Python如何忽略或修复"IndexError: list index out of range"？
Python如何忽略或修复"IndexError: list index out of range"？
提问于 2018-06-24 00:19:13
因此，这个结果有时可能会有不到10个答案。如果'overbought1‘小于10，我很难弄清楚如何忽略它。例如，如果只有8个结果，我希望它显示8，忽略不存在的最后两个结果。
try:
for i in range(10):
(runo[i])
except:
pass
overbought1 = ("Top 10 overbought today: $" + runo[0] + " $" + runo[1] + " $" + runo[2] + " $" + runo[3] + " $" +runo[4] + " $" + runo[5] + " $" + runo[6] + " $" + runo[7]+ " $" + runo[8]+ " $" + runo[9])
await client.say(overbought1)回答 1
Stack Overflow用户
发布于 2018-06-24 04:57:12
尽管您的整个示例意义不大，但以下是避免使用IndexError的方法之一
for i in range(min(10, len(runo))): # loop at most to the minimum
# between ten and len(runo)
(runo[i]) # <-- this does nothing here!另一种方式：
for v in runo[:10]: # access no more than first 10 elements
v # <-- also does nothing. v is equivalent to runo[i] from the previous loop现在，如果您想修复overbought1字符串，请执行以下操作：
overbought1 = "Top 10 overbought today: $" + " $".join(runo[:10])或者甚至是：
overbought1 = ("Top %d overbought today: $" % len(runo)) + " $".join(runo[:10])页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/51002971
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