使用自动映射器将一个源类映射到多个派生类
使用自动映射器将一个源类映射到多个派生类
提问于 2013-02-05 18:16:39
假设我有一个源类：
public class Source
{
//Several properties that can be mapped to DerivedBase and its subclasses
}和一些目标类：
public class DestinationBase
{
//Several properties
}
public class DestinationDerived1 : DestinationBase
{
//Several properties
}
public class DestinationDerived2 : DestinationBase
{
//Several properties
}然后我希望派生的目标类继承基类的自动映射器配置，因为我不想重复它，有什么方法可以实现吗？
Mapper.CreateMap<Source, DestinationBase>()
.ForMember(...)
// Many more specific configurations that should not have to be repeated for the derived classes
.ForMember(...);
Mapper.CreateMap<Source, DestinationDerived1 >()
.ForMember(...);
Mapper.CreateMap<Source, DestinationDerived2 >()
.ForMember(...);当我这样写它时，它根本不使用基映射，而include似乎对我没有帮助。
编辑:这是我得到的：
public class Source
{
public string Test { get; set; }
public string Test2 { get; set; }
}
public class DestinationBase
{
public string Test3 { get; set; }
}
public class DestinationDerived1 : DestinationBase
{
public string Test4 { get; set; }
}
public class DestinationDerived2 : DestinationBase
{
public string Test5 { get; set; }
}Mapper.CreateMap<Source, DestinationBase>()
.ForMember(d => d.Test3, e => e.MapFrom(s => s.Test))
.Include<Source, DestinationDerived1>()
.Include<Source, DestinationDerived2>();
Mapper.CreateMap<Source, DestinationDerived1>()
.ForMember(d => d.Test4, e => e.MapFrom(s => s.Test2));
Mapper.CreateMap<Source, DestinationDerived2>()
.ForMember(d => d.Test5, e => e.MapFrom(s => s.Test2));AutoMapper.AutoMapperConfigurationException :找到了未映射的成员。查看下面的类型和成员。
添加自定义映射表达式、忽略、添加自定义解析器或修改源/目标类型
源-> DestinationDerived1 (目标成员列表)
Test3
回答 3
Stack Overflow用户
回答已采纳
发布于 2013-02-05 18:23:29
将派生映射包含到基本映射中：
Mapper.CreateMap<Source, DestinationBase>()
.ForMember(d => d.Id, op => op.MapFrom(s => s.Id)) // you can remove this
.Include<Source, DestinationDerived1>()
.Include<Source, DestinationDerived2>();
Mapper.CreateMap<Source, DestinationDerived1>()
.ForMember(d => d.Name, op => op.MapFrom(s => s.Text))
.ForMember(d => d.Value2, op => op.MapFrom(s => s.Amount));
Mapper.CreateMap<Source, DestinationDerived2>()
.ForMember(d => d.Value, op => op.MapFrom(s => s.Amount));用法：
Mapper.AssertConfigurationIsValid();
var s = new Source() { Id = 2, Amount = 10M, Text = "foo" };
var d1 = Mapper.Map<DestinationDerived1>(s);
var d2 = Mapper.Map<DestinationDerived2>(s);请参阅AutoMapper维基上的Mapping inheritance。
更新:下面是类的完整代码，可以正常工作。
public class Source
{
public int Id { get; set; }
public string Text { get; set; }
public decimal Amount { get; set; }
}
public class DestinationBase
{
public int Id { get; set; }
}
public class DestinationDerived1 : DestinationBase
{
public string Name { get; set; }
public decimal Value2 { get; set; }
}
public class DestinationDerived2 : DestinationBase
{
public decimal Value { get; set; }
}更新( AutoMapper错误的解决方法)：
public static class Extensions
{
public static IMappingExpression<Source, TDestination> MapBase<TDestination>(
this IMappingExpression<Source, TDestination> mapping)
where TDestination: DestinationBase
{
// all base class mappings goes here
return mapping.ForMember(d => d.Test3, e => e.MapFrom(s => s.Test));
}
}和所有映射：
Mapper.CreateMap<Source, DestinationBase>()
.Include<Source, DestinationDerived1>()
.Include<Source, DestinationDerived2>()
.MapBase();
Mapper.CreateMap<Source, DestinationDerived1>()
.MapBase()
.ForMember(d => d.Test4, e => e.MapFrom(s => s.Test2));
Mapper.CreateMap<Source, DestinationDerived2>()
.MapBase()
.ForMember(d => d.Test5, e => e.MapFrom(s => s.Test2));Stack Overflow用户
发布于 2019-04-18 22:05:16
用于自动映射程序8.0的。
当前版本有新的方法IncludeAllDerived
以下是工作示例：
var config = new MapperConfiguration(cfg =>
{
cfg.CreateMap<Source, DestinationBase>()
.ForMember(dest => dest.Test3, opt => opt.MapFrom(src => src.Test))
.IncludeAllDerived();
cfg.CreateMap<Source, DestinationDerived1>()
.ForMember(dest => dest.Test4, opt => opt.MapFrom(src => src.Test2));
cfg.CreateMap<Source, DestinationDerived2>()
.ForMember(dest => dest.Test5, opt => opt.MapFrom(src => src.Test2));
});
var mapper = config.CreateMapper();
var source = new Source { Test = "SourceTestProperty", Test2 = "SourceTest2Property" };
var d1 = mapper.Map<DestinationDerived1>(source);
var d2 = mapper.Map<DestinationDerived2>(source);
Assert.Equal("SourceTestProperty", d1.Test3);
Assert.Equal("SourceTest2Property", d1.Test4);
Assert.Equal("SourceTestProperty", d2.Test3);
Assert.Equal("SourceTest2Property", d2.Test5);Stack Overflow用户
发布于 2019-09-06 18:57:04
注意！适用于那些在派生接口方面有问题的人。AutoMapper不支持向派生接口注册。只处理类。
要使其正常工作，您必须将CreateMap的类型引用更改为类而不是接口。
示例：
interface Interface1 {}
class Class1: Interface1 {}
interface Interface2: Interface1 {}
class Class2: Class1, Interface2 {}
CreateMap<OtherClass, Interface1>().IncludeAllDerived();
CreateMap<OtherClass, Interface2>();任何针对Interface2的映射都将只使用第一个CreateMap。您必须将第二个标识为
CreateMap<OtherClass, Class2>();页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/14705064
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