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不知道怎么取数据库?
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Stack Overflow用户
提问于 2018-06-15 01:55:31
回答 1查看 0关注 0票数 0

我是一个完全的初学者,使用sqite和GTK。我正在用代码:Block进行我的第一个项目。在获取数据库时,我遇到了一个问题-我的代码是:

代码语言:txt
复制
#include <stdio.h>
#include <stdlib.h>
#include <gtk/gtk.h>
#include "sqlite3.c"
#include <sqlite3.h>
static int callback(void *data, int argc, char **argv, char **azColName){
 int i;
 fprintf(stderr, "%s: ", (const char*)data);
 for(i=0; i<argc; i++){
  printf("%s = %s\n", azColName[i], argv[i] ? argv[i] : "NULL");
}
printf("\n");
return 0;
}

int main(int argc, char *argv[]) {
 sqlite3 *db;
 char *zErrMsg = 0;
 int rc;
 char *sql;
 const char* data = "Callback function called";

 /* Open database */
 rc = sqlite3_open("sign_in.db", &db);
 if( rc ){
  fprintf(stderr, "Can't open database: %s\n", sqlite3_errmsg(db));
  exit(0);
  }else{
  fprintf(stderr, "Opened database successfully\n");
  }


 GtkWidget *window;
 GtkWidget *table;
 GdkColor color;


 GtkWidget *label1;
 GtkWidget *label2;
 GtkWidget *label3;

 GtkWidget *entry1;
 GtkWidget *entry2;

 GtkWidget *button1;

  gtk_init(&argc, &argv);

 window = gtk_window_new(GTK_WINDOW_TOPLEVEL);
 gtk_window_set_position(GTK_WINDOW(window), GTK_WIN_POS_CENTER);
 gtk_window_set_title(GTK_WINDOW(window), "LOG IN");
  gtk_container_set_border_width(GTK_CONTAINER(window), 30);
 gtk_widget_modify_bg(window, GTK_STATE_NORMAL, &color);


 table = gtk_table_new(3, 2, FALSE);
 gtk_container_add(GTK_CONTAINER(window), table);

 label1 = gtk_label_new("----------------------------------   LOGIN AND ENJOY OUR  FACILITY   -----------------------------------");
 label2 = gtk_label_new("USERNAME :");
 label3= gtk_label_new("PASSWORD :");


 button1 = gtk_button_new_with_label("LOG IN");

 gtk_table_attach(GTK_TABLE(table), label1, 0, 1, 0, 1,
   GTK_FILL |GTK_EXPAND | GTK_SHRINK, GTK_FILL |GTK_EXPAND | GTK_SHRINK, 5, 5);
 gtk_table_attach(GTK_TABLE(table), label2, 0, 1, 1, 2,
   GTK_FILL | GTK_EXPAND |GTK_SHRINK, GTK_FILL | GTK_EXPAND |GTK_SHRINK, 5, 5);
 gtk_table_attach(GTK_TABLE(table), label3, 0, 1, 2, 3,
  GTK_FILL | GTK_EXPAND |GTK_SHRINK, GTK_FILL | GTK_EXPAND |GTK_SHRINK, 5, 5);

 entry1 = gtk_entry_new();
 entry2 = gtk_entry_new();

 gtk_table_attach(GTK_TABLE(table), entry1, 1, 2, 1, 2,
  GTK_FILL |GTK_EXPAND | GTK_SHRINK, GTK_FILL |GTK_EXPAND | GTK_SHRINK, 5, 5);
 gtk_table_attach(GTK_TABLE(table), entry2, 1, 2, 2, 3,
  GTK_FILL |GTK_EXPAND | GTK_SHRINK, GTK_FILL |GTK_EXPAND | GTK_SHRINK, 5, 5);
 gtk_table_attach(GTK_TABLE(table), button1, 1, 2, 3, 4,
  GTK_FILL |GTK_EXPAND | GTK_SHRINK, GTK_FILL |GTK_EXPAND | GTK_SHRINK, 5, 5);
  gtk_widget_show(table);

  gtk_widget_show(label1);
   gtk_widget_show(label2);
   gtk_widget_show(label3);
     gtk_widget_show(entry1);
   gtk_widget_show(entry2);
   gtk_widget_show(button1);

   gtk_widget_show(window);


   /* Create SQL statement */
   sql="SELECT * from user where username='char *entry1' and password='char *entry2 '";
   if(sqlite3_exec(db, sql, callback, (void*)data, &zErrMsg))
  {
   int count=0;
   while(sqlite3_exec(db, sql, callback, (void*)data, &zErrMsg)+1)
   {
       count++;
   }
   if(count==1)
    fprintf(stdout, "username and password is correct\n");
          if(count>1)
    fprintf(stdout, "Dulitcate user\n");
           if(count<1)
    fprintf(stdout, "username and password is not correct\n");

   }
     /* Execute SQL statement */
   rc = sqlite3_exec(db, sql, callback, (void*)data, &zErrMsg);
  if( rc != SQLITE_OK ){
   fprintf(stderr, "SQL error: %s\n", zErrMsg);
  sqlite3_free(zErrMsg);
  }else{
  fprintf(stdout, "Operation done successfully\n");
  }
 sqlite3_close(db);

  g_signal_connect(G_OBJECT(button1), "clicked",
  G_CALLBACK(gtk_main_quit), G_OBJECT(window));


  g_signal_connect(window, "destroy",
  G_CALLBACK(gtk_main_quit), NULL);
EN

回答 1

Stack Overflow用户

发布于 2018-06-15 11:50:42

sqlite3_exec如果要在查询数据的地方处理返回的数据,并且有其他缺点,则不适合。

代码语言:txt
复制
char *user = "Supu";
char *password = "secret";
sqlite3_stmt *stmt;
const char *sql = "SELECT username, password FROM user WHERE username = ? AND password = ?";
rc = sqlite3_prepare_v2(db, sql, -1, &stmt, NULL);
if (rc != SQLITE_OK) {
    fprintf(stderr, "error: %s, %s\n", sql, sqlite3_errmsg(db));
} else {
    sqlite3_bind_text(stmt, 1, user, -1, SQLITE_TRANSIENT);
    sqlite3_bind_text(stmt, 2, password, -1, SQLITE_TRANSIENT);
    while ((rc = sqlite3_step(stmt)) == SQLITE_ROW) {
        printf("returned row: user = %s, password = %s\n",
               sqlite3_column_text(stmt, 0),
               sqlite3_column_text(stmt, 1));
        count++;
    }
    if (rc != SQLITE_DONE)
        fprintf(stderr, "error: %s\n", sqlite3_errmsg(db));
    sqlite3_finalize(stmt);
}
票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/-100005403

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