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防止ProGuard混淆类成员名称
EN

Stack Overflow用户
提问于 2013-03-18 19:59:30
回答 9查看 106.9K关注 0票数 84

我有一个带有子类的ClassMultiPoint类。

代码语言:javascript
复制
public class ClassMultiPoints
 {
   public String message;
   public List<ClassPoints> data;

   public class ClassPoints
    {
      public String id;
      public List<ClassPoint> points;
      public class ClassPoint
       {
         public String speed;
         public String bearing;
       }
    }
 }

我将从解析GSON中获取对象oPoints的值

oPoints = gson.fromJson( jsonString, ClassMultiPoints.class);

我尝试使用oPoints.message

当我在没有proguard应用程序运行成功的情况下运行我的应用程序。当我用proguard运行我的应用程序时,我的应用程序崩溃了。

我认为问题是:proguard将我的类的属性'oPoints.message'重命名为短'a'

我尽量保持方法和属性的名称不变,但proguard将其重命名为:

proguard.cfg:

代码语言:javascript
复制
-injars      bin/classes
-injars      libs
-outjars     bin/classes-processed.jar
-dontpreverify
-repackageclasses ''
-allowaccessmodification
-optimizations !code/simplification/arithmetic
-keepattributes *Annotation*
-dontskipnonpubliclibraryclasses
-optimizationpasses 5
-printmapping map.txt
-flattenpackagehierarchy

-keep public class * extends android.app.Activity
-keep public class * extends android.app.Application
-keep public class * extends android.app.MapActivity
-keep public class * extends android.app.Service
-keep public class * extends android.content.BroadcastReceiver
-keep public class * extends android.content.ContentProvider

-libraryjars  libs/commons-io-2.2.jar
-libraryjars  libs/ftp4j-1.7.1.jar
-libraryjars  libs/gson-2.2.2.jar

-keep public class org.apache.commons.io.**
-keep public class it.sauronsoftware.ftp4j.**
-keep public class com.google.gson.**

-keep public class com.mypackagename.ActivityMonitor$*

-keep public class * extends android.view.View {
    public <init>(android.content.Context);
    public <init>(android.content.Context, android.util.AttributeSet);
    public <init>(android.content.Context, android.util.AttributeSet, int);
    public void set*(...);
}

-keepclasseswithmembers class * {
    public <init>(android.content.Context, android.util.AttributeSet);
}

-keepclasseswithmembers class * {
    public <init>(android.content.Context, android.util.AttributeSet, int);
}

-keepclassmembers class * extends android.content.Context {
   public void *(android.view.View);
   public void *(android.view.MenuItem);
}

-keepclassmembers class * implements android.os.Parcelable {
    static android.os.Parcelable$Creator CREATOR;
}

-keepclassmembers class **.R$* {
    public static <fields>;
}

保留my one (静态)类的方法和属性名称的正确方法是什么?

EN

回答 9

Stack Overflow用户

回答已采纳

发布于 2013-03-18 21:21:16

谢谢Waqas!

我为我的案例找到了解决方案:

代码语言:javascript
复制
-optimizationpasses 5
-dump class_files.txt
-printseeds seeds.txt
-printusage unused.txt
-printmapping mapping.txt
-optimizations !code/simplification/arithmetic,!field/*,!class/merging*/
-allowaccessmodification
-repackageclasses ''

-keep public class * extends android.app.Activity
-keep public class * extends android.app.Application
-keep public class * extends android.app.MapActivity
-keep public class * extends android.app.Service
-keep public class * extends android.content.BroadcastReceiver
-keep public class * extends android.content.ContentProvider

-libraryjars  libs/commons-io-2.2.jar
-libraryjars  libs/gson-2.2.2.jar
-keep public class org.apache.commons.io.**
-keep public class com.google.gson.**
-keep public class com.google.gson.** {public private protected *;}

##---------------Begin: proguard configuration for Gson ----------
-keepattributes *Annotation*,Signature
-keep class com.mypackage.ActivityMonitor.ClassMultiPoints.** { *; }
-keep public class com.mypackage.ActivityMonitor$ClassMultiPoints     { public protected *; }
-keep public class com.mypackage.ActivityMonitor$ClassMultiPoints$ClassPoints { public protected *; }
-keep public class com.mypackage.ActivityMonitor$ClassMultiPoints$ClassPoints$ClassPoint { public protected *; }
# To support Enum type of class members
-keepclassmembers enum * { *; } 
##---------------End: proguard configuration for Gson ----------

此外,我没有在我的类中使用@SerializedName("message"),上面的配置在没有序列化的情况下工作得很好。

票数 30
EN

Stack Overflow用户

发布于 2013-03-18 20:03:36

如果你不想让你的类成员被混淆,那么使用Gson提供的SerializedName注解。例如:

代码语言:javascript
复制
public class ClassMultiPoints
{
   @SerializedName("message")
   public String message;
   @SerializedName("data")
   public List<ClassPoints> data;

   ...

}

此外,请确保您也为Gson库添加了正确的proguard配置。例如:

代码语言:javascript
复制
##---------------Begin: proguard configuration for Gson ----------
# Gson uses generic type information stored in a class file when working with
#fields. Proguard removes such information by default, so configure it to keep
#all of it.
-keepattributes Signature

# For using GSON @Expose annotation
-keepattributes *Annotation*

# Gson specific classes
-keep class sun.misc.Unsafe { *; }
#-keep class com.google.gson.stream.** { *; }

# Application classes that will be serialized/deserialized over Gson
-keep class com.google.gson.examples.android.model.** { *; }

##---------------End: proguard configuration for Gson ----------

有关更多信息,请阅读this

票数 71
EN

Stack Overflow用户

发布于 2014-02-21 00:47:32

我还发现在使用Dexguard的-keepclassmembers选项时需要优化。如果没有这一点,我的几个模型对象无法反序列化

代码语言:javascript
复制
##---------------Begin: proguard configuration for Gson  ----------
# Gson uses generic type information stored in a class file when working with fields. Proguard
# removes such information by default, so configure it to keep all of it.
-keepattributes Signature

# For using GSON @Expose annotation
-keepattributes *Annotation*

# Application classes that will be serialized/deserialized over Gson, keepclassmembers
-keep class com.myapp.model.** { *; }
-keepclassmembers class com.myapp.model.** { *; }
票数 27
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/15476315

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