blocks|key|1439960|text|下面这样的代码应该能起到作用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1439961|String+dt+=+"2008-01-01";++//+Start+date
SimpleDateFormat+sdf+=+new+SimpleDateFormat("yyyy-MM-dd");
Calendar+c+=+Calendar.getInstance();
c.setTime(sdf.parse(dt));
c.add(Calendar.DATE,+1);++//+number+of+days+to+add
dt+=+sdf.format(c.getTime());++//+dt+is+now+the+new+date|code-block|syntax|javascript|1439962|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Something like this should do the trick:

<pre><code>String dt = "2008-01-01"; // Start date
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
Calendar c = Calendar.getInstance();
c.setTime(sdf.parse(dt));
c.add(Calendar.DATE, 1); // number of days to add
dt = sdf.format(c.getTime()); // dt is now the new date
</code></pre>

blocks|key|1440040|text|更新(2021年5月)：对于老旧的Java来说，这是一个非常过时的答案。对于Java8和更高版本，请参阅https://stackoverflow.com/a/20906602/314283|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1440041|与C#相比，Java看起来确实远远落后于八球。此实用程序方法显示了在JavaSE6中使用Calendar.add+method执行此操作的方法(可能是惟一简单的方法)。|1440042|public+class+DateUtil
{
++++public+static+Date+addDays(Date+date,+int+days)
++++{
++++++++Calendar+cal+=+Calendar.getInstance();
++++++++cal.setTime(date);
++++++++cal.add(Calendar.DATE,+days);+//minus+number+would+decrement+the+days
++++++++return+cal.getTime();
++++}
}|code-block|syntax|javascript|1440043|要添加一天，根据所问的问题，请按如下方式调用它：|1440044|String+sourceDate+=+"2012-02-29";
SimpleDateFormat+format+=+new+SimpleDateFormat("yyyy-MM-dd");
Date+myDate+=+format.parse(sourceDate);
myDate+=+DateUtil.addDays(myDate,+1);|1440045|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/20906602/314283|1|http://docs.oracle.com/javase/6/docs/api/java/util/Calendar.html#add%2528int,%2520int%2529^0|1G|17|0|0|18|J|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|6|7|12|8|@]|9|@$A|13|B|14|1|15]]|C|$]]|$1|F|3|G|5|H|7|16|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|17|8|@]|9|@]|C|$]]|$1|M|3|N|5|H|7|18|8|@]|9|@]|C|$I|J]]|$1|O|3|-4|5|6|7|19|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]|W|$5|R|S|T|C|$U|X]]]]

UPDATE (May 2021): This is a really outdated answer for old, old Java. For Java 8 and above, see <a href="https://stackoverflow.com/a/20906602/314283">https://stackoverflow.com/a/20906602/314283</a>
Java does appear to be well behind the eight-ball compared to C#. This utility method shows the way to do in Java SE 6 using the <a href="http://docs.oracle.com/javase/6/docs/api/java/util/Calendar.html#add%28int,%20int%29" rel="noreferrer">Calendar.add method</a> (presumably the only easy way).
<pre><code>public class DateUtil
{
 public static Date addDays(Date date, int days)
 {
 Calendar cal = Calendar.getInstance();
 cal.setTime(date);
 cal.add(Calendar.DATE, days); //minus number would decrement the days
 return cal.getTime();
 }
}
</code></pre>
To add one day, per the question asked, call it as follows:
<pre><code>String sourceDate = &quot;2012-02-29&quot;;
SimpleDateFormat format = new SimpleDateFormat(&quot;yyyy-MM-dd&quot;);
Date myDate = format.parse(sourceDate);
myDate = DateUtil.addDays(myDate, 1);
</code></pre>

blocks|key|1654810|text|java.time|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1654811|在Java8和更高版本上，java.time+package使得这几乎是自动的。(Tutorial)|offset|length|1654812|假设String输入和输出：|style|CODE|1654813|import+java.time.LocalDate;

public+class+DateIncrementer+{
++static+public+String+addOneDay(String+date)+{
++++return+LocalDate.parse(date).plusDays(1).toString();
++}
}|code-block|syntax|javascript|1654814|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/8/docs/api/java/time/package-summary.html|1|http://docs.oracle.com/javase/tutorial/datetime/overview/index.html^0|0|D|H|0|15|8|1|0|2|6|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Z|8|@]|9|@$D|10|E|11|1|12]|$D|13|E|14|1|15]]|A|$]]|$1|F|3|G|5|6|7|16|8|@$D|17|E|18|H|I]]|9|@]|A|$]]|$1|J|3|K|5|L|7|19|8|@]|9|@]|A|$M|N]]|$1|O|3|-4|5|6|7|1A|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]|W|$5|R|S|T|A|$U|X]]]]

