## 是否有可能将以一种方式叠加的Python数组重新组合成另一种堆叠类型？内容来源于 Stack Overflow，并遵循CC BY-SA 3.0许可协议进行翻译与使用

• 回答 (1)
• 关注 (0)
• 查看 (259)

```import numpy as np
shape = (3, 2, 2)
x = np.round(np.random.rand(*shape) * 100)
y = np.round(np.random.rand(*shape) * 100)
z = np.round(np.random.rand(*shape) * 100)
w = np.round(np.random.rand(*shape) * 100)
first_stacked = np.stack((x, y, z, w), axis=0)
print(first_stacked.shape)  # (4, 3, 2, 2)```

```import numpy as np
shape = (3, 2, 2)
x = np.round(np.random.rand(*shape) * 100)
y = np.round(np.random.rand(*shape) * 100)
z = np.round(np.random.rand(*shape) * 100)
w = np.round(np.random.rand(*shape) * 100)
last_stacked = np.stack((x, y, z, w), axis=-1)
print(last_stacked.shape)  # (3, 2, 2, 4)```

```new_stacked = [i for i in first_stacked]
new_stacked = np.stack(new_stacked, axis=-1)
other_stacked = np.stack(first_stacked, axis=-1)
print(new_stacked.shape)
print(other_stacked.shape)
print(np.array_equal(new_stacked, last_stacked))
print(np.array_equal(new_stacked, other_stacked))```

```(3, 2, 2, 4)
(3, 2, 2, 4)
False
True```

```import numpy as np
shape = (3, 2, 2)
x = np.round(np.random.rand(*shape) * 100)
y = np.round(np.random.rand(*shape) * 100)
z = np.round(np.random.rand(*shape) * 100)
w = np.round(np.random.rand(*shape) * 100)
first_stacked = np.stack((x, y, z, w), axis=0)
print(first_stacked.shape)
last_stacked = np.stack((x, y, z, w), axis=-1)
print(last_stacked.shape)

new_stacked = [i for i in first_stacked]
new_stacked = np.stack(new_stacked, axis=-1)
other_stacked = np.stack(first_stacked, axis=-1)
print(new_stacked.shape)
print(other_stacked.shape)
print(np.array_equal(new_stacked, last_stacked))
print(np.array_equal(new_stacked, other_stacked))```

```(4, 3, 2, 2)
(3, 2, 2, 4)
(3, 2, 2, 4)
(3, 2, 2, 4)
True
True```

### 1 个回答

`np.moveaxis(first_stacked, 0, -1)`

`np.rollaxis(first_stacked, 0, first_stacked.ndim)`