blocks|key|723530|text|您应该使用urlparse.urljoin：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|723531|>>>+import+urlparse
>>>+urlparse.urljoin(url1,+url2)
'http://127.0.0.1/test1/test4/test6.xml'|code-block|syntax|javascript|723532|使用Python3(其中是urlparse+is+renamed+to+urllib.parse)，您可以使用use+it+as+follow|723533|>>>+import+urllib.parse
>>>+urllib.parse.urljoin(url1,+url2)
'http://127.0.0.1/test1/test4/test6.xml'|723534|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/2/library/urlparse.html#urlparse.urljoin|1|https://docs.python.org/2/library/urlparse.html#index-0|2|https://docs.python.org/3.6/library/urllib.parse.html#urllib.parse.urljoin^0|5|G|0|0|0|D|Z|1|1J|G|2|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|F|7|12|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|13|8|@]|9|@$A|14|B|15|1|16]|$A|17|B|18|1|19]]|C|$]]|$1|K|3|L|5|F|7|1A|8|@]|9|@]|C|$G|H]]|$1|M|3|-4|5|6|7|1B|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]|U|$5|P|Q|R|C|$S|V]]|W|$5|P|Q|R|C|$S|X]]]]

You should use <a href="https://docs.python.org/2/library/urlparse.html#urlparse.urljoin" rel="noreferrer">urlparse.urljoin</a> : 

<pre><code>&gt;&gt;&gt; import urlparse
&gt;&gt;&gt; urlparse.urljoin(url1, url2)
'http://127.0.0.1/test1/test4/test6.xml'
</code></pre>

With Python 3 (where <a href="https://docs.python.org/2/library/urlparse.html#index-0" rel="noreferrer">urlparse is renamed to urllib.parse</a>) you could <a href="https://docs.python.org/3.6/library/urllib.parse.html#urllib.parse.urljoin" rel="noreferrer">use it as follow</a>:

<pre><code>&gt;&gt;&gt; import urllib.parse
&gt;&gt;&gt; urllib.parse.urljoin(url1, url2)
'http://127.0.0.1/test1/test4/test6.xml'
</code></pre>

blocks|key|723550|text|>>>+from+urlparse+import+urljoin
>>>+url1+=+"http://www.youtube.com/user/khanacademy"
>>>+url2+=+"/user/khanacademy"
>>>+urljoin(url1,+url2)
'http://www.youtube.com/user/khanacademy'|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|723551|很简单。|unstyled|723552|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>&gt;&gt;&gt; from urlparse import urljoin
&gt;&gt;&gt; url1 = "http://www.youtube.com/user/khanacademy"
&gt;&gt;&gt; url2 = "/user/khanacademy"
&gt;&gt;&gt; urljoin(url1, url2)
'http://www.youtube.com/user/khanacademy'
</code></pre>

Simple.

blocks|key|507414|text|es+=+['http://127.0.0.1',+'test1',+'test4',+'test6.xml']
base+=+''
map(lambda+e:+urlparse.urljoin(base,+e),+es)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|507415|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>es = ['http://127.0.0.1', 'test1', 'test4', 'test6.xml']
base = ''
map(lambda e: urlparse.urljoin(base, e), es)
</code></pre>

blocks|key|507435|text|如果相对路径由多个部分组成，则必须分别连接它们，因为urljoin将替换相对路径，而不是连接它。最简单的方法是使用posixpath。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|507436|>>>+import+urllib.parse
>>>+import+posixpath
>>>+url1+=+"http://127.0.0.1"
>>>+url2+=+"test1"
>>>+url3+=+"test2"
>>>+url4+=+"test3"
>>>+url5+=+"test5.xml"
>>>+url_path+=+posixpath.join(url2,+url3,+url4,+url5)
>>>+urllib.parse.urljoin(url1,+url_path)
'http://127.0.0.1/test1/test2/test3/test5.xml'|code-block|syntax|javascript|507437|另请参阅：How+to+join+components+of+a+path+when+you+are+constructing+a+URL+in+Python|507438|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/1793261/how-to-join-components-of-a-path-when-you-are-constructing-a-url-in-python^0|Q|7|1L|9|0|0|5|22|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@]|D|@$9|11|A|12|1|13]]|E|$]]|$1|M|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

If your relative path consists of multiple parts, you have to join them separately, since <code>urljoin</code> would replace the relative path, not join it. The easiest way to do that is to use <code>posixpath</code>.

<pre><code>&gt;&gt;&gt; import urllib.parse
&gt;&gt;&gt; import posixpath
&gt;&gt;&gt; url1 = "http://127.0.0.1"
&gt;&gt;&gt; url2 = "test1"
&gt;&gt;&gt; url3 = "test2"
&gt;&gt;&gt; url4 = "test3"
&gt;&gt;&gt; url5 = "test5.xml"
&gt;&gt;&gt; url_path = posixpath.join(url2, url3, url4, url5)
&gt;&gt;&gt; urllib.parse.urljoin(url1, url_path)
'http://127.0.0.1/test1/test2/test3/test5.xml'
</code></pre>

See also: <a href="https://stackoverflow.com/questions/1793261/how-to-join-components-of-a-path-when-you-are-constructing-a-url-in-python">How to join components of a path when you are constructing a URL in Python</a>

blocks|key|507470|text|对于python+3.0%2B，连接urls的正确方法是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|507471|from+urllib.parse+import+urljoin
urljoin('https://10.66.0.200/',+'/api/org')
#+output+:+'https://10.66.0.200/api/org'|code-block|syntax|javascript|507472|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

For python 3.0+ the correct way to join urls is:

<pre><code>from urllib.parse import urljoin
urljoin('https://10.66.0.200/', '/api/org')
# output : 'https://10.66.0.200/api/org'
</code></pre>

I have two urls:

<pre><code>url1 = "http://127.0.0.1/test1/test2/test3/test5.xml"
url2 = "../../test4/test6.xml"
</code></pre>

How can I get an absolute url for url2?

How to join absolute and relative urls?

我有两个urls：url1 = "http://127.0.0.1/test1/test2/test3/test5.xml"url2 = "../../test4/test6.xml"如何获取url2的绝对url？

问如何连接绝对urls和相对urls？
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