PHP: JSON Api男高音
PHP: JSON Api男高音
提问于 2017-08-05 18:00:29
如何从https://api.tenor.com/v1/trending?key=LIVDSRZULELA&limit=8 (results->media->nanomp4->url)获取所有url-s
if($json = cURLGetContents("https://api.tenor.com/v1/trending?key=LIVDSRZULELA&limit=8")) {
$obj = json_decode($json);
echo $obj->results->{"media"}->{"nanomp4"}->{"url"};
}
Function cURLGetContents($url) {
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
$data = curl_exec($ch);
curl_close($ch);
return $data;
}回答 2
Stack Overflow用户
发布于 2017-08-05 18:31:13
在循环基础上：
$json = cURLGetContents("https://api.tenor.com/v1/trending?key=LIVDSRZULELA&limit=8");
$urlList = getAllUrls((array) json_decode($json, true));
function getAllUrls($input, $list = []) {
foreach ($input as $key => $data) {
if (is_array($data)) {
$list = getAllUrls($data, $list);
} elseif ($key === 'url') {
$list[] = $data;
}
}
return $list;
}Stack Overflow用户
发布于 2018-05-30 08:21:12
$endereco = "https://api.tenor.com/v1/search?key=MBDPHCT6LA4H&q=sexo&limit=2";
$GrabURL = cURLGetContents($endereco);
$searchResponse = json_decode($GrabURL, true);
foreach ($searchResponse["results"] as $searchResult) {
print_r($searchResult["media"][0]["tinygif"]["url"]);
}
function cURLGetContents($url) {
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
$data = curl_exec($ch);
curl_close($ch);
return $data;
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/45520614
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