blocks|key|3016293|text|split($pattern,$string)在给定模式或正则表达式中拆分字符串(从5.3.0开始就不推荐使用了)|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|BOLD|entityRanges|data|3016294|preg_split($pattern,$string)在给定的正则表达式模式内拆分字符串|3016295|explode($pattern,$string)在给定模式内拆分字符串|3016296|end($arr)获取最后一个数组元素|3016297|所以：|3016298|end(split('-',$str))|3016299|end(preg_split('/-/',$str))|3016300|$strArray+=+explode('-',$str)|3016301|$lastElement+=+end($strArray)|3016302|将返回-分隔字符串的最后一个元素。|3016303|3016304|有一种核心的方法可以做到这一点：|3016305|$str+=+'1-2-3-4-5';
echo+substr($str,+strrpos($str,+'-')+%2B+1);
//++++++%7C++++++++++++'---+get+the+last+position+of+'-'+and+add+1(if+don't+substr+will+get+'-'+too)
//++++++'-----+get+the+last+piece+of+string+after+the+last+occurrence+of+'-'|code-block|syntax|javascript|3016306|entityMap^0|0|N|Y|N|0|0|S|0|0|P|0|0|9|0|0|0|K|0|0|R|0|0|T|0|0|T|0|3|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@$9|19|A|1A|B|C]|$9|1B|A|1C|B|D]]|E|@]|F|$]]|$1|G|3|H|5|6|7|1D|8|@$9|1E|A|1F|B|C]]|E|@]|F|$]]|$1|I|3|J|5|6|7|1G|8|@$9|1H|A|1I|B|C]]|E|@]|F|$]]|$1|K|3|L|5|6|7|1J|8|@$9|1K|A|1L|B|C]]|E|@]|F|$]]|$1|M|3|N|5|6|7|1M|8|@]|E|@]|F|$]]|$1|O|3|P|5|6|7|1N|8|@$9|1O|A|1P|B|C]]|E|@]|F|$]]|$1|Q|3|R|5|6|7|1Q|8|@$9|1R|A|1S|B|C]]|E|@]|F|$]]|$1|S|3|T|5|6|7|1T|8|@$9|1U|A|1V|B|C]]|E|@]|F|$]]|$1|U|3|V|5|6|7|1W|8|@$9|1X|A|1Y|B|C]]|E|@]|F|$]]|$1|W|3|X|5|6|7|1Z|8|@$9|20|A|21|B|C]]|E|@]|F|$]]|$1|Y|3|-4|5|6|7|22|8|@]|E|@]|F|$]]|$1|Z|3|10|5|6|7|23|8|@]|E|@]|F|$]]|$1|11|3|12|5|13|7|24|8|@]|E|@]|F|$14|15]]|$1|16|3|-4|5|6|7|25|8|@]|E|@]|F|$]]]|17|$]]

<code>split($pattern,$string)</code> split strings within a given pattern or regex (it's deprecated since 5.3.0)

<code>preg_split($pattern,$string)</code> split strings within a given regex pattern

<code>explode($pattern,$string)</code> split strings within a given pattern

<code>end($arr)</code> get last array element

So:

<code>end(split('-',$str))</code>

<code>end(preg_split('/-/',$str))</code>

<code>$strArray = explode('-',$str)</code> 
<code>$lastElement = end($strArray)</code>

Will return the last element of a <code>-</code> separated string.

