如何使用2个连接执行"FOR JSON“
如何使用2个连接执行"FOR JSON“
提问于 2017-03-29 21:03:15
我不能让它正常工作。我有4个表:产品，供应商，X_Product_Suppliers和评论。我想要查询它们，并使用以下查询将它们放到JSON中：
WITH Products (Id, Name, Price) As (
SELECT 1, 'First Product', 10
), Suppliers (Id, Name) As (
SELECT 1, 'Factory1' UNION ALL
SELECT 2, 'Factory2'
), Comments (Id, [Text], ProductId) As (
SELECT 1, 'Good Product', 1 UNION ALL
SELECT 2, 'Fantastic!' , 1
), X_Product_Supplier (ProductId, SupplierId) As (
SELECT 1, 1 UNION ALL
SELECT 1, 2
)
SELECT Products.*, Suppliers.*, Comments.* FROM Products
LEFT OUTER JOIN X_Product_Supplier ON X_Product_Supplier.ProductId = Products.Id
LEFT OUTER JOIN Suppliers ON X_Product_Supplier.SupplierId = Suppliers.Id
LEFT OUTER JOIN Comments ON Comments.ProductId = Products.Id
FOR JSON AUTO由于某种原因，sql-server会将注释嵌套在供应商下，而不是产品下：
{
"Id":1,
"Name":"First Product",
"Price":"10",
"Suppliers":[
{
"Id":1,
"Name":"Factory1",
"Comments":[ //THIS SHOULD BE UNDER PRODUCT, NOT SUPPLIER
{
"Id":1,
"Text":"Good Product",
"ProductId":1
},
{
"Id":2,
"Text":"Fantastic!",
"ProductId":1
}
]
},
{
"Id":2,
"Name":"Factory2",
"Comments":[ //THIS IS NOW DUPLICATE
{
"Id":1,
"Text":"Good Product",
"ProductId":1
},
{
"Id":2,
"Text":"Fantastic!",
"ProductId":1
}
]
}
]
}我真正想要的是：
{
"Id":1,
"Name":"First Product",
"Price":"10",
"Suppliers":[
{
"Id":1,
"Name":"Factory1"
},
{
"Id":2,
"Name":"Factory2"
}
],
"Comments":[
{
"Id":1,
"Text":"Good Product",
"ProductId":1
},
{
"Id":2,
"Text":"Fantastic!",
"ProductId":1
}
]
}我该怎么做呢？
回答 2
Stack Overflow用户
发布于 2018-07-26 08:02:13
如果其他人正在寻找答案，这里是我写的简单的查询。根据您的模式更改查询，它应该会给出适当的结构化结果。
SELECT Products.*,
(SELECT Suppliers.*
FROM Suppliers
WHERE Suppliers.Id = Products.SuppliersId
FOR JSON AUTO) As Suppliers,
(SELECT Comments.*
FROM Comments
WHERE Comments.ProductId = Products.Id
FOR JSON AUTO) As Comments
FROM Products
FOR JSON AUTOStack Overflow用户
发布于 2019-06-17 01:19:01
我知道已经很晚了，但是我遇到了同样的问题，但是答案不能帮助过滤where子句中的空值，我的解决方案如下
SELECT Products.*,
Suppliers.Id as [Suppliers.Id],
Suppliers.Name as [Suppliers.Name],
Comments.Id as [Comments.Id],
Comments.Text as [Comments.Text],
Comments.ProductId as [Comments.ProductId]
FROM Products
LEFT OUTER JOIN X_Product_Supplier ON X_Product_Supplier.ProductId = Products.Id
LEFT OUTER JOIN Suppliers ON X_Product_Supplier.SupplierId = Suppliers.Id
LEFT OUTER JOIN Comments ON Comments.ProductId = Products.Id
FOR JSON PATH 在SQL SERVER 2017上测试和工作
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/43094351
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