.com/index.php | awk -F[/:] '{print $4}'
</code></pre>

OUTPUT: <code>example.com</code>

:-)

blocks|key|1296462|text|$+URI="http://user:pw@example.com:80/"
$+echo+$URI+%7C+sed+-e+'s/[%5E/]*\/\/$[%5E@]*@$\?$[%5E:/]*$.*/\2/'
example.com|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1296463|请参阅http://en.wikipedia.org/wiki/URI_scheme|unstyled|offset|length|1296464|entityMap|0|LINK|mutability|MUTABLE|url|http://en.wikipedia.org/wiki/URI_scheme^0|0|3|13|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@$G|S|H|T|1|U]]|A|$]]|$1|I|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]]]

<pre><code>$ URI=&quot;http://user:pw@example.com:80/&quot;
$ echo $URI | sed -e 's/[^/]*\/\/$[^@]*@$\?$[^:/]*$.*/\2/'
example.com
</code></pre>
see <a href="http://en.wikipedia.org/wiki/URI_scheme" rel="noreferrer" title="URI scheme">http://en.wikipedia.org/wiki/URI_scheme</a>

blocks|key|1081619|text|basename+"http://example.com"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1081620|当然，这不适用于这样的URI：http://www.example.com/index.html，但您可以执行以下操作：|unstyled|offset|length|style|CODE|1081621|basename+$(dirname+"http://www.example.com/index.html")|1081622|或者对于更复杂的URI：|1081623|echo+"http://www.example.com/somedir/someotherdir/index.html"+%7C+cut+-d'/'+-f3|1081624|-d表示“分隔符”，-f表示“字段”；在上面的示例中，由正斜杠'/‘分隔的第三个字段是www.example.com。|1081625|entityMap^0|0|F|X|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|V|8|@$G|W|H|X|I|J]]|9|@]|A|$]]|$1|K|3|L|5|6|7|Y|8|@]|9|@]|A|$B|C]]|$1|M|3|N|5|F|7|Z|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$B|C]]|$1|Q|3|R|5|F|7|11|8|@]|9|@]|A|$]]|$1|S|3|-4|5|F|7|12|8|@]|9|@]|A|$]]]|T|$]]

<pre><code>basename "http://example.com"
</code></pre>

Now of course, this won't work with a URI like this: <code>http://www.example.com/index.html</code> but you could do the following:

<pre><code>basename $(dirname "http://www.example.com/index.html")
</code></pre>

Or for more complex URIs:

<pre><code>echo "http://www.example.com/somedir/someotherdir/index.html" | cut -d'/' -f3
</code></pre>

-d means "delimiter" and -f means "field"; in the above example, the third field delimited by the forward slash '/' is www.example.com.

blocks|key|1296712|text|echo+$URL+%7C+cut+-d'/'+-f3+%7C+cut+-d':'+-f1|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1296713|适用于URL：|unstyled|1296714|http://host.example.com
http://host.example.com/hi/there
http://host.example.com:2345/hi/there
http://host.example.com:2345|1296715|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>echo $URL | cut -d'/' -f3 | cut -d':' -f1
</code></pre>

Works for URLs:

<pre><code>http://host.example.com
http://host.example.com/hi/there
http://host.example.com:2345/hi/there
http://host.example.com:2345
</code></pre>

blocks|key|1081830|text|sed+-E+-e+'s_.*://([%5E/@]*@)?([%5E/:]%2B).*_\2_'|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1081831|例如：|unstyled|1081832|$+sed+-E+-e+'s_.*://([%5E/@]*@)?([%5E/:]%2B).*_\2_'+<<<+'http://example.com'
example.com

$+sed+-E+-e+'s_.*://([%5E/@]*@)?([%5E/:]%2B).*_\2_'+<<<+'https://example.com'
example.com

$+sed+-E+-e+'s_.*://([%5E/@]*@)?([%5E/:]%2B).*_\2_'+<<<+'http://example.com:1234/some/path'
example.com

$+sed+-E+-e+'s_.*://([%5E/@]*@)?([%5E/:]%2B).*_\2_'+<<<+'http://user:pass@example.com:1234/some/path'
example.com

$+sed+-E+-e+'s_.*://([%5E/@]*@)?([%5E/:]%2B).*_\2_'+<<<+'http://user:pass@example.com:1234/some/path#fragment'
example.com

$+sed+-E+-e+'s_.*://([%5E/@]*@)?([%5E/:]%2B).*_\2_'+<<<+'http://user:pass@example.com:1234/some/path#fragment?params=true'
example.com|1081833|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>sed -E -e 's_.*://([^/@]*@)?([^/:]+).*_\2_'
</code></pre>

e.g.

