我知道您可以使用NSEnumerator
枚举NSMutableDictionary
的键或值。有没有可能同时做这两件事?我正在寻找类似于PHP foreach
枚举器的东西,比如:
foreach ($dictionary as $key => $value);
发布于 2010-09-23 13:16:31
也许可以看看NSDictionary的方法:
enumerateKeysAndObjectsUsingBlock:(void (^)(id key, id obj, BOOL *stop))
如果您不熟悉C/Objective-C中的块,这是一个很好的教程:http://thirdcog.eu/pwcblocks/
发布于 2010-09-23 13:23:26
NSDictionary* d = [NSDictionary dictionaryWithObjectsAndKeys:@"obj1",@"key1",
@"obj2",@"key2",
@"obj3",@"key3",
@"obj4",@"key4",nil];
for (id key in [d allKeys]) {
NSLog(@"%@ - %@",key,[d objectForKey:key]);
}
输出:
keytest[7880:a0f] key3 - obj3
keytest[7880:a0f] key1 - obj1
keytest[7880:a0f] key4 - obj4
keytest[7880:a0f] key2 - obj2
发布于 2015-01-19 22:37:10
现在简单多了:
for (NSString * key in dict)
{
id/* or your type */ value = dict[key];
...
}
https://stackoverflow.com/questions/3775507
复制相似问题