blocks|key|63602|text|我认为这会更清晰一些，你不需要处理减法和索引：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|63603|char[]+alphabet+=+"abcdefghijklmnopqrstuvwxyz".toCharArray();|code-block|syntax|javascript|63604|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I think that this ends up a little cleaner, you don't have to deal with the subtraction and indexing:

<pre><code>char[] alphabet = "abcdefghijklmnopqrstuvwxyz".toCharArray();
</code></pre>

blocks|key|63615|text|char[]+alphabet+=+{'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|63616|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>char[] alphabet = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
</code></pre>

blocks|key|279985|text|这是一个有趣的Unicode解决方案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|279986|char[]+alpha+=+new+char[26]
for(int+i+=+0;+i+<+26;+i%2B%2B){
++++alpha[i]+=+(char)(97+%2B+i)
}|code-block|syntax|javascript|279987|这会生成一个字母表的小写版本，如果你想要大写，你可以用'65‘替换'97’。|279988|希望这能有所帮助。|279989|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

This is a fun Unicode solution.

<pre><code>char[] alpha = new char[26]
for(int i = 0; i &lt; 26; i++){
 alpha[i] = (char)(97 + i)
}
</code></pre>

This generates a lower-cased version of alphabet, if you want upper-cased, you can replace '97' with '65'.

Hope this helps.

blocks|key|280116|text|在带有Stream+API的Java+8中，您可以做到这一点。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|280117|IntStream.rangeClosed('A',+'Z').mapToObj(var+->+(char)+var).forEach(System.out::println);|code-block|syntax|javascript|280118|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In Java 8 with Stream API, you can do this.

<pre><code>IntStream.rangeClosed('A', 'Z').mapToObj(var -&gt; (char) var).forEach(System.out::println);
</code></pre>

blocks|key|280070|text|如果您使用的是Java+8|type|unstyled|depth|inlineStyleRanges|entityRanges|data|280071|char[]+charArray+=+IntStream.rangeClosed('A',+'Z')
++++.mapToObj(c+->+""+%2B+(char)+c).collect(Collectors.joining()).toCharArray();|code-block|syntax|javascript|280072|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you are using Java 8 

<pre><code>char[] charArray = IntStream.rangeClosed('A', 'Z')
 .mapToObj(c -&gt; "" + (char) c).collect(Collectors.joining()).toCharArray();
</code></pre>

blocks|key|63786|text|static+String[]+AlphabetWithDigits+=+{"0",+"1",+"2",+"3",+"4",+"5",+"6",+"7",+"8",+"9",+"A",+"B",+"C",+"D",+"E",+"F",+"G",+"H",+"I",+"J",+"K",+"L",+"M",+"N",+"O",+"P",+"Q",+"R",+"S",+"T",+"U",+"V",+"W",+"X",+"Y",+"Z",+"a",+"b",+"c",+"d",+"e",+"f",+"g",+"h",+"i",+"j",+"k",+"l",+"m",+"n",+"o",+"p",+"q",+"r",+"s",+"t",+"u",+"v",+"w",+"x",+"y",+"z"};|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|63787|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>static String[] AlphabetWithDigits = {"0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z", "a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"};
</code></pre>

blocks|key|280044|text|检查一下，我确信你会将a转换成z字母表：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|280045|for+(char+c+=+'a';+c+<=+'z';+c%2B%2B)+{
++++al.add(c);
}
System.out.println(al);'|code-block|syntax|javascript|280046|entityMap^0|B|1|F|1|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

Check this once I'm sure you will get <code>a</code> to <code>z</code> alphabets:

