下面的代码将弹出一个具有相同问题的测试按钮。
import tkinter as tk
if __name__ == '__main__':
root = tk.Tk()
root.title('Button Test')
button = tk.Button(root, text = 'test me', padx= '20', pady = '20')
button.grid()
root.mainloop()
编辑:我四处搜索,发现有些人通过更新Python/TCL包来解决类似的问题,但我的问题似乎是持久的。
发布于 2018-07-24 15:58:09
改变:
import tkinter as tk
if __name__ = '__main__': # needs to be == not =.
root = tk.Tk()
root.title('Button Test')
# test= should be text=. remove command if you are not using it.
# typo in padx. padx '20; should be padx='20'
button = tk.Button(root, test = 'test me', command = None, padx '20;, pady = '20')
button.grid()
root.mainloop()
对此:
import tkinter as tk
if __name__ == '__main__':
root = tk.Tk()
root.title('Button Test')
button = tk.Button(root, text='test me', padx='20', pady='20')
button.grid()
root.mainloop()
https://stackoverflow.com/questions/-100008712
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