问如何在java中提取zip文件中的特定文件？

EN

public static void main(String[] args) throws Exception{
        String fileToBeExtracted="fileName";
        String zipPackage="zip_name_with_full_path";
        OutputStream out = new FileOutputStream(fileToBeExtracted);
        FileInputStream fileInputStream = new FileInputStream(zipPackage);
        BufferedInputStream bufferedInputStream = new BufferedInputStream(fileInputStream );
        ZipInputStream zin = new ZipInputStream(bufferedInputStream);
        ZipEntry ze = null;
        while ((ze = zin.getNextEntry()) != null) {
            if (ze.getName().equals(fileToBeExtracted)) {
                byte[] buffer = new byte[9000];
                int len;
                while ((len = zin.read(buffer)) != -1) {
                    out.write(buffer, 0, len);
                }
                out.close();
                break;
            }
        }
        zin.close();

    }

ZipFile zf = new ZipFile(file);
try {
  InputStream in = zf.getInputStream(zf.getEntry("file.txt"));
  // ... read from 'in' as normal
} finally {
  zf.close();
}

Path zipfile = Paths.get("/samples/ziptest.zip");
FileSystem fs = FileSystems.newFileSystem(zipfile, env, null);
final Path root = fs.getPath("/file.TXT");