我是python的新手,所以我不能完全理解如何使用循环。我目前正在编写一段代码,我必须找到前N个质数。期望的结果是,如果你输入5,它输出2,3,5,7和11,但无论我输入什么'max',输出总是2和3。有什么方法可以改善这一点吗?
max=int(input("How many prime numbers do you want: "))
min=2
while(min<=(max)):
for c in range(2, min):
if min%c==0:
break
else:
print min
min=min+1
发布于 2018-07-01 02:23:07
您只需在else
块中递增min
,即,如果所有c
的min % c
都不为零,即,如果min
是质数。这意味着代码将不能超过任何组合数字。您可以通过取消缩进一个级别的min=min+1
来修复此问题,以便它与for
和else
对齐。
发布于 2018-07-01 03:06:19
number = int(input("Prime numbers between 2 and "))
for num in range(2,number + 1):
if num > 1:
for i in range(2,num):
if (num % i) == 0:
break
else:
print(num)
发布于 2018-11-06 10:18:12
解决方案:获取第n个质数条目。遍历质数的每个自然数,并将质数附加到列表中。当列表的长度满足用户的第n个素数条目时,终止程序。
# Get the number of prime numbers entry.
try:
enterNumber = int(input("List of nth prime numbers: "))
except:
print("The entry MUST be an integer.")
exit()
startNumber = 1
primeList = []
while True:
# Check for the entry to greater than zero.
if enterNumber <= 0:
print("The entry MUST be greater than zero.")
break
# Check each number from 1 for prime unless prime number entry is satisfied.
if startNumber > 1:
for i in range(2,startNumber):
if (startNumber % i) == 0:
break
else:
primeList.append(startNumber)
if (len(primeList) == enterNumber):
print(primeList)
break
else:
startNumber = startNumber + 1
continue
https://stackoverflow.com/questions/51117445
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