<h1>java.time</h1>

On Java 8 and later, the <a href="http://docs.oracle.com/javase/8/docs/api/java/time/package-summary.html">java.time package</a> makes this pretty much automatic. (<a href="http://docs.oracle.com/javase/tutorial/datetime/overview/index.html">Tutorial</a>)

Assuming <code>String</code> input and output:

<pre><code>import java.time.LocalDate;

public class DateIncrementer {
 static public String addOneDay(String date) {
 return LocalDate.parse(date).plusDays(1).toString();
 }
}
</code></pre>

blocks|key|1654677|text|SimpleDateFormat+dateFormat+=+new+SimpleDateFormat(+"yyyy-MM-dd"+);
Calendar+cal+=+Calendar.getInstance();
cal.setTime(+dateFormat.parse(+inputString+)+);
cal.add(+Calendar.DATE,+1+);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1654678|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>SimpleDateFormat dateFormat = new SimpleDateFormat( "yyyy-MM-dd" );
Calendar cal = Calendar.getInstance();
cal.setTime( dateFormat.parse( inputString ) );
cal.add( Calendar.DATE, 1 );
</code></pre>

blocks|key|1654656|text|构造一个日历对象并使用add(Calendar.DATE，1)方法；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1654657|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Construct a Calendar object and use the method add(Calendar.DATE, 1);

blocks|key|1439998|text|看看Joda-Time+(https://www.joda.org/joda-time/)。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1439999|DateTimeFormatter+parser+=+ISODateTimeFormat.date();

DateTime+date+=+parser.parseDateTime(dateString);

String+nextDay+=+parser.print(date.plusDays(1));|code-block|syntax|javascript|1440000|entityMap|0|LINK|mutability|MUTABLE|url|https://www.joda.org/joda-time/^0|D|V|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Take a look at Joda-Time (<a href="https://www.joda.org/joda-time/" rel="noreferrer">https://www.joda.org/joda-time/</a>).

<pre><code>DateTimeFormatter parser = ISODateTimeFormat.date();

DateTime date = parser.parseDateTime(dateString);

String nextDay = parser.print(date.plusDays(1));
</code></pre>

blocks|key|1655402|text|Java8添加了一个用于处理日期和时间的新API。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1655403|在Java+8中，您可以使用以下代码行：|1655404|//+parse+date+from+yyyy-mm-dd+pattern
LocalDate+januaryFirst+=+LocalDate.parse("2014-01-01");

//+add+one+day
LocalDate+januarySecond+=+januaryFirst.plusDays(1);|code-block|syntax|javascript|1655405|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Java 8 added a new API for working with dates and times.

With Java 8 you can use the following lines of code:

<pre><code>// parse date from yyyy-mm-dd pattern
LocalDate januaryFirst = LocalDate.parse("2014-01-01");

// add one day
LocalDate januarySecond = januaryFirst.plusDays(1);
</code></pre>

blocks|key|1440015|text|请注意，这一行增加了24小时：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1440016|d1.getTime()+%2B+1+*+24+*+60+*+60+*+1000|code-block|syntax|javascript|1440017|但这一行增加了一天|1440018|cal.add(+Calendar.DATE,+1+);|1440019|在夏令时改变(25或23小时)的日子里，你会得到不同的结果！|1440020|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Please note that this line adds 24 hours:

<pre><code>d1.getTime() + 1 * 24 * 60 * 60 * 1000
</code></pre>

but this line adds one day

<pre><code>cal.add( Calendar.DATE, 1 );
</code></pre>

On days with a daylight savings time change (25 or 23 hours) you will get different results!