<hr>

And there's a hardcore way to do this:

<pre><code>$str = '1-2-3-4-5';
echo substr($str, strrpos($str, '-') + 1);
// | '--- get the last position of '-' and add 1(if don't substr will get '-' too)
// '----- get the last piece of string after the last occurrence of '-'
</code></pre>

blocks|key|185991|text|$string+=+'abc-123-xyz-789';
$exploded+=+explode('-',+$string);
echo+end($exploded);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|185992|EDIT：：终于解决了E_STRICT问题|unstyled|185993|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>$string = 'abc-123-xyz-789';
$exploded = explode('-', $string);
echo end($exploded);
</code></pre>

EDIT::Finally got around to removing the E_STRICT issue

blocks|key|185981|text|只需检查分隔符是否存在，拆分或不拆分：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|185982|if+(strpos($potentiallyDelimitedString,+'-')+!==+FALSE)+{
++found+delimiter,+so+split
}|code-block|syntax|javascript|185983|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Just check whether or not the delimiting character exists, and either split or don't:

<pre><code>if (strpos($potentiallyDelimitedString, '-') !== FALSE) {
 found delimiter, so split
}
</code></pre>

blocks|key|184599|text|根据this+post|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|184600|end((explode('-',+$string)));|code-block|syntax|javascript|184601|这不会在PHP5+(PHP+magic)中引起E_STRICT警告。虽然the+warning+will+be+issued+in+PHP+7，所以在它前面添加@可以作为一种解决办法。|style|CODE|184602|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/21016338/55075|1|http://phpsadness.com/sad/51|2|http://php.net/manual/en/migration70.incompatible.php#migration70.incompatible.variable-handling.parentheses^0|2|9|0|0|0|28|1|A|9|1|10|Z|2|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|F|7|12|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|13|8|@$A|14|B|15|K|L]]|9|@$A|16|B|17|1|18]|$A|19|B|1A|1|1B]]|C|$]]|$1|M|3|-4|5|6|7|1C|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]|U|$5|P|Q|R|C|$S|V]]|W|$5|P|Q|R|C|$S|X]]]]

As per <a href="https://stackoverflow.com/a/21016338/55075">this post</a>:

<pre><code>end((explode('-', $string)));
</code></pre>

which won't cause E_STRICT warning in PHP 5 (<a href="http://phpsadness.com/sad/51" rel="nofollow noreferrer">PHP magic</a>). Although <a href="http://php.net/manual/en/migration70.incompatible.php#migration70.incompatible.variable-handling.parentheses" rel="nofollow noreferrer">the warning will be issued in PHP 7</a>, so adding <code>@</code> in front of it can be used as a workaround.

blocks|key|186016|text|这段代码可以做到这一点|type|unstyled|depth|inlineStyleRanges|entityRanges|data|186017|<?php
$string+=+'abc-123-xyz-789';
$output+=+explode("-",$string);
echo+$output[count($output)-1];
?>|code-block|syntax|javascript|186018|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This code will do that

<pre><code>&lt;?php
$string = 'abc-123-xyz-789';
$output = explode("-",$string);
echo $output[count($output)-1];
?&gt;
</code></pre>

blocks|key|2804052|text|正如其他人所提到的，如果您不将explode()的结果赋给一个变量，您会得到这样的消息：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2804053|2804054|+E_STRICT:严格的标准:只有变量应该通过引用传递|blockquote|2804055|2804056|2804057|正确的方法是：|2804058|$words+=+explode('-',+'hello-world-123');
$id+=+array_pop($words);+//+123
$slug+=+implode('-',+$words);+//+hello-world|code-block|syntax|javascript|2804059|entityMap^0|F|9|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|X|8|@]|D|@]|E|$]]|$1|G|3|H|5|I|7|Y|8|@]|D|@]|E|$]]|$1|J|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]|$1|K|3|-4|5|6|7|10|8|@]|D|@]|E|$]]|$1|L|3|M|5|6|7|11|8|@]|D|@]|E|$]]|$1|N|3|O|5|P|7|12|8|@]|D|@]|E|$Q|R]]|$1|S|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|T|$]]

As has been mentioned by others, if you don't assign the result of <code>explode()</code> to a variable, you get the message:

<blockquote>
 E_STRICT: Strict standards: Only variables should be passed by reference
</blockquote>

The correct way is:

