blocks|key|747397|text|你所拥有的应该是有效的。但是，如果提供的空格默认为...还有别的吗？您可以使用空格regex：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|747398|str+=+"Hello+I'm+your+String";
String[]+splited+=+str.split("\\s%2B");|code-block|syntax|javascript|747399|这将导致任意数量的连续空格将字符串分割为标记。|747400|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

What you have should work. If, however, the spaces provided are defaulting to... something else? You can use the whitespace regex:
<pre><code>str = &quot;Hello I'm your String&quot;;
String[] splited = str.split(&quot;\\s+&quot;);
</code></pre>
This will cause any number of consecutive spaces to split your string into tokens.

blocks|key|530978|text|我相信将正则表达式放在str.split括号中应该可以解决这个问题。Java+String.split()方法基于正则表达式，因此您需要的是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|530979|str+=+"Hello+I'm+your+String";
String[]+splitStr+=+str.split("\\s%2B");|code-block|syntax|javascript|530980|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I do believe that putting a regular expression in the str.split parentheses should solve the issue. The Java String.split() method is based upon regular expressions so what you need is:

<pre><code>str = "Hello I'm your String";
String[] splitStr = str.split("\\s+");
</code></pre>

blocks|key|531018|text|使用Stringutils.split()将字符串按空格拆分。例如，StringUtils.split("Hello+World")返回"Hello“和"World"；|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|531019|为了解决上述情况，我们使用了如下的split方法|531020|String+split[]=+StringUtils.split("Hello+I'm+your+String");|code-block|syntax|javascript|531021|当我们打印拆分数组时，输出将是：|531022|你好|531023|我|531024|你的|531025|字符串|531026|For+complete+example+demo+check+here|531027|entityMap|0|LINK|mutability|MUTABLE|url|http://java-interview-questions.com/how-to-separate-strings-in-java-by-spaces-with-example^0|2|J|Y|W|0|0|0|0|0|0|0|0|0|10|0|0^^$0|@$1|2|3|4|5|6|7|16|8|@$9|17|A|18|B|C]|$9|19|A|1A|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1B|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|1C|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1D|8|@]|D|@]|E|$]]|$1|O|3|P|5|6|7|1E|8|@]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1F|8|@]|D|@]|E|$]]|$1|S|3|T|5|6|7|1G|8|@]|D|@]|E|$]]|$1|U|3|V|5|6|7|1H|8|@]|D|@]|E|$]]|$1|W|3|X|5|6|7|1I|8|@]|D|@$9|1J|A|1K|1|1L]]|E|$]]|$1|Y|3|-4|5|6|7|1M|8|@]|D|@]|E|$]]]|Z|$10|$5|11|12|13|E|$14|15]]]]

Use <code>Stringutils.split()</code> to split the string by whites paces. For example <code>StringUtils.split("Hello World")</code> returns "Hello" and "World";

In order to solve the mentioned case we use split method like this 

<pre><code>String split[]= StringUtils.split("Hello I'm your String");
</code></pre>

when we print the split array the output will be :

Hello

I'm

your

String

<a href="http://java-interview-questions.com/how-to-separate-strings-in-java-by-spaces-with-example">For complete example demo check here</a>

blocks|key|530866|text|试一试|type|unstyled|depth|inlineStyleRanges|entityRanges|data|530867|String[]+splited+=+str.split("\\s");|code-block|syntax|javascript|530868|http://download.oracle.com/javase/tutorial/essential/regex/pre_char_classes.html|offset|length|530869|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|0|28|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|T|8|@]|9|@$I|U|J|V|1|W]]|A|$]]|$1|K|3|-4|5|6|7|X|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|H]]]]

Try 

<pre><code>String[] splited = str.split("\\s");
</code></pre>

<a href="http://download.oracle.com/javase/tutorial/essential/regex/pre_char_classes.html" rel="noreferrer">http://download.oracle.com/javase/tutorial/essential/regex/pre_char_classes.html</a>

blocks|key|531064|text|如果你不想使用字符串拆分方法，那么你可以使用StringTokenizer类作为..|type|unstyled|depth|inlineStyleRanges|entityRanges|data|531065|++++StringTokenizer+tokens+=+new+StringTokenizer("Hello+I'm+your+String",+"+");
++++String[]+splited+=+new+String[tokens.countTokens()];
++++int+index+=+0;
++++while(tokens.hasMoreTokens()){
++++++++splited[index]+=+tokens.nextToken();
++++++++%2B%2Bindex;
++++}|code-block|syntax|javascript|531066|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

if somehow you don't wanna use String split method then you can use StringTokenizer class in Java as..

