blocks|key|273296|text|如果您知道扩展名，则可以使用basename|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|273297|$+basename+/home/jsmith/base.wiki+.wiki
base|code-block|syntax|javascript|273298|entityMap|0|LINK|mutability|MUTABLE|url|http://wikipedia.org/wiki/Basename^0|E|8|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

If you know the extension, you can use <a href="http://wikipedia.org/wiki/Basename">basename</a>

<pre><code>$ basename /home/jsmith/base.wiki .wiki
base
</code></pre>

blocks|key|490454|text|如果您的文件名包含一个点(而不是扩展名的点)，则使用以下命令：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|490455|echo+$filename+%7C+rev+%7C+cut+-f+2-+-d+'.'+%7C+rev|code-block|syntax|javascript|490456|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If your filename contains a dot (other than the one of the extension) then use this:

<pre><code>echo $filename | rev | cut -f 2- -d '.' | rev
</code></pre>

blocks|key|490509|text|file1=/tmp/main.one.two.sh
t=$(basename+"$file1")++++++++++++++++++++++++#+output+is+main.one.two.sh
name=$(echo+"$file1"+%7C+sed+-e+'s/\.[%5E.]*$//')+#+output+is+/tmp/main.one.two
name=$(echo+"$t"+%7C+sed+-e+'s/\.[%5E.]*$//')+++++#+output+is+main.one.two|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|490510|你想用什么就用哪一个。在这里，我假设文本后面的最后一个.+(点)是扩展名。|unstyled|offset|length|style|CODE|490511|entityMap^0|0|R|1|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>file1=/tmp/main.one.two.sh
t=$(basename "$file1") # output is main.one.two.sh
name=$(echo "$file1" | sed -e 's/\.[^.]*$//') # output is /tmp/main.one.two
name=$(echo "$t" | sed -e 's/\.[^.]*$//') # output is main.one.two
</code></pre>

use whichever you want. Here I assume that last <code>.</code> (dot) followed by text is extension.

blocks|key|273643|text|仅使用POSIX的内置功能：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|273644|#!/usr/bin/env+sh
path=this.path/with.dots/in.path.name/filename.tar.gz

#+Get+the+basedir+without+external+command
#+by+stripping+out+shortest+trailing+match+of+/+followed+by+anything
dirname=${path%25/*}

#+Get+the+basename+without+external+command
#+by+stripping+out+longest+leading+match+of+anything+followed+by+/
basename=${path##*/}

#+Strip+uptmost+trailing+extension+only
#+by+stripping+out+shortest+trailing+match+of+dot+followed+by+anything
oneextless=${basename%25.*};+echo+"$noext"+

#+Strip+all+extensions
#+by+stripping+out+longest+trailing+match+of+dot+followed+by+anything
noext=${basename%25%25.*};+echo+"$noext"

#+Printout+demo
printf+%25s\\n+"$path"+"$dirname"+"$basename"+"$oneextless"+"$noext"|code-block|syntax|javascript|273645|打印输出演示：|273646|this.path/with.dots/in.path.name/filename.tar.gz
this.path/with.dots/in.path.name
filename.tar.gz
filename.tar
filename|273647|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Using POSIX's built-in only:
<pre class="lang-sh prettyprint-override"><code>#!/usr/bin/env sh
path=this.path/with.dots/in.path.name/filename.tar.gz

# Get the basedir without external command
# by stripping out shortest trailing match of / followed by anything
dirname=${path%/*}

# Get the basename without external command
# by stripping out longest leading match of anything followed by /
basename=${path##*/}

# Strip uptmost trailing extension only
# by stripping out shortest trailing match of dot followed by anything
oneextless=${basename%.*}; echo &quot;$noext&quot; 

# Strip all extensions
# by stripping out longest trailing match of dot followed by anything
noext=${basename%%.*}; echo &quot;$noext&quot;

# Printout demo
printf %s\\n &quot;$path&quot; &quot;$dirname&quot; &quot;$basename&quot; &quot;$oneextless&quot; &quot;$noext&quot;
</code></pre>
Printout demo:
<pre class="lang-none prettyprint-override"><code>this.path/with.dots/in.path.name/filename.tar.gz
this.path/with.dots/in.path.name
filename.tar.gz
filename.tar
filename
</code></pre>

blocks|key|490554|text|#!/bin/bash
file=/tmp/foo.bar.gz
echo+$file+${file%25.*}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|490555|输出：|unstyled|490556|/tmp/foo.bar.gz+/tmp/foo.bar|490557|请注意，只有最后一个扩展名被删除。|490558|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>#!/bin/bash
file=/tmp/foo.bar.gz
echo $file ${file%.*}
</code></pre>

outputs:

