我的代码不能正常工作。我想把'next_question_id‘按钮的内容发送到我的php文件next_question.php中。然后在div "question_text“中显示输出。我做错了什么..。:)
Javascript
function myFunction(clicked_id) {
var button = clicked_id
var next_question_id = document.getElementById(button).getAttribute("next_question_id");
$.post('next_question.php', {
postnextquestionid: next_question_id
},
function(data) {
$('#question_text').html(data);
});
}
PHP
<?php
include 'conn.php';
$next_question_id = $_POST['next_question_id'];
echo $next_question_id;
?>
发布于 2018-06-06 04:23:53
您的post变量应该是postnextquestionid
,而不是next_question_id
$next_question_id = $_POST['postnextquestionid'];
https://stackoverflow.com/questions/50708323
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