编辑:苹果确认这是一个编译器错误。
下面的第一个if
表达式(17个术语)编译并产生预期的结果(false
)。第二个if
表达式(18个术语)失败,并显示错误消息:
不能使用类型为'($T106,$T110)‘的参数列表调用'||’。
除了额外的项之外,这两个表达式是相同的。
我可以解决这个问题,但我就是不明白它在抱怨什么。有人能告诉我我犯了什么愚蠢的错误吗?温文尔雅,非常缺乏经验的程序员在这里。
import Darwin
var a = -1
if
a == 0 ||
a == 1 ||
a == 2 ||
a == 3 ||
a == 4 ||
a == 5 ||
a == 6 ||
a == 7 ||
a == 8 ||
a == 9 ||
a == 10 ||
a == 11 ||
a == 12 ||
a == 13 ||
a == 14 ||
a == 15 ||
a == 16 ||
a == 17 { println("value was true") } else { println("value was false")}
if
a == 0 ||
a == 1 ||
a == 2 ||
a == 3 ||
a == 4 ||
a == 5 ||
a == 6 ||
a == 7 ||
a == 8 ||
a == 9 ||
a == 10 ||
a == 11 ||
a == 12 ||
a == 13 ||
a == 14 ||
a == 15 ||
a == 16 ||
a == 17 ||
a == 18 { println("value was true") } else { println("value was false")}
发布于 2014-09-19 13:00:00
当bug被解决时,你可以使用以下命令:
switch a {
case 0...17:
println("value was true")
default:
println("value was false")
}
https://stackoverflow.com/questions/25412198
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