blocks|key|1440885|text|您可以使用简单的java.util库|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1440886|Calendar+cal+=+Calendar.getInstance();+
cal.setTime(yourDate);+
cal.add(Calendar.DATE,+1);
yourDate+=+cal.getTime();|code-block|syntax|javascript|1440887|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

you can use Simple java.util lib

<pre><code>Calendar cal = Calendar.getInstance(); 
cal.setTime(yourDate); 
cal.add(Calendar.DATE, 1);
yourDate = cal.getTime();
</code></pre>

blocks|key|1654774|text|Date+today+=+new+Date();+++++++++++++++
SimpleDateFormat+formattedDate+=+new+SimpleDateFormat("yyyyMMdd");++++++++++++
Calendar+c+=+Calendar.getInstance();++++++++
c.add(Calendar.DATE,+1);++//+number+of+days+to+add++++++
String+tomorrow+=+(String)(formattedDate.format(c.getTime()));
System.out.println("Tomorrows+date+is+"+%2B+tomorrow);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1654775|这将给出明天的日期。可以将c.add(...)参数从1更改为另一个数字，以获得适当的增量。|unstyled|offset|length|style|CODE|1654776|entityMap^0|0|D|A|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>Date today = new Date(); 
SimpleDateFormat formattedDate = new SimpleDateFormat("yyyyMMdd"); 
Calendar c = Calendar.getInstance(); 
c.add(Calendar.DATE, 1); // number of days to add 
String tomorrow = (String)(formattedDate.format(c.getTime()));
System.out.println("Tomorrows date is " + tomorrow);
</code></pre>

This will give tomorrow's date. <code>c.add(...)</code> parameters could be changed from 1 to another number for appropriate increment.

blocks|key|1440830|text|long+timeadj+=+24*60*60*1000;
Date+newDate+=+new+Date+(oldDate.getTime+()%2Btimeadj);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1440831|这从oldDate获取了从epoch开始的毫秒数，然后加上1天的毫秒数，然后使用Date()公共构造函数使用新值创建一个日期。此方法允许您添加1天或任意数量的小时/分钟，而不仅仅是整天。|unstyled|1440832|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>long timeadj = 24*60*60*1000;
Date newDate = new Date (oldDate.getTime ()+timeadj);
</code></pre>

This takes the number of milliseconds since epoch from oldDate and adds 1 day worth of milliseconds then uses the Date() public constructor to create a date using the new value. This method allows you to add 1 day, or any number of hours/minutes, not only whole days.

blocks|key|1655701|text|在Java+8中，简单的方法是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1655702|Date.from(Instant.now().plusSeconds(SECONDS_PER_DAY))|code-block|syntax|javascript|1655703|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In Java 8 simple way to do is:

<pre><code>Date.from(Instant.now().plusSeconds(SECONDS_PER_DAY))
</code></pre>

blocks|key|1440979|text|这很简单，试着用一个简单的词来解释。如下所示获取今天的日期|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1440980|Calendar+calendar+=+Calendar.getInstance();
System.out.println(calendar.getTime());//+print+today's+date
calendar.add(Calendar.DATE,+1);|code-block|syntax|javascript|1440981|现在通过calendar.add方法将这个日期提前一天设置，该方法采用(常量，值)。这里的常量可以是日期、小时、分钟、秒等，值是常量的值。例如，对于一天，ahead常量是Calendar.DATE，它的值是1，因为我们想要提前一天的值。|1440982|System.out.println(calendar.getTime());//+print+modified+date+which+is明天的日期|offset|length|style|CODE|1440983|谢谢|1440984|entityMap^0|0|0|0|0|1Y|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|V|8|@$K|W|L|X|M|N]]|9|@]|A|$]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

It's very simple, trying to explain in a simple word.
get the today's date as below 

<pre><code>Calendar calendar = Calendar.getInstance();
System.out.println(calendar.getTime());// print today's date
calendar.add(Calendar.DATE, 1);
</code></pre>

Now set one day ahead with this date by calendar.add method which takes (constant, value). Here constant could be DATE, hours, min, sec etc. and value is the value of constant. Like for one day, ahead constant is Calendar.DATE and its value are 1 because we want one day ahead value.

<code>System.out.println(calendar.getTime());// print modified date which is</code> tomorrow's date

Thanks

blocks|key|1655713|text|startCalendar.add(Calendar.DATE,+1);+//Add+1+Day+to+the+current+Calender|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1655714|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>startCalendar.add(Calendar.DATE, 1); //Add 1 Day to the current Calender
</code></pre>

blocks|key|1655564|text|在java+8中，您可以使用java.time.LocalDate|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1655565|LocalDate+parsedDate+=+LocalDate.parse("2015-10-30");+//Parse+date+from+String
LocalDate+addedDate+=+parsedDate.plusDays(1);+++//Add+one+to+the+day+field|code-block|syntax|javascript|1655566|您可以按如下方式转换为java.util.Date对象。|1655567|Date+date+=+Date.from(addedDate.atStartOfDay(ZoneId.systemDefault()).toInstant());|1655568|您可以将LocalDate格式化为字符串，如下所示。|1655569|String+str+=+addedDate.format(DateTimeFormatter.ofPattern("yyyy-MM-dd"));|1655570|entityMap^0|E|J|0|0|B|E|0|0|4|9|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|12|8|@$9|13|A|14|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|T|$]]

In java 8 you can use <code>java.time.LocalDate</code>

<pre><code>LocalDate parsedDate = LocalDate.parse("2015-10-30"); //Parse date from String
LocalDate addedDate = parsedDate.plusDays(1); //Add one to the day field
</code></pre>

You can convert in into <code>java.util.Date</code> object as follows.

