如何使用正则表达式处理某些字符的拆分
如何使用正则表达式处理某些字符的拆分
提问于 2018-06-01 05:34:05
在我的应用程序中，我尝试根据正则表达式模式将一个字符串拆分成一个数组。我希望能够加载我的volt模板，并通过我们的自定义渲染引擎运行它们-只是为了更多地了解渲染引擎是如何工作的。
为此，我编写了下面的正则表达式：
"(?s)(\\{\\{.*?\\}\\}|\\{%.*?%\\}|\\{#.*?#\\})"这是一个这样的模板的例子：
# {{ title }}
{{created_at}} {{created_location}}
============
Paragraphs are separated by a blank line.
2nd paragraph. *Italic*, **bold**, and `monospace`.
Itemized lists look like:
{% for (item in items) %}
* {{ item }}
{% endfor %}现在，理想情况下，我希望将其转换为如下所示的数组：
[
"# ",
"{{ title }}",
"\n",
"{{created_at}}",
" ",
"{{created_location}}",
"\n============\nParagraphs are separated by a blank line\n2nd paragraph. *Italic*, **bold**, and `monospace`.\n\nItemized lists look like:"
"{% for (item in items) %}",
"\n* {{ item }}\n",
"{% endfor %}"
]但是，当我运行上面的正则表达式时，我得到：
[
"Paragraphs are separated by a blank line.\n2nd paragraph. *Italic*, **bold**, and `monospace`.\n\nItemized lists look like:",
"{% for (item in items) %}\n* {{ item }}",
"{% endfor %}\n"
]如你所见，标题部分完全消失了。此外，换行符似乎存在一些问题。你知道我怎么解决这个问题吗？
回答 1
Stack Overflow用户
发布于 2018-06-04 16:59:39
问题不在正则表达式中，而是在我用来拆分正则表达式的代码中。我修改了下面的代码，也返回了正则表达式本身。
extension NSRegularExpression {
func split(_ str: String) -> [String] {
let range = NSRange(location: 0, length: str.characters.count)
//get locations of matches
var matchingRanges: [NSRange] = []
let matches: [NSTextCheckingResult] = self.matches(in: str, options: [], range: range)
for match: NSTextCheckingResult in matches {
matchingRanges.append(match.range)
}
//invert ranges - get ranges of non-matched pieces
var pieceRanges: [NSRange] = []
//add first range
pieceRanges.append(NSRange(location: 0, length: (matchingRanges.count == 0 ? str.characters.count : matchingRanges[0].location)))
var endLoc: Int = 0
var startLoc: Int = 0
//add between splits ranges and last range
for i in 0..<matchingRanges.count {
let isLast = i + 1 == matchingRanges.count
let location = matchingRanges[i].location
let length = matchingRanges[i].length
startLoc = location + length
endLoc = isLast ? str.characters.count : matchingRanges[i + 1].location
pieceRanges.append(NSRange(location: startLoc, length: endLoc - startLoc))
}
var pieces: [String] = []
var previous: NSRange = NSRange(location: 0, length: 0)
for range: NSRange in pieceRanges {
let item = (str as NSString).substring(with: NSRange(location:previous.location+previous.length, length:range.location-(previous.location+previous.length)))
pieces.append(item)
let piece = (str as NSString).substring(with: range)
pieces.append(piece)
previous = range
}
return pieces
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50633111
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