<pre><code> StringTokenizer tokens = new StringTokenizer("Hello I'm your String", " ");
 String[] splited = new String[tokens.countTokens()];
 int index = 0;
 while(tokens.hasMoreTokens()){
 splited[index] = tokens.nextToken();
 ++index;
 }
</code></pre>

blocks|key|747571|text|试试这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|747572|++++String+str+=+"This+is+String";
++++String[]+splited+=+str.split("\\s%2B");

++++String+split_one=splited[0];
++++String+split_second=splited[1];
++++String+split_three=splited[2];

+++Log.d("Splited+String+",+"Splited+String"+%2B+split_one%2Bsplit_second%2Bsplit_three);|code-block|syntax|javascript|747573|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this one

<pre><code> String str = "This is String";
 String[] splited = str.split("\\s+");

 String split_one=splited[0];
 String split_second=splited[1];
 String split_three=splited[2];

 Log.d("Splited String ", "Splited String" + split_one+split_second+split_three);
</code></pre>

blocks|key|747633|text|好的，所以我们必须做拆分，因为你已经得到了答案，我会推广它。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|747634|如果你想用空格分割任何字符串，请使用分隔符(特殊字符)。|747635|首先，删除前导空格，因为它们会产生大多数问题。|747636|str1+=+"++++Hello+I'm+your+++++++String++++";
str2+=+"++++Are+you+serious+about+this+question_++boy,+aren't+you?+++";|code-block|syntax|javascript|747637|首先删除前导空格，可以是空格、制表符等。|747638|String+s+=+str1.replaceAll("%5E\\s%2B","");//starting+with+whitespace+one+or+more|747639|现在，如果您想要按空格或任何特殊字符拆分。|747640|String[]+sa+=+s.split("[%5E\\w]%2B");//split+by+any+non+word+char|747641|但是由于w包含a-zA-Z_0-9，所以如果您想要用下划线(_)拆分，也可以使用|747642|+String[]+sa+=+s.split("[!,?+._'@]%2B");//for+str2+after+removing+leading+space|747643|entityMap^0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Z|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|10|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|11|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|9|@]|A|$]]|$1|M|3|N|5|H|7|13|8|@]|9|@]|A|$I|J]]|$1|O|3|P|5|6|7|14|8|@]|9|@]|A|$]]|$1|Q|3|R|5|H|7|15|8|@]|9|@]|A|$I|J]]|$1|S|3|T|5|6|7|16|8|@]|9|@]|A|$]]|$1|U|3|V|5|H|7|17|8|@]|9|@]|A|$I|J]]|$1|W|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|X|$]]

OK, so we have to do splitting as you already got the answer I would generalize it.

If you want to split any string by spaces, delimiter(special chars).

First, remove the leading space as they create most of the issues.

<pre><code>str1 = " Hello I'm your String ";
str2 = " Are you serious about this question_ boy, aren't you? ";
</code></pre>

First remove the leading space which can be space, tab etc.

<pre><code>String s = str1.replaceAll("^\\s+","");//starting with whitespace one or more
</code></pre>

Now if you want to split by space or any special char.

<pre><code>String[] sa = s.split("[^\\w]+");//split by any non word char
</code></pre>

But as w contains [a-zA-Z_0-9] ,so if you want to split by underscore(_) also use

<pre><code> String[] sa = s.split("[!,? ._'@]+");//for str2 after removing leading space
</code></pre>

blocks|key|747523|text|另一种方法是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|747524|import+java.util.regex.Pattern;

...

private+static+final+Pattern+SPACE+=+Pattern.compile("+");
String[]+arr+=+SPACE.split(str);+//+str+is+the+string+to+be+split|code-block|syntax|javascript|747525|我看到了here|offset|length|747526|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/apache/spark/blob/master/examples/src/main/java/org/apache/spark/examples/streaming/JavaNetworkWordCount.java^0|0|0|4|4|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

An alternative way would be:

<pre><code>import java.util.regex.Pattern;

...

private static final Pattern SPACE = Pattern.compile(" ");
String[] arr = SPACE.split(str); // str is the string to be split
</code></pre>

Saw it <a href="https://github.com/apache/spark/blob/master/examples/src/main/java/org/apache/spark/examples/streaming/JavaNetworkWordCount.java" rel="noreferrer">here</a>

blocks|key|747913|text|下面是一个非常简单的例子：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|747914|希望能有所帮助。|747915|String+str+=+"Hello+I'm+your+String";
String[]+splited+=+str.split("+");
var+splited+=+str.split("+");
var+splited1=splited[0];+//Hello
var+splited2=splited[1];+//I'm
var+splited3=splited[2];+//your
var+splited4=splited[3];+//String|code-block|syntax|javascript|747916|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Very Simple Example below:

Hope it helps.

