下面是对象的示例数组。我希望在criteriaType
,id
和source
的基础上过滤这个。如果没有匹配的input.source
,父对象应该被过滤掉。此外,所有过滤条件都是可选的。
[{
"id": "9be6c6299cca48f597fe71bc99c37b2f",
"caption": "caption1",
"criteriaType": "type2",
"input": [
{
"id_1": "66be4486ffd3431eb60e6ea6326158fe",
"criteriaId": "9be6c6299cca48f597fe71bc99c37b2f",
"source": "type1",
},
{
"id_1": "1ecdf410b3314865be2b52ca9b4c8539",
"criteriaId": "9be6c6299cca48f597fe71bc99c37b2f",
"source": "type2",
}
]
},
{
"id": "b83b3f081a7b45e087183740b12faf3a",
"caption": "caption1",
"criteriaType": "type1",
"input": [
{
"id_1": "f46da7ffa859425e922bdbb701cfcf88",
"criteriaId": "b83b3f081a7b45e087183740b12faf3a",
"source": "type3",
},
{
"id_1": "abb87219db254d108a1e0f774f88dfb6",
"criteriaId": "b83b3f081a7b45e087183740b12faf3a",
"source": "type1",
}
]
},
{
"id": "fe5b071a2d8a4a9da61bbd81b9271e31",
"caption": "caption1",
"criteriaType": "type1",
"input": [
{
"id_1": "7ea1b85e4dbc44e8b37d1110b565a081",
"criteriaId": "fe5b071a2d8a4a9da61bbd81b9271e31",
"source": "type3",
},
{
"id_1": "c5f943b61f674265b8237bb560cbed03",
"criteriaId": "fe5b071a2d8a4a9da61bbd81b9271e31",
"source": "type3",
}
]
}]
我能够实现仅按criteriaType
& id
过滤。但是,如果没有匹配的input.source,我也不能通过source
过滤来确保不返回父级。
var json = <<array of objects>> ;
const {objectId: id, ctype: criteriaType, inputSource: source } = param; // getting the the params
json = ctype ? json.filter(({criteriaType}) => criteriaType === ctype ): json;
json = (objectId ? json.filter(({id}) => id === objectId ): json)
.map (({id, caption, criteriaType, input }) => {
//some manipulation
return { //results after manipulation}
})
帮帮我!提前谢谢。我不确定我们是否可以用链式过滤器来实现它。
寻找与esLint兼容的代码
https://stackoverflow.com/questions/51528469
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