<pre><code>$ sed -E -e 's_.*://([^/@]*@)?([^/:]+).*_\2_' &lt;&lt;&lt; 'http://example.com'
example.com

$ sed -E -e 's_.*://([^/@]*@)?([^/:]+).*_\2_' &lt;&lt;&lt; 'https://example.com'
example.com

$ sed -E -e 's_.*://([^/@]*@)?([^/:]+).*_\2_' &lt;&lt;&lt; 'http://example.com:1234/some/path'
example.com

$ sed -E -e 's_.*://([^/@]*@)?([^/:]+).*_\2_' &lt;&lt;&lt; 'http://user:pass@example.com:1234/some/path'
example.com

$ sed -E -e 's_.*://([^/@]*@)?([^/:]+).*_\2_' &lt;&lt;&lt; 'http://user:pass@example.com:1234/some/path#fragment'
example.com

$ sed -E -e 's_.*://([^/@]*@)?([^/:]+).*_\2_' &lt;&lt;&lt; 'http://user:pass@example.com:1234/some/path#fragment?params=true'
example.com
</code></pre>

blocks|key|1081467|text|#!/usr/bin/perl+-w
use+strict;

my+$url+=+$ARGV[0];

if($url+=~+/([%5E:]*:\/\/)?([%5E\/]%2B\.[%5E\/]%2B)/g)+{
++print+$2;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1081468|用法：|unstyled|1081469|./test.pl+'https://example.com'
example.com

./test.pl+'https://www.example.com/'
www.example.com

./test.pl+'example.org/'
example.org

+./test.pl+'example.org'
example.org

./test.pl+'example'++->+no+output|1081470|如果您只需要域，而不是完整的主机%2B域，请使用以下代码：|1081471|#!/usr/bin/perl+-w
use+strict;

my+$url+=+$ARGV[0];
if($url+=~+/([%5E:]*:\/\/)?([%5E\/]*\.)*([%5E\/\.]%2B\.[%5E\/]%2B)/g)+{
++print+$3;
}|1081472|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|P|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|M|3|-4|5|F|7|T|8|@]|9|@]|A|$]]]|N|$]]

<pre><code>#!/usr/bin/perl -w
use strict;

my $url = $ARGV[0];

if($url =~ /([^:]*:\/\/)?([^\/]+\.[^\/]+)/g) {
 print $2;
}
</code></pre>

Usage:

<pre><code>./test.pl 'https://example.com'
example.com

./test.pl 'https://www.example.com/'
www.example.com

./test.pl 'example.org/'
example.org

 ./test.pl 'example.org'
example.org

./test.pl 'example' -&gt; no output
</code></pre>

And if you just want the domain and not the full host + domain use this instead:

<pre><code>#!/usr/bin/perl -w
use strict;

my $url = $ARGV[0];
if($url =~ /([^:]*:\/\/)?([^\/]*\.)*([^\/\.]+\.[^\/]+)/g) {
 print $3;
}
</code></pre>

blocks|key|1296401|text|您可以使用python的urlparse，而不是使用regex：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1296402|+URL=http://www.example.com

+python+-c+"from+urlparse+import+urlparse
+url+=+urlparse('$URL')
+print+url.netloc"|code-block|syntax|javascript|1296403|您可以像这样使用它，也可以将它放在一个小脚本中。然而，这仍然需要一个有效的方案标识符，看看你的评论，你的输入不一定会提供一个。您可以指定默认方案，但urlparse要求netloc以'//'开头：|offset|length|style|CODE|1296404|url+=+urlparse('//www.example.com/index.html'，'http')|1296405|因此，您必须手动预先考虑这些内容，即：|1296406|+python+-c+"from+urlparse+import+urlparse
+if+'$URL'.find('://')+==+-1+then:
+++url+=+urlparse('//$URL','http')
+else:
+++url+=+urlparse('$URL')
+print+url.netloc"|1296407|entityMap^0|0|0|2J|4|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|Z|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

Instead of using regex to do this you can use python's urlparse:

<pre><code> URL=http://www.example.com

 python -c "from urlparse import urlparse
 url = urlparse('$URL')
 print url.netloc"
</code></pre>

You could either use it like this or put it in a small script. However this still expects a valid scheme identifier, looking at your comment your input doesn't necessarily provide one. You can specify a default scheme, but urlparse expects the netloc to start with <code>'//'</code> :

url = urlparse('//www.example.com/index.html','http')

So you will have to prepend those manually, i.e:

