Python 2.7返回值和添加函数
Python 2.7返回值和添加函数
提问于 2018-06-20 04:00:41
以下是打印和计算加权考试成绩的代码：
def exam(weight,score_earned,score_shift):
if (score_shift==1):
shift_amount=input("What was the shift amount?")
score_earned=int(shift_amount+score_earned)
if (score_earned >100):
score_earned=100
print("Total points = "+str(score_earned)+str("/100"))
weighted_score=int((score_earned/100.0)*weight)
print("Your weighted score = "+str(weighted_score)+"/"+str(weight))
return weighted_score
def exam_1():
print("Midterm 1:")
exam(input("Weight 0-100?"),input("Score earned?"),input("Were scores shifted (1= yes 2=no)? "))def exam_2():
print("\nMidterm 2:")
exam(input("Weight 0-100? "),input("Score earned? "),input("Were scores shifted (1= yes 2=no)? "))overall_percentage =int(exam_1() +exam_2())我希望代码使用返回的weighted_score将加权分数相加在一起。尽管如此，当我运行代码时，它给出了这个错误：
TypeError: unsupported operand type(s) for +: 'NoneType' and 'NoneType'我该如何解决这个问题？
这也是一个示例输出--除了overall_percentage之外，所有的东西都可以工作，因为它让我认为我的返回语句出了问题：
Midterm 1:
Weight 0-100? 50
Score earned? 88
Were scores shifted (1= yes 2=no)? 2
Total points = 88/100
Your weighted score = 44/50
Midterm 2:
Weight 0-100? 50
Score earned? 88
Were scores shifted (1= yes 2=no)? 2
Total points = 88/100
Your weighted score = 44/50回答 1
Stack Overflow用户
发布于 2018-06-20 04:04:08
您的函数exam_1和exam_2不返回任何内容(= None )。
这就是为什么exam_1() + exam_2()会导致None + None并抛出您所看到的异常：
TypeError：+：'NoneType‘和'NoneType’不支持的操作数类型
你可以很容易地解决这个问题：
def exam_1():
print("Midterm 1:")
return exam( ...和
def exam_2():
print("\nMidterm 2:")
return exam( ...页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50936077
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