<pre><code>/tmp/foo.bar.gz /tmp/foo.bar
</code></pre>

Note that only the last extension is removed.

blocks|key|490513|text|#!/bin/bash
filename=program.c
name=$(basename+"$filename"+.c)
echo+"$name"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|490514|输出：|unstyled|490515|program|490516|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre class="lang-sh prettyprint-override"><code>#!/bin/bash
filename=program.c
name=$(basename "$filename" .c)
echo "$name"
</code></pre>

outputs:

<pre><code>program
</code></pre>

blocks|key|273523|text|正如Hawker65在chepner+answer的评论中指出的那样，投票最多的解决方案既不关心多个扩展名(如filename.tar.gz)，也不关心路径其余部分中的点(如this.path/+path+.dots/in.path.name)。一种可能的解决方案是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|273524|a=this.path/with.dots/in.path.name/filename.tar.gz
echo+$(dirname+$a)/$(basename+$a+%7C+cut+-d.+-f1)|code-block|syntax|javascript|273525|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

As pointed out by Hawker65 in the comment of chepner answer, the most voted solution does neither take care of multiple extensions (such as filename.tar.gz), nor of dots in the rest of the path (such as this.path/with.dots/in.path.name).
A possible solution is:

<pre><code>a=this.path/with.dots/in.path.name/filename.tar.gz
echo $(dirname $a)/$(basename $a | cut -d. -f1)
</code></pre>

blocks|key|273574|text|之前提供的答案存在包含点的路径问题。下面是一些例子：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|273575|/xyz.dir/file.ext
./file.ext
/a.b.c/x.ddd.txt|code-block|syntax|javascript|273576|我更喜欢使用%7Csed+-e+'s/\.[%5E./]*$//'。例如：|offset|length|style|CODE|273577|$+echo+"/xyz.dir/file.ext"+%7C+sed+-e+'s/\.[%5E./]*$//'
/xyz.dir/file
$+echo+"./file.ext"+%7C+sed+-e+'s/\.[%5E./]*$//'
./file
$+echo+"/a.b.c/x.ddd.txt"+%7C+sed+-e+'s/\.[%5E./]*$//'
/a.b.c/x.ddd|273578|注意:如果要删除多个扩展名(如上一个示例所示)，请使用%7Csed+-e+'s/\.[%5E/]*$//'|273579|$+echo+"/a.b.c/x.ddd.txt"+%7C+sed+-e+'s/\.[%5E/]*$//'
/a.b.c/x|273580|273581|但是，此方法在没有扩展名的“点文件”中将失败：|273582|$+echo+"/a.b.c/.profile"+%7C+sed+-e+'s/\.[%5E./]*$//'
/a.b.c/|273583|要涵盖这类情况，您可以使用：|273584|$+echo+"/a.b.c/.profile"+%7C+sed+-re+'s/(%5E.*[%5E/])\.[%5E./]*$/\1/'
/a.b.c/.profile|273585|entityMap^0|0|0|6|N|0|0|R|M|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|13|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|15|8|@$I|16|J|17|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|18|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|19|8|@$I|1A|J|1B|K|L]]|9|@]|A|$]]|$1|Q|3|R|5|D|7|1C|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]|$1|T|3|U|5|6|7|1E|8|@]|9|@]|A|$]]|$1|V|3|W|5|D|7|1F|8|@]|9|@]|A|$E|F]]|$1|X|3|Y|5|6|7|1G|8|@]|9|@]|A|$]]|$1|Z|3|10|5|D|7|1H|8|@]|9|@]|A|$E|F]]|$1|11|3|-4|5|6|7|1I|8|@]|9|@]|A|$]]]|12|$]]

