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Return受UPDATE语句影响的行数
EN

Stack Overflow用户
提问于 2009-07-09 11:18:39
回答 3查看 255.6K关注 0票数 106

如何获取存储过程(SQL Server2005)中受UPDATE查询影响的行数作为结果集。例如:

代码语言:javascript
复制
CREATE PROCEDURE UpdateTables
AS
BEGIN
    -- SET NOCOUNT ON added to prevent extra result sets from
    -- interfering with SELECT statements.
    SET NOCOUNT ON;

    UPDATE Table1 Set Column = 0 WHERE Column IS NULL
    UPDATE Table2 Set Column = 0 WHERE Column IS NULL
    UPDATE Table3 Set Column = 0 WHERE Column IS NULL
    UPDATE Table4 Set Column = 0 WHERE Column IS NULL
END

然后返回:

代码语言:javascript
复制
Table1    Table2    Table3    Table4
32        45        0         3
EN

回答 3

Stack Overflow用户

回答已采纳

发布于 2009-07-09 11:22:01

代码语言:javascript
复制
CREATE PROCEDURE UpdateTables
AS
BEGIN
    -- SET NOCOUNT ON added to prevent extra result sets from
    -- interfering with SELECT statements.
    SET NOCOUNT ON;
    DECLARE @RowCount1 INTEGER
    DECLARE @RowCount2 INTEGER
    DECLARE @RowCount3 INTEGER
    DECLARE @RowCount4 INTEGER

    UPDATE Table1 Set Column = 0 WHERE Column IS NULL
    SELECT @RowCount1 = @@ROWCOUNT
    UPDATE Table2 Set Column = 0 WHERE Column IS NULL
    SELECT @RowCount2 = @@ROWCOUNT
    UPDATE Table3 Set Column = 0 WHERE Column IS NULL
    SELECT @RowCount3 = @@ROWCOUNT
    UPDATE Table4 Set Column = 0 WHERE Column IS NULL
    SELECT @RowCount4 = @@ROWCOUNT

    SELECT @RowCount1 AS Table1, @RowCount2 AS Table2, @RowCount3 AS Table3, @RowCount4 AS Table4
END
票数 155
EN

Stack Overflow用户

发布于 2009-07-09 12:13:13

这正是SQL Server2005以后版本中的OUTPUT子句的出色之处。

示例

代码语言:javascript
复制
CREATE TABLE [dbo].[test_table](
    [LockId] [int] IDENTITY(1,1) NOT NULL,
    [StartTime] [datetime] NULL,
    [EndTime] [datetime] NULL,
PRIMARY KEY CLUSTERED 
(
    [LockId] ASC
) ON [PRIMARY]
) ON [PRIMARY]

INSERT INTO test_table(StartTime, EndTime)
VALUES('2009 JUL 07','2009 JUL 07')
INSERT INTO test_table(StartTime, EndTime)
VALUES('2009 JUL 08','2009 JUL 08')
INSERT INTO test_table(StartTime, EndTime)
VALUES('2009 JUL 09','2009 JUL 09')
INSERT INTO test_table(StartTime, EndTime)
VALUES('2009 JUL 10','2009 JUL 10')
INSERT INTO test_table(StartTime, EndTime)
VALUES('2009 JUL 11','2009 JUL 11')
INSERT INTO test_table(StartTime, EndTime)
VALUES('2009 JUL 12','2009 JUL 12')
INSERT INTO test_table(StartTime, EndTime)
VALUES('2009 JUL 13','2009 JUL 13')

UPDATE test_table
    SET StartTime = '2011 JUL 01'
    OUTPUT INSERTED.* -- INSERTED reflect the value after the UPDATE, INSERT, or MERGE statement is completed 
WHERE
    StartTime > '2009 JUL 09'

结果将返回以下内容

代码语言:javascript
复制
    LockId StartTime                EndTime
-------------------------------------------------------
4      2011-07-01 00:00:00.000  2009-07-10 00:00:00.000
5      2011-07-01 00:00:00.000  2009-07-11 00:00:00.000
6      2011-07-01 00:00:00.000  2009-07-12 00:00:00.000
7      2011-07-01 00:00:00.000  2009-07-13 00:00:00.000

在您的特定情况下,由于不能将聚合函数与OUTPUT一起使用,因此需要在表变量或临时表中捕获INSERTED.*的输出,并对记录进行计数。例如,

代码语言:javascript
复制
DECLARE @temp TABLE (
  [LockId] [int],
  [StartTime] [datetime] NULL,
  [EndTime] [datetime] NULL 
)

UPDATE test_table
    SET StartTime = '2011 JUL 01'
    OUTPUT INSERTED.* INTO @temp
WHERE
    StartTime > '2009 JUL 09'


-- now get the count of affected records
SELECT COUNT(*) FROM @temp
票数 28
EN

Stack Overflow用户

发布于 2009-07-09 11:23:23

您可能需要在执行过程中收集统计数据,但@@ROWCOUNT捕获了以下内容:

代码语言:javascript
复制
declare @Fish table (
Name varchar(32)
)

insert into @Fish values ('Cod')
insert into @Fish values ('Salmon')
insert into @Fish values ('Butterfish')
update @Fish set Name = 'LurpackFish' where Name = 'Butterfish'
select @@ROWCOUNT  --gives 1

update @Fish set Name = 'Dinner'
select @@ROWCOUNT -- gives 3
票数 19
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/1103260

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