我有一个这样的文本文件:
>ENST00000511961.1|ENSG00000013561.13|OTTHUMG00000129660.5|OTTHUMT00000370661.3|RNF14-003|RNF14|278
MSSEDREAQEDELLALASIYDGDEFRKAESVQGGETRIYLDLPQNFKIFVSGNSNECLQNSGFEYTICFLPPLVLNFELPPDYPSSSPPSFTLSGKWLSPTQLSALCKHLDNLWEEHRGSVVLFAWMQFLKEETLAYLNIVSPFELKIGSQKKVQRRTAQASPNTELDFGGAAGSDVDQEEIVDERAVQDVESLSNLIQEILDFDQAQQIKCFNSKLFLCSICFCEKLGSECMYFLECRHVYCKACLKDYFEIQIRDGQVQCLNCPEPKCPSVATPGQ
>ENST00000506822.1|ENSG00000013561.13|OTTHUMG00000129660.5|OTTHUMT00000370662.1|RNF14-004|GAPDH|132
MSSEDREAQEDELLALASIYDGDEFRKAESVQGGETRIYLDLPQNFKIFVSGNSNECLQNSGFEYTICFLPPLVLNFELPPDYPSSSPPSFTLSGKWLSPTQLSALCKHLDNLWEEHRGSVVLFAWMQFLKE
>ENST00000513019.1|ENSG00000013561.13|OTTHUMG00000129660.5|OTTHUMT00000370663.1|RNF14-005|ACTB|99
MSSEDREAQEDELLALASIYDGDEFRKAESVQGGETRIYLDLPQNFKIFVSGNSNECLQNSGFEYTICFLPPLVLNFELPPDYPSSSPPSFTLSGKWLS
>ENST00000356143.1|ENSG00000013561.13|OTTHUMG00000129660.5|-|RNF14-202|HELLE|474
MSSEDREAQEDELLALASIYDGDEFRKAESVQGGETRIYLDLPQNFKIFVSGNSNECLQNSGFEYTICFLPPLVLNFELPPDYPSSSPPSFTLSGKWLSPTQLSALCKHLDNLWEEHRGSVVLFAWMQFLKEETLAYLNIVSPFELKIGSQKKVQRRTAQASPNTELDFGGAAGSDVDQEEIVDERAVQDVESLSNLIQEILDFDQAQQIKCFNSKLFLCSICFCEKLGSECMYFLECRHVYCKACLKDYFEIQIRDGQVQCLNCPEPKCPSVATPGQVKELVEAELFARYDRLLLQSSLDLMADVVYCPRPCCQLPVMQEPGCTMGICSSCNFAFCTLCRLTYHGVSPCKVTAEKLMDLRNEYLQADEANKRLLDQRYGKRVIQKAL
我想在python
中为以">
“开头的行的第6个元素创建一个list
。为此,我首先在python中创建一个dictionary
,然后关键字应该是我想要的list
。如下所示:
from itertools import groupby
with open('infile.txt') as f:
groups = groupby(f, key=lambda x: not x.startswith(">"))
d = {}
for k,v in groups:
if not k:
key, val = list(v)[0].rstrip(), "".join(map(str.rstrip,next(groups)[1],""))
d[key] = val
k = d.keys()
res = [el[5:] for s in k for el in s.split("|")]
但它返回以">".
开头的行中的所有元素
你知道怎么修吗?
以下是预期输出:
["RNF14", "GAPDH", "ACTB", "HELLE"]
发布于 2018-06-02 06:25:16
使用过滤器而不是groupby和map的解决方案
with open('infile.txt') as f:
lines = f.readlines()
groups = filter(lambda x: x.startswith(">"), lines)
res = list(map(lambda x: x.split('|')[5],groups))
https://stackoverflow.com/questions/50651429
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