<pre><code>$words = explode('-', 'hello-world-123');
$id = array_pop($words); // 123
$slug = implode('-', $words); // hello-world
</code></pre>

blocks|key|186708|text|为了满足“需要尽可能快”的要求，我对一些可能的解决方案运行了一个基准测试。每个解决方案都必须满足这组测试用例。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|186709|$cases+=+[
++++'aaa-zzz'+++++++++++++++++++++=>+'zzz',
++++'zzz'+++++++++++++++++++++++++=>+'zzz',
++++'-zzz'++++++++++++++++++++++++=>+'zzz',
++++'aaa-'++++++++++++++++++++++++=>+'',
++++''++++++++++++++++++++++++++++=>+'',
++++'aaa-bbb-ccc-ddd-eee-fff-zzz'+=>+'zzz',
];|code-block|syntax|javascript|186710|以下是解决方案：|186711|function+test_substr($str,+$delimiter+=+'-')+{
++++$idx+=+strrpos($str,+$delimiter);
++++return+$idx+===+false+?+$str+:+substr($str,+$idx+%2B+1);
}

function+test_end_index($str,+$delimiter+=+'-')+{
++++$arr+=+explode($delimiter,+$str);
++++return+$arr[count($arr)+-+1];
}

function+test_end_explode($str,+$delimiter+=+'-')+{
++++$arr+=+explode($delimiter,+$str);
++++return+end($arr);
}

function+test_end_preg_split($str,+$pattern+=+'/-/')+{
++++$arr+=+preg_split($pattern,+$str);
++++return+end($arr);
}|186712|以下是针对测试用例运行每个解决方案1,000,000次后的结果：|186713|test_substr+++++++++++++++:+1.706+sec
test_end_index++++++++++++:+2.131+sec++%2B0.425+sec++%2B25%25
test_end_explode++++++++++:+2.199+sec++%2B0.493+sec++%2B29%25
test_end_preg_split+++++++:+2.775+sec++%2B1.069+sec++%2B63%25|186714|因此，其中最快的是结合使用substr和strpos。注意，在这个解决方案中，我们必须在strpos中检查false，这样才能返回完整的字符串(满足zzz的需要)。|offset|length|style|CODE|186715|entityMap^0|0|0|0|0|0|0|D|6|K|6|18|6|1H|5|22|3|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|10|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|12|8|@$Q|13|R|14|S|T]|$Q|15|R|16|S|T]|$Q|17|R|18|S|T]|$Q|19|R|1A|S|T]|$Q|1B|R|1C|S|T]]|9|@]|A|$]]|$1|U|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]]|V|$]]

To satisfy the requirement that "it needs to be as fast as possible" I ran a benchmark against some possible solutions. Each solution had to satisfy this set of test cases.

<pre><code>$cases = [
 'aaa-zzz' =&gt; 'zzz',
 'zzz' =&gt; 'zzz',
 '-zzz' =&gt; 'zzz',
 'aaa-' =&gt; '',
 '' =&gt; '',
 'aaa-bbb-ccc-ddd-eee-fff-zzz' =&gt; 'zzz',
];
</code></pre>

Here are the solutions:

<pre><code>function test_substr($str, $delimiter = '-') {
 $idx = strrpos($str, $delimiter);
 return $idx === false ? $str : substr($str, $idx + 1);
}

function test_end_index($str, $delimiter = '-') {
 $arr = explode($delimiter, $str);
 return $arr[count($arr) - 1];
}

function test_end_explode($str, $delimiter = '-') {
 $arr = explode($delimiter, $str);
 return end($arr);
}

function test_end_preg_split($str, $pattern = '/-/') {
 $arr = preg_split($pattern, $str);
 return end($arr);
}
</code></pre>

Here are the results after each solution was run against the test cases 1,000,000 times:

<pre><code>test_substr : 1.706 sec
test_end_index : 2.131 sec +0.425 sec +25%
test_end_explode : 2.199 sec +0.493 sec +29%
test_end_preg_split : 2.775 sec +1.069 sec +63%
</code></pre>

