计数从另一个Json数组中筛选出来的Json数组数量
计数从另一个Json数组中筛选出来的Json数组数量
提问于 2018-06-05 03:21:04
我有两个json需要使用Angular cli 6.0进行嵌套。
我刚来angular，所以我需要帮助..
Json 1
[{"Name": "Fields1",
"DFields":["Fields1_1","Fields1_2"]
},
{"Name": "Fields2",
"DFields":["Fields2_1"]
}]Json 2
[
{"Id": "1", "Fields1_1": 1 , "Fields1_2": 1, "Fields2_1: 1},
{"Id": "2", "Fields1_1": 1 , "Fields1_2": 0, "Fields2_1: 1}
{"Id": "3", "Fields1_1": 1 , "Fields1_2": 1, "Fields2_1: null}
]循环字段并计算其相应数据的速度更快的方法是什么？该计数不应为空或零..
该示例应返回一个数组..
Fields1_1 = 3
Fields1_2 = 2
Fields2_1 = 2请注意，这些字段是动态的，可以根据json进行更改。
回答 1
Stack Overflow用户
回答已采纳
发布于 2018-06-05 04:14:39
RxJs v6解决方案:)
const json1 = [
{ "Name": "Fields1", "DFields": ["Fields1_1", "Fields1_2"] },
{ "Name": "Fields2", "DFields": ["Fields2_1"] }
];
const json2 = [
{ "Id": "1", "Fields1_1": 1, "Fields1_2": 1, "Fields2_1": 1 },
{ "Id": "2", "Fields1_1": 1, "Fields1_2": 0, "Fields2_1": 1 },
{ "Id": "3", "Fields1_1": 1, "Fields1_2": 5, "Fields2_1": null }
];
from(json2).pipe(
map(obj => Object.keys(obj).map(k => { return { key: k, val: obj[k] } })),
flatMap(kvPairArray => from(kvPairArray)),
groupBy(kvPair => kvPair.key),
filter(group => json1.map(a => a.DFields).reduce((acc, curr) => [...acc, ...curr], []).includes(group.key)),
mergeMap(group => group.pipe(
filter(groupEntry => groupEntry.val !== null && groupEntry.val !== 0),
reduce<{key: string, val: number},number>((acc, groupEntry) => acc + groupEntry.val, 0),
map(count => {
return {
key: group.key,
count: count
};
})
)),
toArray()
).subscribe(result => console.log(result));页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50687429
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