使用JSON.sh从shell脚本中解析JSON
我正在使用JSON.sh解析JSON数据。我想从json文件(test.json)中读取数据，其内容如下：
{
"/home/ukrishnan/projects/test.yml": {
"LOG_DRIVER": "syslog",
"IMAGE": "mysql:5.6"
},
"/home/ukrishnan/projects/mysql/app.xml": {
"ENV_ACCOUNT_BRIDGE_ENDPOINT": "/u01/src/test/sample.txt"
}
}我试着用JSON.sh解析这个JSON，
test_parser=`sh ./lib/JSON.sh < test/test.json`
echo $test_parser它打印出来，
["/home/ukrishnan/projects/test.yml","LOG_DRIVER"] "syslog" ["/home/ukrishnan/projects/test.yml","IMAGE"] "mysql:5.6" ["/home/ukrishnan/projects/test.yml"] {"LOG_DRIVER":"syslog","IMAGE":"mysql:5.6"} ["/home/ukrishnan/projects/mysql/app.xml","ENV_ACCOUNT_BRIDGE_ENDPOINT"] "/u01/src/test/sample.txt" ["/home/ukrishnan/projects/mysql/app.xml"] {"ENV_ACCOUNT_BRIDGE_ENDPOINT":"/u01/src/test/sample.txt"} [] {"/home/ukrishnan/projects/test.yml":{"LOG_DRIVER":"syslog","IMAGE":"mysql:5.6"},"/home/ukrishnan/projects/mysql/app.xml":{"ENV_ACCOUNT_BRIDGE_ENDPOINT":"/u01/src/test/sample.txt"}}然而，同样的命令(sh ./lib/JSON.sh < test/test.json)，如果我在终端上运行，它是用换行符打印的，
["/home/ukrishnan/projects/test.yml","LOG_DRIVER"] "syslog"
["/home/ukrishnan/projects/test.yml","IMAGE"] "mysql:5.6"
["/home/ukrishnan/projects/test.yml"] {"LOG_DRIVER":"syslog","IMAGE":"mysql:5.6"}
["/home/ukrishnan/projects/mysql/app.xml","ENV_ACCOUNT_BRIDGE_ENDPOINT"] "/u01/src/test/sample.txt"
["/home/ukrishnan/projects/mysql/app.xml"] {"ENV_ACCOUNT_BRIDGE_ENDPOINT":"/u01/src/test/sample.txt"}
[] {"/home/ukrishnan/projects/test.yml":{"LOG_DRIVER":"syslog","IMAGE":"mysql:5.6"},"/home/ukrishnan/projects/mysql/app.xml":{"ENV_ACCOUNT_BRIDGE_ENDPOINT":"/u01/src/test/sample.txt"}}我想读取它并将其赋值给bash变量，例如，
file_name='/home/ukrishnan/projects/test.yml'
key='LOG_DRIVER'
value='syslog'因为我几乎完全不熟悉shell脚本和grep或awk，所以我不太了解如何实现这一点。在这方面的任何帮助都将非常感谢。
回答 1
Stack Overflow用户
发布于 2018-06-09 03:47:19
我写了一个JSON serializer / deserializer for gawk，如果你感兴趣的话。保存该脚本并对其进行修改，将# === FUNCTIONS ===上的所有内容替换为以下内容：
#!/usr/bin/gawk -f
# capture JSON string from beginning to end into a scalar variable
{ json = json ORS $0 }
END {
# objectify JSON string to the multilevel array "obj"
deserialize(json, obj)
for (filename in obj) {
print "file_name=" quote(filename)
for (key in obj[filename]) {
# print key="value"
print key "=" quote(obj[filename][key])
}
}
}执行chmod 755 json.awk并执行它。输出将如下所示：
$ ./json.awk test5.json
file_name="/home/ukrishnan/projects/mysql/app.xml"
ENV_ACCOUNT_BRIDGE_ENDPOINT="/u01/src/test/sample.txt"
file_name="/home/ukrishnan/projects/test.yml"
LOG_DRIVER="syslog"
IMAGE="mysql:5.6"希望逻辑是相当容易遵循的。如果您希望在每次循环迭代时输出filename=、key=和value=，请相应地修改嵌套的for循环：
for (filename in obj) {
for (key in obj[filename]) {
print "file_name=" quote(filename)
print "key=" quote(key)
print "value=" quote(obj[filename][key])
}
}该更改将导致以下输出：
$ ./json.awk test5.json
file_name="/home/ukrishnan/projects/mysql/app.xml"
key="ENV_ACCOUNT_BRIDGE_ENDPOINT"
value="/u01/src/test/sample.txt"
file_name="/home/ukrishnan/projects/test.yml"
key="LOG_DRIVER"
value="syslog"
file_name="/home/ukrishnan/projects/test.yml"
key="IMAGE"
value="mysql:5.6"无论如何，有了这个输出，您可以在BASH中做一些愚蠢的事情来填充变量并对其执行操作：
#!/bin/bash
./test.awk test5.json | while read -r line; do {
eval $line
[ "${line/=*/}" = "value" ] && {
echo "bash: file_name=$file_name"
echo "bash: key=$key"
echo "bash: value=$value"
echo "------"
}
}; done不过，如果从头到尾都在gawk中完成所有处理，而不是搞乱多国语言的移交，可能会更优雅。
回到json.awk，如果您更喜欢将json.awk模块化以便于在将来的项目中重用，您可以删除# === FUNCTIONS ===上面的所有内容，创建一个包含此答案顶部的代码块的单独main.awk，并将@include "json.awk"作为END {...}之外的几乎任何地方(例如，就在shbang之下)的帮助库。
https://stackoverflow.com/questions/36839706
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