So turns out the fastest of these was using <code>substr</code> with <code>strpos</code>. Note that in this solution we must check <code>strpos</code> for <code>false</code> so we can return the full string (catering for the <code>zzz</code> case).

blocks|key|188852|text|由于explode()返回一个数组，如果您碰巧知道最后一个数组项的位置，则可以直接在该函数的末尾添加方括号。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|188853|$email+=+'name@example.com';
$provider+=+explode('@',+$email)[1];
echo+$provider;+//+example.com|code-block|syntax|javascript|188854|或者另一种方式是list()|188855|$email+=+'name@example.com';
list($prefix,+$provider)+=+explode('@',+$email);
echo+$provider;+//+example.com|188856|如果你不知道位置：|188857|$path+=+'one/two/three/four';
$dirs+=+explode('/',+$path);
$last_dir+=+$dirs[count($dirs)+-+1];
echo+$last_dir;+//+four|188858|entityMap^0|2|9|0|0|8|6|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|12|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|T|$]]

Since <code>explode()</code> returns an array, you can add square brackets directly to the end of that function, if you happen to know the position of the last array item.

<pre><code>$email = 'name@example.com';
$provider = explode('@', $email)[1];
echo $provider; // example.com
</code></pre>

Or another way is <code>list()</code>:

<pre><code>$email = 'name@example.com';
list($prefix, $provider) = explode('@', $email);
echo $provider; // example.com
</code></pre>

If you don't know the position:

<pre><code>$path = 'one/two/three/four';
$dirs = explode('/', $path);
$last_dir = $dirs[count($dirs) - 1];
echo $last_dir; // four
</code></pre>

blocks|key|186103|text|只需调用以下单行代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|186104|+$expectedString+=+end(explode('-',+$orignalString));|code-block|syntax|javascript|186105|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Just Call the following single line code:
<pre><code> $expectedString = end(explode('-', $orignalString));
</code></pre>

blocks|key|3016480|text|接受的答案中有一个bug，如果找不到分隔符，它仍然会吃掉输入字符串的第一个字符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3016481|$str+=+'1-2-3-4-5';
echo+substr($str,+strrpos($str,+'-')+%2B+1);|code-block|syntax|javascript|3016482|产生预期的结果：5|offset|length|style|CODE|3016483|$str+=+'1-2-3-4-5';
echo+substr($str,+strrpos($str,+';')+%2B+1);|3016484|生成-2-3-4-5|3016485|$str+=+'1-2-3-4-5';
if+(($pos+=+strrpos($str,+';'))+!==+false)
++++echo+substr($str,+$pos+%2B+1);
else
++++echo+$str;|3016486|根据需要生成整个字符串。|3016487|3v4l+link|3016488|entityMap|0|LINK|mutability|MUTABLE|url|https://3v4l.org/Ihtf2^0|0|0|8|1|0|0|2|8|0|0|0|0|9|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|16|8|@$I|17|J|18|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|1A|8|@$I|1B|J|1C|K|L]]|9|@]|A|$]]|$1|Q|3|R|5|D|7|1D|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1E|8|@]|9|@]|A|$]]|$1|U|3|V|5|6|7|1F|8|@]|9|@$I|1G|J|1H|1|1I]]|A|$]]|$1|W|3|-4|5|6|7|1J|8|@]|9|@]|A|$]]]|X|$Y|$5|Z|10|11|A|$12|13]]]]