<pre><code>for (char c = 'a'; c &lt;= 'z'; c++) {
 al.add(c);
}
System.out.println(al);'
</code></pre>

blocks|key|63869|text|使用io.vavr|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|63870|public+static+char[]+alphanumericAlphabet()+{
++++return+CharSeq
++++++++++++.rangeClosed('0','9')
++++++++++++.appendAll(CharSeq.rangeClosed('a','z'))
++++++++++++.appendAll(CharSeq.rangeClosed('A','Z'))
++++++++++++.toCharArray();
}|code-block|syntax|javascript|63871|entityMap|0|LINK|mutability|MUTABLE|url|http://www.vavr.io/^0|2|7|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

with <a href="http://www.vavr.io/" rel="nofollow noreferrer">io.vavr</a>

<pre><code>public static char[] alphanumericAlphabet() {
 return CharSeq
 .rangeClosed('0','9')
 .appendAll(CharSeq.rangeClosed('a','z'))
 .appendAll(CharSeq.rangeClosed('A','Z'))
 .toCharArray();
}
</code></pre>

blocks|key|280253|text|简单是一种美德。使用这个自然可读的数组：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|280254|char+alphabet[]+=+{'a',+'b',+'c',+'d',+'e',+'f',+'g',+'h',+'i',+'j',+'k',+'l',+'m',+'n',+'o',+'p',+'q',+'r',+'s',+'t',+'u',+'v',+'w',+'x',+'y',+'z'};|code-block|syntax|javascript|280255|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Simplicity is a virtue. Use this naturally readable array:
<pre><code>char alphabet[] = {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'};
</code></pre>

blocks|key|64014|text|对于寻找Kotlin解决方案的Android开发人员，请在此处结束：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|64015|//+Creates+List<Char>
val+chars1+=+('a'..'z').toList()|code-block|syntax|javascript|64016|//+Creates+Array<Char>+(boxed)
val+chars2+=+('a'..'z').toList().toTypedArray()|64017|//+Creates+CharArray+(unboxed)
val+chars3+=+CharArray(26)+{+'a'+%2B+it+}|64018|//+Creates+CharArray+(unboxed)
val+chars4+=+('a'..'z').toArray()
fun+CharRange.toArray()+=+CharArray(count())+{+'a'+%2B+it+}|64019|要了解我所说的“已装箱”和“未装箱”是什么意思，请参见this+post。|offset|length|64020|非常感谢this+Kotlin+discussion+thread。|64021|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/q/45090808/8583692|1|https://discuss.kotlinlang.org/t/arrays-from-ranges/5216^0|0|0|0|0|0|R|9|0|0|4|T|1|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|I|3|J|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|D|7|16|8|@]|9|@]|A|$E|F]]|$1|M|3|N|5|6|7|17|8|@]|9|@$O|18|P|19|1|1A]]|A|$]]|$1|Q|3|R|5|6|7|1B|8|@]|9|@$O|1C|P|1D|1|1E]]|A|$]]|$1|S|3|-4|5|6|7|1F|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z]]|10|$5|V|W|X|A|$Y|11]]]]

For Android developers searching for a Kotlin solution and ending up here:
<pre class="lang-kotlin prettyprint-override"><code>// Creates List&lt;Char&gt;
val chars1 = ('a'..'z').toList()
</code></pre>
<pre class="lang-kotlin prettyprint-override"><code>// Creates Array&lt;Char&gt; (boxed)
val chars2 = ('a'..'z').toList().toTypedArray()
</code></pre>
<pre class="lang-kotlin prettyprint-override"><code>// Creates CharArray (unboxed)
val chars3 = CharArray(26) { 'a' + it }
</code></pre>
<pre class="lang-kotlin prettyprint-override"><code>// Creates CharArray (unboxed)
val chars4 = ('a'..'z').toArray()
fun CharRange.toArray() = CharArray(count()) { 'a' + it }
</code></pre>
To see what I mean by &quot;boxed&quot; and &quot;unboxed&quot; see <a href="https://stackoverflow.com/q/45090808/8583692" title="IntArray vs Array&lt;Int&gt; in Kotlin">this post</a>. 
Many thanks to <a href="https://discuss.kotlinlang.org/t/arrays-from-ranges/5216" rel="nofollow noreferrer" title="Arrays from Ranges">this Kotlin discussion thread</a>.

