Matplotlib使用时间字符串的x轴重叠
Matplotlib使用时间字符串的x轴重叠
提问于 2018-06-12 03:54:43
我想从以下数据创建一个图：
timeArray= ['11:47:46.585', '11:47:46.695', '11:47:46.805', '11:47:46.915', '11:47:47.025', '11:47:47.135', '11:47:47.245', '11:47:47.355', '11:47:47.465', '11:47:47.575', '11:47:47.685', '11:47:47.795', '11:47:47.905', '11:47:48.015', '11:47:48.125', '11:47:48.235', '11:47:48.345', '11:47:48.455', '11:47:48.565', '11:47:48.675', '11:47:48.785', '11:47:48.895', '11:47:49.005', '11:47:49.115', '11:47:49.225', '11:47:49.335', '11:47:49.445', '11:47:49.555', '11:47:49.665', '11:47:49.775', '11:47:49.885', '11:47:49.995', '11:47:50.105', '11:47:50.215', '11:47:50.325', '11:47:50.435', '11:47:50.545', '11:47:50.655', '11:47:50.765', '11:47:50.875', '11:47:50.985', '11:47:51.095', '11:47:51.205', '11:47:51.315', '11:47:51.425', '11:47:51.535', '11:47:51.645', '11:47:51.755', '11:47:51.865', '11:47:51.975', '11:47:52.085', '11:47:52.195', '11:47:52.305', '11:47:52.415']
valueArray = [10382.0, 8372.0, 11117.0, 11804.0, 10164.0, 10221.0, 10488.0, 7910.0, 12911.0, 11422.0, 15361.0, 15424.0, 10629.0, 14993.0, 13827.0, 15164.0, 10514.0, 10356.0, 14638.0, 12272.0, 14980.0, 14391.0, 12984.0, 18967.0, 15792.0, 14753.0, 16205.0, 19187.0, 13922.0, 10787.0, 14500.0, 12918.0, 13985.0, 14695.0, 14014.0, 12087.0, 12163.0, 11424.0, 8598.0, 8573.0, 9986.0, 10315.0, 11449.0, 9146.0, 11160.0, 6861.0, 10211.0, 9097.0, 8443.0, 5446.0, 6354.0, 6829.0, 5786.0, 7860.0]timeArray将是x轴，valueArray将是y轴。
绘制线如下所示：
import matplotlib.pyplot as plt
plt.plot(timeArray,valueArray,'r', label='values over time')我得到了这个图表：
我已经使用了：plt.gcf().autofmt_xdate()，但仍然比下一次更好。
我也尝试过：
xaxis = np.linspace(min(timeArray),max(timeArray), 10)
plt.xticks(xaxis) 但我有一台typeError: ufunc 'multiply' did not contain a loop with signature matching types dtype('<U32') dtype('<U32') dtype('<U32')
有没有一种简单的方法来保持数据的原样，而不是以微秒的速度显示每一次？
回答 2
Stack Overflow用户
回答已采纳
发布于 2018-06-12 04:06:09
我建议您将时间转换为datetime对象，而不是字符串，然后以适当的日期格式使用matplotlib.mdates.DateFormatter()：
import matplotlib.dates as mdates
import datetime
fmt = mdates.DateFormatter('%H:%M:%S')
timeArray = [datetime.datetime.strptime(i, '%H:%M:%S.%f') for i in timeArray]
fig, ax = plt.subplots()
plt.plot(timeArray,valueArray,'r', label='values over time')
ax.xaxis.set_major_formatter(fmt)结果是：
Stack Overflow用户
发布于 2018-06-12 14:02:41
您可以这样做：
import datetime
import matplotlib.pyplot as plt
import pandas as pd
timeArray = pd.to_datetime(pd.Series(timeArray))
plt.plot(timeArray,valueArray,'r', label='values over time')
plt.show()输出：
或者给刻度添加一些旋转：
plt.xticks(rotation=45) # or 90 to be vertical
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原文链接：
https://stackoverflow.com/questions/50805114
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