Answers provided previously have problems with paths containing dots. Some examples:
<pre><code>/xyz.dir/file.ext
./file.ext
/a.b.c/x.ddd.txt
</code></pre>
I prefer to use <code>|sed -e 's/\.[^./]*$//'</code>. For example:
<pre><code>$ echo &quot;/xyz.dir/file.ext&quot; | sed -e 's/\.[^./]*$//'
/xyz.dir/file
$ echo &quot;./file.ext&quot; | sed -e 's/\.[^./]*$//'
./file
$ echo &quot;/a.b.c/x.ddd.txt&quot; | sed -e 's/\.[^./]*$//'
/a.b.c/x.ddd
</code></pre>
Note: If you want to remove multiple extensions (as in the last example), use <code>|sed -e 's/\.[^/]*$//'</code>:
<pre><code>$ echo &quot;/a.b.c/x.ddd.txt&quot; | sed -e 's/\.[^/]*$//'
/a.b.c/x
</code></pre>
<hr />
However, this method will fail in &quot;dot-files&quot; with no extension:
<pre><code>$ echo &quot;/a.b.c/.profile&quot; | sed -e 's/\.[^./]*$//'
/a.b.c/
</code></pre>
To cover also such cases, you can use:
<pre><code>$ echo &quot;/a.b.c/.profile&quot; | sed -re 's/(^.*[^/])\.[^./]*$/\1/'
/a.b.c/.profile
</code></pre>

blocks|key|490907|text|在Zsh中：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|490908|fullname=bridge.zip
echo+${fullname:r}|code-block|syntax|javascript|490909|它很简单，干净，并且可以链接起来删除多个扩展：|490910|fullname=bridge.tar.gz
echo+${fullname:r:r}|490911|并且可以与其他类似的modifiers结合使用。|offset|length|490912|entityMap|0|LINK|mutability|MUTABLE|url|https://zsh.sourceforge.io/Doc/Release/Expansion.html#Modifiers^0|0|0|0|0|A|9|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|10|8|@]|9|@$M|11|N|12|1|13]]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

In Zsh:
<pre><code>fullname=bridge.zip
echo ${fullname:r}
</code></pre>
It's simple, clean and it can be chained to remove more than one extension:
<pre><code>fullname=bridge.tar.gz
echo ${fullname:r:r}
</code></pre>
And it can be combined with other similar <a href="https://zsh.sourceforge.io/Doc/Release/Expansion.html#Modifiers" rel="nofollow noreferrer">modifiers</a>.

blocks|key|490857|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|490858|📷|atomic|offset|length|490859|490860|假设您的文件具有.new扩展名|490861|ls+-1+%7C+awk+'{+print+"mv+"$1“basename+"$1"+.new"}‘%7C+sh|style|CODE|490862|由于在发帖后没有显示特殊的引号，请参阅图片。|490863|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/bef5c3fb52111ca2e22e27d93b0a3b69.png|imageAlt^0|0|0|1|0|0|0|0|T|I|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@$E|10|F|11|1|12]]|A|$]]|$1|G|3|4|5|6|7|13|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|14|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|15|8|@$E|16|F|17|L|M]]|9|@]|A|$]]|$1|N|3|O|5|6|7|18|8|@]|9|@]|A|$]]|$1|P|3|-4|5|6|7|19|8|@]|9|@]|A|$]]]|Q|$R|$5|S|T|U|A|$V|W|X|-4]]]]

<a href="https://i.stack.imgur.com/Mnh6P.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/Mnh6P.png" alt="enter image description here" /></a>
Assuming your files have .new extension
ls -1 | awk '{ print &quot;mv &quot;$1&quot; <code>basename &quot;$1&quot; .new</code>&quot;}' | sh
Since it is not showing special quotes after posting, please see image.

What's wrong with the following code?

<pre><code>name='$filename | cut -f1 -d'.''
</code></pre>

As is, I get the literal string <code>$filename | cut -f1 -d'.'</code>, but if I remove the quotes I don't get anything. Meanwhile, typing

<pre><code>"test.exe" | cut -f1 -d'.'
</code></pre>

in a shell gives me the output I want, <code>test</code>. I already know <code>$filename</code> has been assigned the right value. What I want to do is assign to a variable the filename without the extension.

How can I remove the extension of a filename in a shell script?

下面的代码有什么问题？name='$filename | cut -f1 -d'.''按原样，我得到了文字字符串$filename | cut -f1 -d'.'，但是如果我去掉引号，我什么也得不到。同时，输入"test.exe" | cut -f1 -d'.'在shell中给出了我想要的输出，test。我已经知道$filename已经被分配了正确的值。我想要做的是将不带扩展名的文件名分配给一个变

问如何删除shell脚本中文件名的扩展名？
EN

回答 10

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问如何删除shell脚本中文件名的扩展名？EN

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问如何删除shell脚本中文件名的扩展名？
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