<pre><code>String str = "Hello I'm your String";
String[] splited = str.split(" ");
var splited = str.split(" ");
var splited1=splited[0]; //Hello
var splited2=splited[1]; //I'm
var splited3=splited[2]; //your
var splited4=splited[3]; //String
</code></pre>

blocks|key|747824|text|您可以使用以下代码创建字符串|type|unstyled|depth|inlineStyleRanges|entityRanges|data|747825|+++String+thisString="Hello+world";

+++String[]+parts+=+theString.split("+");

+++String+first+=+parts[0];//"hello"

++++String+second+=+parts[1];//"World"|code-block|syntax|javascript|747826|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

you can saperate string using the below code

<pre><code> String thisString="Hello world";

 String[] parts = theString.split(" ");

 String first = parts[0];//"hello"

 String second = parts[1];//"World"
</code></pre>

blocks|key|747864|text|自从这些答案发布以来已经有一段时间了，这里有另一种更新的方法来做被问到的事情：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|747865|List<String>+output+=+new+ArrayList<>();
try+(Scanner+sc+=+new+Scanner(inputString))+{
++++while+(sc.hasNext())+output.add(sc.next());
}|code-block|syntax|javascript|747866|现在您有了一个字符串列表(可以说比数组更好)；如果确实需要一个数组，可以执行output.toArray(new+String[0]);|offset|length|style|CODE|747867|entityMap^0|0|0|12|U|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Since it's been a while since these answers were posted, here's another more current way to do what's asked:

<pre><code>List&lt;String&gt; output = new ArrayList&lt;&gt;();
try (Scanner sc = new Scanner(inputString)) {
 while (sc.hasNext()) output.add(sc.next());
}
</code></pre>

Now you have a list of strings (which is arguably better than an array); if you do need an array, you can do <code>output.toArray(new String[0]);</code>

blocks|key|531579|text|不仅是空白，我的解决方案也解决了看不见的字符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|531580|str+=+"Hello+I'm+your+String";
String[]+splited+=+str.split("\p{Z}");|code-block|syntax|javascript|531581|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Not only white space, but my solution also solves the invisible characters as well.

<pre><code>str = "Hello I'm your String";
String[] splited = str.split("\p{Z}");
</code></pre>

blocks|key|747671|text|下面是一个方法，用于修剪包含"，“或空格的字符串|type|unstyled|depth|inlineStyleRanges|entityRanges|data|747672|private+String+shorterName(String+s){
++++++++String[]+sArr+=+s.split("\\,%7C\\s%2B");
++++++++String+output+=+sArr[0];

++++++++return+output;
++++}|code-block|syntax|javascript|747673|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is a method to trim a String that has a "," or white space

<pre><code>private String shorterName(String s){
 String[] sArr = s.split("\\,|\\s+");
 String output = sArr[0];

 return output;
 }
</code></pre>

blocks|key|531612|text|合二为一的解决方案！|type|unstyled|depth|inlineStyleRanges|entityRanges|data|531613|public+String+getFirstNameFromFullName(String+fullName){
++++int+indexString+=+fullName.trim().lastIndexOf('+');
++++return+(indexString+!=+-1)++?+fullName.trim().split("\\s%2B")[0].toUpperCase()+:+fullName.toUpperCase();
}|code-block|syntax|javascript|531614|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Join solutions in one!
<pre><code>public String getFirstNameFromFullName(String fullName){
 int indexString = fullName.trim().lastIndexOf(' ');
 return (indexString != -1) ? fullName.trim().split(&quot;\\s+&quot;)[0].toUpperCase() : fullName.toUpperCase();
}
</code></pre>

blocks|key|748026|text|字符的单引号而不是双引号|type|unstyled|depth|inlineStyleRanges|entityRanges|data|748027|String[]拆分=+str.split(‘')；|748028|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

Single quotes for char instead of double
String[] splited = str.split(' ');

I need to split my String by spaces.
For this I tried:

<pre><code>str = "Hello I'm your String";
String[] splited = str.split(" ");
</code></pre>

But it doesn't seem to work.

How to split a String by space

我需要用空格拆分我的字符串。为此，我尝试了：str = "Hello I'm your String";String[] splited = str.split(" ");但它似乎不起作用。

问如何按空格拆分字符串
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回答 15

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问如何按空格拆分字符串
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