<pre><code> python -c "from urlparse import urlparse
 if '$URL'.find('://') == -1 then:
 url = urlparse('//$URL','http')
 else:
 url = urlparse('$URL')
 print url.netloc"
</code></pre>

blocks|key|1296304|text|关于你如何让这些urls...please下一次显示更多信息的信息是如此之少。在url等中是否有参数...同时，只需对示例url进行简单的字符串操作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1296305|例如|1296306|$+s="http://example.com/index.php"
$+echo+${s/%25/*}++#get+rid+of+last+"/"+onwards
http://example.com
$+s=${s/%25\//}++
$+echo+${s/#http:\/\//}+#+get+rid+of+http://
example.com|code-block|syntax|javascript|1296307|其他方式，使用sed(GNU)|1296308|$+echo+$s+%7C+sed+'s/http:\/\///;s%7C\/.*%7C%7C'
example.com|1296309|使用awk|1296310|$+echo+$s%7C+awk+'{gsub("http://%7C/.*","")}1'
example.com|1296311|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|V|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|W|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

there is so little info on how you get those urls...please show more info next time. are there parameters in the url etc etc...
Meanwhile, just simple string manipulation for your sample url

eg

<pre><code>$ s="http://example.com/index.php"
$ echo ${s/%/*} #get rid of last "/" onwards
http://example.com
$ s=${s/%\//} 
$ echo ${s/#http:\/\//} # get rid of http://
example.com
</code></pre>

other ways, 
using sed(GNU)

<pre><code>$ echo $s | sed 's/http:\/\///;s|\/.*||'
example.com
</code></pre>

use awk

<pre><code>$ echo $s| awk '{gsub("http://|/.*","")}1'
example.com
</code></pre>

blocks|key|1296444|text|下面将输出"example.com"：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1296445|URI="http://user@example.com/foo/bar/baz/?lala=foo"+
ruby+-ruri+-e+"p+URI.parse('$URI').host"|code-block|syntax|javascript|1296446|有关如何处理Ruby类的更多信息，您必须咨询the+docs。|offset|length|1296447|entityMap|0|LINK|mutability|MUTABLE|url|http://ruby-doc.org/stdlib/libdoc/uri/rdoc/classes/URI.html#M001443^0|0|0|M|8|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

The following will output "example.com":

<pre><code>URI="http://user@example.com/foo/bar/baz/?lala=foo" 
ruby -ruri -e "p URI.parse('$URI').host"
</code></pre>

For more info on what you can do with Ruby's URI class you'd have to consult <a href="http://ruby-doc.org/stdlib/libdoc/uri/rdoc/classes/URI.html#M001443" rel="nofollow noreferrer">the docs</a>.

blocks|key|1296655|text|这是node.js的方式，不管有没有端口和深度路径，它都能工作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1296656|//get-hostname.js
'use+strict';

const+url+=+require('url');
const+parts+=+url.parse(process.argv[2]);

console.log(parts.hostname);|code-block|syntax|javascript|1296657|可以像这样调用：|1296658|node+get-hostname.js+http://foo.example.com:8080/test/1/2/3.html
//foo.example.com|1296659|文档：https://nodejs.org/api/url.html|offset|length|1296660|entityMap|0|LINK|mutability|MUTABLE|url|https://nodejs.org/api/url.html^0|0|0|0|0|3|V|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|10|8|@]|9|@$M|11|N|12|1|13]]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

Here's the node.js way, it works with or without ports and deep paths:

<pre><code>//get-hostname.js
'use strict';

const url = require('url');
const parts = url.parse(process.argv[2]);

console.log(parts.hostname);
</code></pre>

Can be called like:

<pre><code>node get-hostname.js http://foo.example.com:8080/test/1/2/3.html
//foo.example.com
</code></pre>

Docs: <a href="https://nodejs.org/api/url.html" rel="nofollow">https://nodejs.org/api/url.html</a>

blocks|key|1081806|text|一种适用于更多情况的解决方案是基于sed正则表达式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1081807|echo+http://example.com/index.php+%7C+sed+-e+'s#%5Ehttps://\%7C%5Ehttp://##'+-e+'s#:.*##'+-e+'s#/.*##'|offset|length|style|CODE|1081808|这将适用于URL，如：http://example.com/index.php,+http://example.com:4040/index.php,+https://example.com/index.php|1081809|entityMap^0|0|0|2M|0|B|2M|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@$D|N|E|O|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|P|8|@$D|Q|E|R|F|G]]|9|@]|A|$]]|$1|J|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|K|$]]

One solution that would cover for more cases would be based on sed regexps:

<code>echo http://example.com/index.php | sed -e 's#^https://\|^http://##' -e 's#:.*##' -e 's#/.*##'</code>

That would work for URLs like:
<code>http://example.com/index.php, http://example.com:4040/index.php, https://example.com/index.php</code>

How do I extract the domain name from a url using bash?
like: <a href="http://example.com/" rel="noreferrer">http://example.com/</a> to example.com
must work for any tld, not just .com

How to extract domain name from url?

如何使用bash从url中提取域名？比如： to example.com必须适用于任何tld，而不仅仅是.com。

问如何从url中提取域名？
EN

回答 11

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问如何从url中提取域名？EN

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问如何从url中提取域名？
EN