需要帮助从列表中提取数据模式，如下所示
需要帮助从列表中提取数据模式，如下所示
提问于 2018-07-23 20:24:29
我有如下所示的数据示例，我想提取具有如下键/值模式的数据：
'Signature Algorithm: ecdsa-with-SHA256', 'Not Before: Jul 23 00:00:00 2018 GMT', 'Not After : Jul 19 00:00:00 2033 GMT, 'Public Key Algorithm: id-ecPublicKeyid', Public-Key: (256 bit)' 示例：
['Certificate:', 'Data:', 'Version: 3 (0x2)', 'Serial Number:', 'b9:d9:f5:38:f8:42:6a:f9', 'Signature Algorithm: ecdsa-with-SHA256', 'Issuer: C=US, ST=NC, L=Raleigh, O=Eaton Corporation, OU=Electrical Division, CN=PowerXpert-02-00-34-56-63-01', 'Validity', 'Not Before: Jul 23 00:00:00 2018 GMT', 'Not After : Jul 19 00:00:00 2033 GMT', 'Subject: C=US, ST=NC, L=Raleigh, O=Eaton Corporation, OU=Electrical Division, CN=PowerXpert-02-00-34-56-63-01', 'Subject Public Key Info:', 'Public Key Algorithm: id-ecPublicKey', 'Public-Key: (256 bit)', 'pub:', '04:bf:72:4b:01:8b:5c:46:98:96:a6:d6:06:7b:d8:', '73:50:2f:47:85:60:f0:38:25:79:3d:96:be:20:3b:', '3f:39:c8:58:62:e9:d7:b6:f8:3a:6b:24:50:e1:5c:', '78:ce:5e:28:f2:60:3a:b6:cc:43:0e:0b:2b:d6:03:', '51:76:21:a4:78', 'ASN1 OID: prime256v1', 'NIST CURVE: P-256', 'X509v3 extensions:', 'X509v3 Subject Key Identifier:', '6A:E0:28:A7:17:2B:65:01:FD:31:48:5C:68:24:94:4B:42:49:76:58', 'X509v3 Basic Constraints: critical', 'CA:TRUE', 'X509v3 Key Usage: critical', 'Digital Signature, Certificate Sign, CRL Sign', 'X509v3 Subject Alternative Name:', 'DNS:PXG900-56-63-01', 'Signature Algorithm: ecdsa-with-SHA256', '30:45:02:20:43:33:58:ce:ef:f7:fd:a8:60:21:15:a3:2b:35:', '8c:1f:13:a0:1e:77:05:6f:1a:bb:a0:b6:fe:f3:ea:7b:6d:31:', '02:21:00:cf:db:9a:d1:6b:88:ae:fb:d5:5c:5a:db:0a:a0:eb:', 'a9:c9:4a:52:d0:57:18:9c:58:1b:67:42:47:c5:ec:bf:b0', '', '']使用下面的正则表达式，但没有得到想要的结果
regex = re.compile(r'''
[\S]+: # a key (any word followed by a colon)
(?:
\s # then a space in between
(?!\S+:)\S+ # then a value (any word not followed by a colon)
)+ # match multiple values if present
''', re.VERBOSE)
matches = regex.findall(str(lines))
print(matches)回答 3
Stack Overflow用户
回答已采纳
发布于 2018-07-23 20:35:14
我不确定我是否完全明白。但你就不能说：
extracted = []
for item in lines:
if len(item.split(": ")) == 2: # It has 2 items
extracted.append(item)这将提取在"：“两边都有"stuff”的每一项。我希望这能帮到你。
Stack Overflow用户
发布于 2018-07-23 21:18:52
Stack Overflow用户
发布于 2018-07-24 16:50:20
re.findall("'[A-Z][^':]+:[^',:]+(?:\d{2}:){0,3}[^',:]+'(?=,)",str(lines))
Out[139]:
["'Version: 3 (0x2)'",
"'Signature Algorithm: ecdsa-with-SHA256'",
"'Not Before: Jul 23 00:00:00 2018 GMT'",
"'Not After : Jul 19 00:00:00 2033 GMT'",
"'Public Key Algorithm: id-ecPublicKey'",
"'Public-Key: (256 bit)'",
"'ASN1 OID: prime256v1'",
"'NIST CURVE: P-256'",
"'X509v3 Basic Constraints: critical'",
"'CA:TRUE'",
"'X509v3 Key Usage: critical'",
"'DNS:PXG900-56-63-01'",
"'Signature Algorithm: ecdsa-with-SHA256'"]页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/51478730
复制相关文章
相似问题
腾讯云开发者