blocks|key|280096|text|char[]+abc+=+new+char[26];

for(int+i+=+0;+i<26;i%2B%2B)+{
++++abc[i]+=+(char)('a'%2Bi);
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|280097|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

blocks|key|280167|text|使用Java+8+streams|type|unstyled|depth|inlineStyleRanges|entityRanges|data|280168|++char+[]+alphabets+=+Stream.iterate('a'+,+x+->+(char)(x+%2B+1))
++++++++++++.limit(26)
++++++++++++.map(c+->+c.toString())
++++++++++++.reduce("",+(u+,+v)+->+u+%2B+v).toCharArray();|code-block|syntax|javascript|280169|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Using Java 8 streams

<pre><code> char [] alphabets = Stream.iterate('a' , x -&gt; (char)(x + 1))
 .limit(26)
 .map(c -&gt; c.toString())
 .reduce("", (u , v) -&gt; u + v).toCharArray();
</code></pre>

blocks|key|280223|text|要获得除小写字母之外的大写字母，还可以执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|280224|String+alphabetWithUpper+=+"abcdefghijklmnopqrstuvwxyz"+%2B+"abcdefghijklmnopqrstuvwxyz".toUpperCase();
char[]+letters+=+alphabetWithUpper.toCharArray();|code-block|syntax|javascript|280225|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To get uppercase letters in addition to lower case letters, you could also do the following:

<pre><code>String alphabetWithUpper = "abcdefghijklmnopqrstuvwxyz" + "abcdefghijklmnopqrstuvwxyz".toUpperCase();
char[] letters = alphabetWithUpper.toCharArray();
</code></pre>

blocks|key|63989|text|在kotlin中，您可以做到这一点|type|unstyled|depth|inlineStyleRanges|entityRanges|data|63990|var+alphabet+=+"abcdefghijklmnopqrstuvwxyz".toCharArray()|code-block|syntax|javascript|63991|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In kotlin you can do this
<pre><code>var alphabet = &quot;abcdefghijklmnopqrstuvwxyz&quot;.toCharArray()
</code></pre>

blocks|key|280337|text|const+alphabetArray+=+"abcdefghijklmnopqrstuvwxyz".split("");|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|280338|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>const alphabetArray = &quot;abcdefghijklmnopqrstuvwxyz&quot;.split(&quot;&quot;);
</code></pre>

blocks|key|63715|text|import+java.util.*;
public+class+Experiments{


List+uptoChar(int+i){
+++++++char+c='a';+
++++++++List+list+=+new+LinkedList();
+++++++++for(;;)+{
+++++++++++list.add(c);
+++++++if(list.size()==i){
+++++++++++++break;
+++++++++++}
+++++++c%2B%2B;
++++++++++++}
++++++++return+list;
++++++}+

++++public+static+void+main+(String+[]+args)+{

++++++++Experiments+experiments+=+new+Experiments();
++++++++++System.out.println(experiments.uptoChar(26));
++++}+|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|63716|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import java.util.*;
public class Experiments{


List uptoChar(int i){
 char c='a'; 
 List list = new LinkedList();
 for(;;) {
 list.add(c);
 if(list.size()==i){
 break;
 }
 c++;
 }
 return list;
 } 

 public static void main (String [] args) {

 Experiments experiments = new Experiments();
 System.out.println(experiments.uptoChar(26));
 } 
</code></pre>

blocks|key|63620|text|for+(char+letter+=+'a';+letter+<=+'z';+letter%2B%2B)
{
++++System.out.println(letter);
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|63621|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>for (char letter = 'a'; letter &lt;= 'z'; letter++)
{
 System.out.println(letter);
}
</code></pre>

Right now I'm doing

<pre><code>for (char c = 'a'; c &lt;= 'z'; c++) {
 alphabet[c - 'a'] = c;
}
</code></pre>

but is there a better way to do it? Similar to Scala's <code>'a' to 'z'</code>

Better way to generate array of all letters in the alphabet

Android

Kotlin

Java

现在我正在做的是for (char c = 'a'; c <= 'z'; c++) { alphabet[c - 'a'] = c;}但是有没有更好的方法呢？类似于Scala的'a' to 'z'

问生成字母表中所有字母数组的更好方法
EN

回答 17

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问生成字母表中所有字母数组的更好方法EN

回答 17

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问生成字母表中所有字母数组的更好方法
EN