是否有可能将以一种方式叠加的Python数组重新组合成另一种堆叠类型?

内容来源于 Stack Overflow,并遵循CC BY-SA 3.0许可协议进行翻译与使用

  • 回答 (1)
  • 关注 (0)
  • 查看 (259)

我有一个数组:

import numpy as np
shape = (3, 2, 2)
x = np.round(np.random.rand(*shape) * 100)
y = np.round(np.random.rand(*shape) * 100)
z = np.round(np.random.rand(*shape) * 100)
w = np.round(np.random.rand(*shape) * 100)
first_stacked = np.stack((x, y, z, w), axis=0)
print(first_stacked.shape)  # (4, 3, 2, 2)

我想转换成这个数组:

import numpy as np
shape = (3, 2, 2)
x = np.round(np.random.rand(*shape) * 100)
y = np.round(np.random.rand(*shape) * 100)
z = np.round(np.random.rand(*shape) * 100)
w = np.round(np.random.rand(*shape) * 100)
last_stacked = np.stack((x, y, z, w), axis=-1)
print(last_stacked.shape)  # (3, 2, 2, 4)

我试过这个:

new_stacked = [i for i in first_stacked]
new_stacked = np.stack(new_stacked, axis=-1)
other_stacked = np.stack(first_stacked, axis=-1)
print(new_stacked.shape)
print(other_stacked.shape)
print(np.array_equal(new_stacked, last_stacked))
print(np.array_equal(new_stacked, other_stacked))

输出:

(3, 2, 2, 4)
(3, 2, 2, 4)
False
True

我遗漏了什么?能不能在first_stacked用一个reshape

我将x,y,z,w数组随机化了两次,第二个值显然不等于第一个。

我的代码如下:

import numpy as np
shape = (3, 2, 2)
x = np.round(np.random.rand(*shape) * 100)
y = np.round(np.random.rand(*shape) * 100)
z = np.round(np.random.rand(*shape) * 100)
w = np.round(np.random.rand(*shape) * 100)
first_stacked = np.stack((x, y, z, w), axis=0)
print(first_stacked.shape)
last_stacked = np.stack((x, y, z, w), axis=-1)
print(last_stacked.shape)

new_stacked = [i for i in first_stacked]
new_stacked = np.stack(new_stacked, axis=-1)
other_stacked = np.stack(first_stacked, axis=-1)
print(new_stacked.shape)
print(other_stacked.shape)
print(np.array_equal(new_stacked, last_stacked))
print(np.array_equal(new_stacked, other_stacked))

输出:

(4, 3, 2, 2)
(3, 2, 2, 4)
(3, 2, 2, 4)
(3, 2, 2, 4)
True
True
提问于
用户回答回答于

你可以用numpy.moveaxis将第一个轴移动到最后一个位置。

np.moveaxis(first_stacked, 0, -1)

或者你可以把轴滚到想要的位置。

np.rollaxis(first_stacked, 0, first_stacked.ndim)

扫码关注云+社区

领取腾讯云代金券