<pre><code>Date date = Date.from(addedDate.atStartOfDay(ZoneId.systemDefault()).toInstant());
</code></pre>

You can formate <code>LocalDate</code> into a String as follows.

<pre><code>String str = addedDate.format(DateTimeFormatter.ofPattern("yyyy-MM-dd"));
</code></pre>

blocks|key|1440066|text|Apache+Commons已经有了您可以使用的DateUtils.addDays(日期、日期、整数)+http://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/time/DateUtils.html#addDays%2528java.util.Date,%2520int%2529，或者您可以使用JodaTime使其更简洁。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1440067|entityMap|0|LINK|mutability|MUTABLE|url|http://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/time/DateUtils.html#addDays%2528java.util.Date,%2520int%2529^0|1G|3P|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

Apache Commons already has this DateUtils.addDays(Date date, int amount) <a href="http://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/time/DateUtils.html#addDays%28java.util.Date,%20int%29">http://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/time/DateUtils.html#addDays%28java.util.Date,%20int%29</a> which you use or you could go with the JodaTime to make it more cleaner.

blocks|key|1440801|text|只需在字符串中传递日期和接下来的天数|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1440802|+private+String+getNextDate(String+givenDate,int+noOfDays)+{
++++++++SimpleDateFormat+dateFormat+=+new+SimpleDateFormat("yyyy-MM-dd");
++++++++Calendar+cal+=+Calendar.getInstance();
++++++++String+nextDaysDate+=+null;
++++try+{
++++++++cal.setTime(dateFormat.parse(givenDate));
++++++++cal.add(Calendar.DATE,+noOfDays);

+++++++nextDaysDate+=+dateFormat.format(cal.getTime());

++++}+catch+(ParseException+ex)+{
++++++++Logger.getLogger(GR_TravelRepublic.class.getName()).log(Level.SEVERE,+null,+ex);
++++}finally{
++++dateFormat+=+null;
++++cal+=+null;
++++}

++++return+nextDaysDate;

}|code-block|syntax|javascript|1440803|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Just pass date in String and number of next days 

<pre><code> private String getNextDate(String givenDate,int noOfDays) {
 SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd");
 Calendar cal = Calendar.getInstance();
 String nextDaysDate = null;
 try {
 cal.setTime(dateFormat.parse(givenDate));
 cal.add(Calendar.DATE, noOfDays);

 nextDaysDate = dateFormat.format(cal.getTime());

 } catch (ParseException ex) {
 Logger.getLogger(GR_TravelRepublic.class.getName()).log(Level.SEVERE, null, ex);
 }finally{
 dateFormat = null;
 cal = null;
 }

 return nextDaysDate;

}
</code></pre>

blocks|key|1655504|text|如果要添加单个时间单位，且希望其他字段也递增，则可以安全地使用add方法。如下例所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1655505|SimpleDateFormat+simpleDateFormat1+=+new+SimpleDateFormat("yyyy-MM-dd");
Calendar+cal+=+Calendar.getInstance();
cal.set(1970,Calendar.DECEMBER,31);
System.out.println(simpleDateFormat1.format(cal.getTime()));
cal.add(Calendar.DATE,+1);
System.out.println(simpleDateFormat1.format(cal.getTime()));
cal.add(Calendar.DATE,+-1);
System.out.println(simpleDateFormat1.format(cal.getTime()));|code-block|syntax|javascript|1655506|将打印：|1655507|1970-12-31
1971-01-01
1970-12-31|1655508|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

If you want to add a single unit of time and you expect that other fields to be incremented as well, you can safely use add method. See example below:

<pre><code>SimpleDateFormat simpleDateFormat1 = new SimpleDateFormat("yyyy-MM-dd");
Calendar cal = Calendar.getInstance();
cal.set(1970,Calendar.DECEMBER,31);
System.out.println(simpleDateFormat1.format(cal.getTime()));
cal.add(Calendar.DATE, 1);
System.out.println(simpleDateFormat1.format(cal.getTime()));
cal.add(Calendar.DATE, -1);
System.out.println(simpleDateFormat1.format(cal.getTime()));
</code></pre>

