如何在Android中实现Telenor easypay API
如何在Android中实现Telenor easypay API
提问于 2017-03-24 22:28:03
我正在实现telenor easypay API，它由两个next服务组成，第一个我发布我的商店id和其他信息，这些信息给我成功的响应与Auth_token和postbackurl.When我发布身份验证令牌和回发url到下一个next服务URL https://easypaystg.easypaisa.com.pk/easypay/Confirm.jsf它重定向到easypaisa结帐屏幕，在easypay结帐屏幕上显示以下错误。
我的代码：
private class PostTask extends AsyncTask < String, String, String > {
@Override
protected void onPreExecute() {
super.onPreExecute();
mBT.setEnabled(false);
}
@Override
protected String doInBackground(String...data) {
OkHttpClient client; // = new OkHttpClient();
client = getUnsafeOkHttpClient();
client.setHostnameVerifier(new HostnameVerifier() {
@Override
public boolean verify(String hostname, SSLSession session) {
return true;
}
});
MediaType mediaType = MediaType.parse("application/x-www-form-urlencoded");
RequestBody body = RequestBody.create(mediaType, "amount=10&orderRefNum=110&storeId=xxxx&postBackURL=https://www.jeevaysehat.com/");
Request request = new Request.Builder()
.url("https://easypaystg.easypaisa.com.pk/easypay/Index.jsf")
.post(body)
.addHeader("content-type", "application/x-www-form-urlencoded")
.addHeader("cache-control", "no-cache")
.build();
Response response = null;
String resp = null;
try {
response = client.newCall(request).execute();
resp = response.body().string();
} catch (IOException e) {
e.printStackTrace();
}
//return resp;
return response.request().url().toString();
}
@Override
protected void onPostExecute(String s) {
super.onPostExecute(s);
Log.e("data", s);
try {
mBT.setEnabled(true);
String[] ist = s.split("=");
String[] snd = ist[1].split("&");
Token = snd[0];
Log.e("token", Token);
Log.e("posturl", ist[2]);
pburl = ist[2];
medPost.setText(pburl);
medtoken.setText(Token);
// Log.e("pburl", pburl);
/* Intent ii = new Intent(MainActivity.this, Payment_details.class);
ii.putExtra("data", token);
startActivity(ii);*/
//http://jeevaysehat.com/?auth_token=260915100358342650147434472217522869797&postBackURL=http%3A%2F%2Fjeevaysehat.com%2F
} catch (Exception e) {
}
}
}
private class PostTask1 extends AsyncTask < String, String, String > {
String mtoken;
String PBURL;
public PostTask1(String token, String pb) {
mtoken = token;
PBURL = pb;
}
@Override
protected String doInBackground(String...data) {
OkHttpClient client; // = new OkHttpClient();
client = getUnsafeOkHttpClient();
client.setHostnameVerifier(new HostnameVerifier() {
@Override
public boolean verify(String hostname, SSLSession session) {
return true;
}
});
MediaType mediaType = MediaType.parse("application/x-www-form-urlencoded");
RequestBody body = RequestBody.create(mediaType, "auth_token=" + mtoken + "&postBackURL=https://www.jeevaysehat.com/");
Request request = new Request.Builder()
.url("https://easypaystg.easypaisa.com.pk/easypay/Confirm.jsf")
.post(body)
.addHeader("content-type", "application/x-www-form-urlencoded")
.addHeader("cache-control", "no-cache")
.build();
Response response = null;
String resp = null;
try {
response = client.newCall(request).execute();
resp = response.body().string();
} catch (Exception e) {
e.printStackTrace();
}
return response.request().url().toString();
}
@Override
protected void onPostExecute(String s) {
super.onPostExecute(s);
Log.e("data", s);
//here i redirect to webview activity
Intent ii = new Intent(MainActivity.this, Payment_details.class);
ii.putExtra("data", s);
startActivity(ii);
// Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(s));
// startActivity(browserIntent);
}
}回答 1
Stack Overflow用户
回答已采纳
发布于 2017-03-27 22:02:01
我已经解决了这个问题并实现了Telenor easypay API，神奇的是我们将在webview中做所有的事情……使用webview将数据张贴到第一个网址，它将返回auth_token和postbackurl附加到网址...然后在webview中的第二个网址上发布auth_token和postbackurl，它会成功地将你带到easypay结账屏幕。
public class Payment_details extends AppCompatActivity {
private WebView webView;
String postData = null;
private RelativeLayout mConfirm;
String data;
boolean isFirst = true;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.payment_details);
mConfirm = (RelativeLayout) findViewById(R.id.pd_confirm);
webView = (WebView) findViewById(R.id.pdwebView);
data = "https://easypaystg.easypaisa.com.pk/easypay/Index.jsf";
Log.e("data", data);
try {
postData = URLEncoder.encode("amount", "UTF-8")
+ "=" + URLEncoder.encode("10", "UTF-8");
postData += "&" + URLEncoder.encode("storeId", "UTF-8") + "="
+ URLEncoder.encode("xxxx", "UTF-8");
postData += "&" + URLEncoder.encode("postBackURL", "UTF-8")
+ "=" + URLEncoder.encode("your post back url any url", "UTF-8");
postData += "&" + URLEncoder.encode("orderRefNum", "UTF-8")
+ "=" + URLEncoder.encode("1111", "UTF-8");
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
webView.setWebViewClient(new MyWebViewClient());
WebSettings settings = webView.getSettings();
settings.setJavaScriptEnabled(true);
webView.postUrl(data, postData.getBytes());
}
private class MyWebViewClient extends WebViewClient {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
@Override
public void onPageFinished(WebView view, String url) {
super.onPageFinished(view, url);
Log.e("purl", url);
if(isFirst) {
isFirst = false;
String[] ist = url.split("=");
String[] snd = ist[1].split("&");
String Token = snd[0];
Log.e("token", Token);
Log.e("posturl", ist[2]);
secondredirect(Token, view);
}
}
@Override
public void onPageStarted(WebView view, String url, Bitmap favicon) {
super.onPageStarted(view, url, favicon);
}
@Override
public void onReceivedSslError(WebView view, SslErrorHandler handler, SslError error) {
handler.proceed();
}
}
@Override
public void onBackPressed() {
}
private void secondredirect(String token, WebView view){
String sData = null;
String sURL = "https://easypaystg.easypaisa.com.pk/easypay/Confirm.jsf";
try {
sData = URLEncoder.encode("auth_token", "UTF-8")
+ "=" + URLEncoder.encode(token, "UTF-8");
sData += "&" + URLEncoder.encode("postBackURL", "UTF-8") + "="
+ URLEncoder.encode("any url as a postback url", "UTF-8");
view.postUrl(sURL, sData.getBytes());
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/43002086
复制相关文章
相似问题
腾讯云开发者