The accepted answer has a bug in it where it still eats the first character of the input string if the delimiter is not found.
<pre><code>$str = '1-2-3-4-5';
echo substr($str, strrpos($str, '-') + 1);
</code></pre>
Produces the expected result: <code>5</code>
<pre><code>$str = '1-2-3-4-5';
echo substr($str, strrpos($str, ';') + 1);
</code></pre>
Produces <code>-2-3-4-5</code>
<pre><code>$str = '1-2-3-4-5';
if (($pos = strrpos($str, ';')) !== false)
 echo substr($str, $pos + 1);
else
 echo $str;
</code></pre>
Produces the whole string as desired.
<a href="https://3v4l.org/Ihtf2" rel="nofollow noreferrer">3v4l link</a>

blocks|key|2804129|text|此解决方案是空安全的，并支持所有PHP版本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2804130|//+https://www.php.net/manual/en/function.array-slice.php
$strLastStringToken+=+array_slice(explode('-',$str),-1,1)[0];|code-block|syntax|javascript|2804131|如果为$str+=+null，则返回''。|offset|length|style|CODE|2804132|entityMap^0|0|0|3|B|I|2|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|N|$]]

This solution is null-safe and supports all PHP versions:
<pre><code>// https://www.php.net/manual/en/function.array-slice.php
$strLastStringToken = array_slice(explode('-',$str),-1,1)[0];
</code></pre>
returning <code>''</code> if <code>$str = null</code>.

blocks|key|188783|text|你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|188784|$str+=+"abc-123-xyz-789";
$last+=+array_pop(+explode('-',+$str)+);
echo+$last;+//echoes+789|code-block|syntax|javascript|188785|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can do it like this:

<pre><code>$str = "abc-123-xyz-789";
$last = array_pop( explode('-', $str) );
echo $last; //echoes 789
</code></pre>

blocks|key|3016318|text|您可以结合使用array_pop和explode|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|3016319|代码：|3016320|$string+=+'abc-123-xyz-789';
$output+=+array_pop(explode("-",$string));
echo+$output;|code-block|syntax|javascript|3016321|演示：Click+here|3016322|entityMap|0|LINK|mutability|MUTABLE|url|http://codepad.org/re1VGntA^0|7|9|H|7|0|0|0|0|2|3|A|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|11|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|12|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@$9|16|A|17|1|18]]|E|$]]|$1|O|3|-4|5|6|7|19|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

You can use array_pop combined with explode

Code:

<pre><code>$string = 'abc-123-xyz-789';
$output = array_pop(explode("-",$string));
echo $output;
</code></pre>

DEMO: <a href="http://codepad.org/re1VGntA" rel="nofollow">Click here</a>

blocks|key|2804080|text|你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2804081|$str+=+"abc-123-xyz-789";
$arr+=+explode('-',+$str);
$last+=+array_pop(+$arr+);
echo+$last;+//echoes+789|code-block|syntax|javascript|2804082|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can do it like this:

<pre><code>$str = "abc-123-xyz-789";
$arr = explode('-', $str);
$last = array_pop( $arr );
echo $last; //echoes 789
</code></pre>

I need to split a string in PHP by "-" and get the last part.

So from this:

<blockquote>
 abc-123-xyz-789
</blockquote>

I expect to get 

<blockquote>
 "789"
</blockquote>

This is the code I've come up with:

<pre><code>substr(strrchr($urlId, '-'), 1)
</code></pre>

which works fine, except:

If my input-string does not contain any "-", I must get the whole string, like from:

<blockquote>
 123
</blockquote>

I need to get back

<blockquote>
 123
</blockquote>

and it needs to be as fast as possible.
Any help is appreciated!

Splitting strings in PHP and get last part

我需要在PHP中用"-“拆分一个字符串，然后得到最后一部分。因此，从这里可以看出： abc-123-xyz-789我希望能得到 "789“这是我想出来的代码：substr(strrchr($urlId, '-'), 1)它工作得很好，除了：如果我的input-string不包含任何"-"，我必须获取整个字符串，比如from： 123我要回去了 123而且它需要尽可能快。如有任何帮助，我们不胜感激！

问在PHP中拆分字符串并获取最后一部分
EN

回答 14

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问在PHP中拆分字符串并获取最后一部分EN

回答 14

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问在PHP中拆分字符串并获取最后一部分
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