Will Print:

<pre><code>1970-12-31
1971-01-01
1970-12-31
</code></pre>

blocks|key|1439949|text|使用DateFormat接口将字符串转换为Date对象，然后使用Calendar接口添加一天。如果您需要特定的代码示例，请让我知道，我可以更新我的答案。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1439950|entityMap|0|LINK|mutability|MUTABLE|url|http://java.sun.com/j2se/1.5.0/docs/api/java/text/DateFormat.html|1|http://java.sun.com/j2se/1.5.0/docs/api/java/util/Calendar.html^0|2|A|W|8|2|A|0|W|8|1|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]|$9|S|A|T|B|C]]|D|@$9|U|A|V|1|W]|$9|X|A|Y|1|Z]]|E|$]]|$1|F|3|-4|5|6|7|10|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]|N|$5|I|J|K|E|$L|O]]]]

Use the <a href="http://java.sun.com/j2se/1.5.0/docs/api/java/text/DateFormat.html" rel="noreferrer"><code>DateFormat</code></a> API to convert the String into a Date object, then use the <a href="http://java.sun.com/j2se/1.5.0/docs/api/java/util/Calendar.html" rel="noreferrer"><code>Calendar</code></a> API to add one day. Let me know if you want specific code examples, and I can update my answer.

blocks|key|1655765|text|尝试以下方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1655766|public+static+Date+addDay(int+day)+{
++++++++Calendar+calendar+=+Calendar.getInstance();
++++++++calendar.setTime(new+Date());
++++++++calendar.add(Calendar.DATE,+day);
++++++++return+calendar.getTime();
}|code-block|syntax|javascript|1655767|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this method:
<pre><code>public static Date addDay(int day) {
 Calendar calendar = Calendar.getInstance();
 calendar.setTime(new Date());
 calendar.add(Calendar.DATE, day);
 return calendar.getTime();
}
</code></pre>

blocks|key|1441085|text|实际上，这很简单。一天包含86400000个milliSeconds。因此，首先使用System.currentTimeMillis()从系统获取当前时间(以毫秒为单位)，然后添加84000000+milliseconds，并使用Date类生成以毫秒为单位的日期格式。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1441086|示例|1441087|String+Today+=+new+Date(System.currentTimeMillis()).toString();|1441088|String+Today将为2019-05-9|1441089|String+Tommorow+=+new+Date(System.currentTimeMillis()+%2B+86400000).toString();|1441090|String+Tommorow将为2019-05-10|1441091|String+DayAfterTommorow+=+new+Date(System.currentTimeMillis()+%2B+(2+*+86400000)).toString();|1441092|String+DayAfterTommorow为2019-05-11|1441093|entityMap^0|16|Q|37|4|0|0|0|1R|0|0|0|25|0|0|0|2J|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@$9|W|A|X|B|C]|$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|10|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|14|8|@]|D|@]|E|$]]|$1|L|3|M|5|6|7|15|8|@$9|16|A|17|B|C]]|D|@]|E|$]]|$1|N|3|O|5|6|7|18|8|@]|D|@]|E|$]]|$1|P|3|Q|5|6|7|19|8|@$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|R|3|S|5|6|7|1C|8|@]|D|@]|E|$]]|$1|T|3|-4|5|6|7|1D|8|@]|D|@]|E|$]]]|U|$]]

It's simple actually.
One day contains 86400000 milliSeconds. 
So first you get the current time in millis from The System by using<code>System.currentTimeMillis()</code> then
add the 84000000 milliSeconds and use the <code>Date</code> Class to generate A date format for the milliseconds.

Example 

<code>String Today = new Date(System.currentTimeMillis()).toString();</code>

String Today will be 2019-05-9 

<code>String Tommorow = new Date(System.currentTimeMillis() + 86400000).toString();</code>

String Tommorow will be 2019-05-10

<code>String DayAfterTommorow = new Date(System.currentTimeMillis() + (2 * 86400000)).toString();</code>

String DayAfterTommorow will be 2019-05-11

blocks|key|1441024|text|您可以使用“org.apache.commons.lang3.time”中的包：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1441025|+SimpleDateFormat+sdf+=+new+SimpleDateFormat("yyyy-MM-dd");
+Date+myNewDate+=+DateUtils.addDays(myDate,+4);
+Date+yesterday+=+DateUtils.addDays(myDate,+-1);
+String+formatedDate+=+sdf.format(myNewDate);++|code-block|syntax|javascript|1441026|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use this package from "org.apache.commons.lang3.time":

