如何从列表中创建带有名称的新变量?这一点:
name = ['mike', 'john', 'steve']
age = [20, 32, 19]
index = 0
for e in name:
name[index] = age[index]
index = index+1
当然不起作用。我该怎么办?
我想这样做:
print mike
>>> 20
print steve
>>> 19
发布于 2012-07-04 06:14:00
我认为dictionaries
更适合用于此目的:
>>> name = ['mike', 'john', 'steve']
>>> age = [20, 32, 19]
>>> dic=dict(zip(name, age))
>>> dic['mike']
20
>>> dic['john']
32
但是,如果您仍然希望动态创建变量,则可以使用globals()[]
>>> for x,y in zip(name, age):
globals()[x] = y
>>> mike
20
>>> steve
19
>>> john
32
发布于 2018-06-29 04:51:20
name = ['mike', 'john', 'steve']
age = [20, 32, 19]
for i in range(len(name)):
exec("%s = %d" %(name[i], age[i]))
print(mike)
print(john)
print(steve)
发布于 2019-06-09 17:34:56
字典是最好的选择!
import pandas as pd
import datetime
import pandas_datareader as dr
# Get data for this year, so far
start = datetime.datetime(2019,1,1)
end = datetime.datetime(2019,6,1)
companies = ['AA', 'AAPL', 'BA', 'IBM']
df_dict = {}
for name in companies:
df_dict[name] = pd.DataFrame()
df_dict[name] = dr.data.get_data_yahoo(name, start, end)
print()
print(' Apple dataframe ')
print(df_dict['AAPL'].head())
https://stackoverflow.com/questions/11319909
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