我得到了exception-org.apache.catalina.core.ApplicationDispatcher.invoke抛出的异常java.lang.IllegalStateException
我得到了exception-org.apache.catalina.core.ApplicationDispatcher.invoke抛出的异常java.lang.IllegalStateException
提问于 2018-05-08 15:11:19
我的服务器日志中出现以下错误，
08-May-2018 12:00:07.460 SEVERE [https-jsse-nio-8443-exec-1] org.apache.catalina.core.ApplicationDispatcher.invoke Servlet.service() for servlet [jsp] threw exception java.lang.IllegalStateException: getOutputStream() has already been called for this response
at org.apache.catalina.connector.Response.getWriter(Response.java:624)
at org.apache.catalina.connector.ResponseFacade.getWriter(ResponseFacade.java:211)
at javax.servlet.ServletResponseWrapper.getWriter(ServletResponseWrapper.java:109)
at javax.servlet.ServletResponseWrapper.getWriter(ServletResponseWrapper.java:109)
at javax.servlet.ServletResponseWrapper.getWriter(ServletResponseWrapper.java:109)
at org.springframework.security.web.util.OnCommittedResponseWrapper.getWriter(OnCommittedResponseWrapper.java:149)
at org.apache.jasper.runtime.JspWriterImpl.initOut(JspWriterImpl.java:118)
at org.apache.jasper.runtime.JspWriterImpl.flushBuffer(JspWriterImpl.java:111)
at org.apache.jasper.runtime.PageContextImpl.release(PageContextImpl.java:176)
at org.apache.jasper.runtime.JspFactoryImpl.internalReleasePageContext(JspFactoryImpl.java:120)
at org.apache.jasper.runtime.JspFactoryImpl.releasePageContext(JspFactoryImpl.java:75)
at org.apache.jsp.WEB_002dINF.views.uncaughtException_html._jspService(uncaughtException_html.java:209)
08-May-2018 12:00:07.468 SEVERE [https-jsse-nio-8443-exec-1] org.apache.catalina.core.StandardWrapperValve.invoke Servlet.service() for servlet [xyz] in context with path [] threw exception java.lang.IllegalStateException: getOutputStream() has already been called for this response] with root cause java.lang.IllegalStateException: getOutputStream() has already been called for this response
at org.apache.catalina.connector.Response.getWriter(Response.java:624)
at org.apache.catalina.connector.ResponseFacade.getWriter(ResponseFacade.java:211)
at javax.servlet.ServletResponseWrapper.getWriter(ServletResponseWrapper.java:109)
at javax.servlet.ServletResponseWrapper.getWriter(ServletResponseWrapper.java:109)
at javax.servlet.ServletResponseWrapper.getWriter(ServletResponseWrapper.java:109)
at org.springframework.security.web.util.OnCommittedResponseWrapper.getWriter(OnCommittedResponseWrapper.java:149)
at org.apache.jasper.runtime.JspWriterImpl.initOut(JspWriterImpl.java:118)
at org.apache.jasper.runtime.JspWriterImpl.flushBuffer(JspWriterImpl.java:111)
at org.apache.jasper.runtime.PageContextImpl.release(PageContextImpl.java:176)
at org.apache.jasper.runtime.JspFactoryImpl.internalReleasePageContext(JspFactoryImpl.java:120)
at org.apache.jasper.runtime.JspFactoryImpl.releasePageContext(JspFactoryImpl.java:75)
at org.apache.jsp.WEB_002dINF.views.uncaughtException_html._jspService(uncaughtException_html.java:209)
at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:742)
at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:443)
at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:386)
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:330)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:742)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:231)我不知道是哪个方法抛出了这个错误，以及这个错误的原因是什么。实际上，这个异常发生在我在tomcat中部署我的应用程序并试图获取索引页的时候(有时是第一次，有时是第二次，有时是第三次，不管它什么时候出现。)，实际上，根据我的配置，当ssl启用时，当我部署我的应用程序并试图获取欢迎页面会话过期页面时，将调用该页面，并且从现在开始，一旦我尝试获取其他页面，它将抛出上述异常。我用的是spring 4，spring security，maven，hibernate 4，有人能帮我吗？任何帮助都会得到重视。
web.xml
<web-app>
<display-name>Smart app Application</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-security.xml, /WEB-INF/app-servlet.xml
</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.security.web.session.HttpSessionEventPublisher</listener-class>
</listener>
<servlet>
<servlet-name>app</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>app</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>jsp</servlet-name>
<url-pattern>/WEB-INF/views/*</url-pattern>
</servlet-mapping>
<security-constraint>
<web-resource-collection>
<web-resource-name>application</web-resource-name>
<url-pattern>/*</url-pattern>
</web-resource-collection>
<user-data-constraint>
<transport-guarantee>CONFIDENTIAL</transport-guarantee>
</user-data-constraint>
</security-constraint>
<filter>
<filter-name>encodingFilter</filter-name>
<filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
<init-param>
<param-name>encoding</param-name>
<param-value>UTF-8</param-value>
</init-param>
<init-param>
<param-name>forceEncoding</param-name>
<param-value>true</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>encodingFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<welcome-file-list>
<welcome-file>index</welcome-file>
</welcome-file-list>
<session-config>
<session-timeout>50</session-timeout>
</session-config>
</web-app>回答 1
Stack Overflow用户
回答已采纳
发布于 2018-06-13 18:57:21
如果你有一个SimpleMappingExceptionResolver，试着检查你的ControllerAdvice注解类是否有冲突。异常只能在一个地方处理。
正如我所说的，它可以由循环关系和Jackason作为序列化程序生成。在这里，你有一些选项，比如使用DTO来简化答案，或者user @JsonIgnore。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50227896
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