<pre><code> SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
 Date myNewDate = DateUtils.addDays(myDate, 4);
 Date yesterday = DateUtils.addDays(myDate, -1);
 String formatedDate = sdf.format(myNewDate); 
</code></pre>

blocks|key|1440963|text|如果您使用的是Java8，那么java.time.LocalDate和java.time.format.DateTimeFormatter可以让这项工作变得非常简单。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1440964|public+String+nextDate(String+date){
++++++LocalDate+parsedDate+=+LocalDate.parse(date);
++++++LocalDate+addedDate+=+parsedDate.plusDays(1);
++++++DateTimeFormatter+formatter+=+DateTimeFormatter.ofPattern("yyyy-mm-dd");
++++++return+addedDate.format(formatter);+
}|code-block|syntax|javascript|1440965|entityMap^0|F|J|Z|Y|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

If you are using Java 8, <code>java.time.LocalDate</code> and <code>java.time.format.DateTimeFormatter</code> can make this work quite simple.

<pre><code>public String nextDate(String date){
 LocalDate parsedDate = LocalDate.parse(date);
 LocalDate addedDate = parsedDate.plusDays(1);
 DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-mm-dd");
 return addedDate.format(formatter); 
}
</code></pre>

blocks|key|1441148|text|您只需一行代码即可完成此操作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1441149|例如，增加5天|1441150|Date+newDate+=+Date.from(Date().toInstant().plus(5,+ChronoUnit.DAYS));|code-block|syntax|javascript|1441151|减去5天|1441152|Date+newDate+=+Date.from(Date().toInstant().minus(5,+ChronoUnit.DAYS));|1441153|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

You can do this just in one line.
e.g to add 5 days
<pre><code>Date newDate = Date.from(Date().toInstant().plus(5, ChronoUnit.DAYS));
</code></pre>
to subtract 5 days
<pre><code>Date newDate = Date.from(Date().toInstant().minus(5, ChronoUnit.DAYS));
</code></pre>

blocks|key|1440049|text|Date+newDate+=+new+Date();
newDate.setDate(newDate.getDate()%2B1);
System.out.println(newDate);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1440050|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>Date newDate = new Date();
newDate.setDate(newDate.getDate()+1);
System.out.println(newDate);
</code></pre>

blocks|key|1655784|text|我认为最快的是永远不会被弃用的，它是最核心的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1655785|let+d=new+Date();
d.setTime(d.getTime()%2B86400000);
console.log(d);|code-block|syntax|javascript|1655786|它只有一行，只有两个命令。它在日期类型上工作，而不使用日历。|1655787|我总是认为在代码端使用unix时间会更好，并在准备好向用户显示的时候显示日期。|1655788|要打印日期d，我使用|1655789|let+format1+=+new+Intl.DateTimeFormat('en',+{+year:+'numeric',+month:+'numeric',+month:+'2-digit',+day:+'2-digit'});
let+[{+value:+month+},,{+value:+day+},,{+value:+year+}]+=+format1.formatToParts(d);|1655790|它设置var、月、年和日，但可以扩展到小时、分钟和秒，并且还可以根据国家标志在标准的rapresentations中使用。|1655791|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|V|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|W|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

I think the fastest one, that never will be deprecated, it's the one that go to the core
<pre><code>let d=new Date();
d.setTime(d.getTime()+86400000);
console.log(d);
</code></pre>
It's just one line,
and just 2 commands.
It works on Date type, without using calendar.
I always think it's better to work with unix times on code side, and present the date just when it's ready to be shown to the user.
To print a date d, I use
<pre><code>let format1 = new Intl.DateTimeFormat('en', { year: 'numeric', month: 'numeric', month: '2-digit', day: '2-digit'});
let [{ value: month },,{ value: day },,{ value: year }] = format1.formatToParts(d);
</code></pre>
It sets vars month year and day but can be extended to hours minutes and seconds and can be used also in standard rapresentations depending on country flag.

I'm working with a date in this format: <code>yyyy-mm-dd</code>.

How can I increment this date by one day?

How can I increment a date by one day in Java?

我正在使用以下格式的日期：yyyy-mm-dd。如何将此日期增加一天？

问如何在Java中将日期增加一天？
EN

回答 26

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