更改JSON响应如何导致POST请求| DRF？
更改JSON响应如何导致POST请求| DRF？
提问于 2018-08-07 04:33:42
我有点困惑，需要一些建议如何正确组织视图。在我的Django REST Framework项目中，我有非常简单的模型和序列化程序。
models.py
class Article(models.Model):
body = models.TextField()serializers.py
class ArticleSerializer(serializers.ModelSerializer):
class Meta:
model = Article
fields = ('id', 'body')假设我在数据库中有下一个数据：
ID | BODY
-------------------------------------------------------------
1 | Aki doing his homework about japanese robot in library.
2 | All chapters are accompanied by necessary links.
3 | Japanese robot Aki doing a lot of tasks.现在，我尝试通过POST向ArticleFilterView控制器发送JSON请求：
curl -X POST -H "Content-Type: application/json" -d '[
{
"first": ["Aki", "robot"],
"second": ["doing", "library"]
}]'
http://localhost:8000/api/article/filter/如果任何文章的正文字段中包含单词"Aki“和"robot”，我希望将该文章添加到JSON response中。同时，我需要从文本中删除“做”和“库”的单词。
输入：
[{
"fisrt": ["Aki", "robot"],
"second": ["doing", "library"]
}]输出：
[
{"id": 1, "body": "Aki his homework about japanese robot in ."},
{"id": 3, "body": "Japanese robot Aki a lot of tasks."},
]views.py:
class ArticleFilterView(APIView):
parser_classes = (JSONParser,)
def post(self, request, format=None):
# some code
return Response({'received data': request.data})settings.py:
REST_FRAMEWORK = {
'DEFAULT_RENDERER_CLASSES': (
'rest_framework.renderers.JSONRenderer',
),
'DEFAULT_PARSER_CLASSES': (
'rest_framework.parsers.JSONParser',
),
'DEFAULT_PERMISSION_CLASSES': (
'rest_framework.permissions.AllowAny',
),
}urls.py: (与settings.py文件在同一目录下)
urlpatterns = [
path('api/', include('article.urls')),
]article/urls.py:
urlpatterns = [
path(
'article/filter/',
ArticleFilterView.as_view(),
name='article_filter',
),
]
回答 1
Stack Overflow用户
回答已采纳
发布于 2018-08-07 11:11:10
我想，这是可行的。(我只是提到逻辑，而不是确切的代码)
class ArticleFilterView(APIView):
parser_classes = (JSONParser,)
def post(self, request, format=None):
# some code
return_data = {}
if first got a match:
return_data.update({'received data': request.data[0]['first']})
elif second got a match:
return_data.update({'received data': request.data[0]['second']})
return_data.update({"search_result":your_serch_result})
return Response(data=return_data)更新
视图的全面实现
from django.db.models import Q
class ArticleFilterView(APIView):
parser_classes = (JSONParser,)
def post(self, request, format=None):
for key, value in request.data.items():
my_filter = Q()
for search in value:
my_filter &= Q(body__icontains=search)
queryset = Article.objects.filter(my_filter)
if queryset.exists():
serializer = ArticleSerializer(queryset, many=True)
return_data = {
"search_result": serializer.data,
"input_data": {key: value}
}
return Response(data=return_data)
return Response({"message": "No data found"})但是，您的输入有效负载必须是一个类似dict的对象，
{
"first": ["Aki", "robot"],
"second": ["doing", "library"]
}更新-2
将views.py更改为，
from django.db.models import Q
class ArticleFilterView(APIView):
parser_classes = (JSONParser,)
def post(self, request, format=None):
my_filter = Q()
for search in request.data.get('first'):
my_filter &= Q(body__icontains=search)
queryset = Article.objects.filter(my_filter)
if queryset.exists():
serializer = ArticleSerializer(queryset, many=True,context={"request":request})
return_data = {
"search_result": serializer.data,
"input_data": {"first": request.data.get('first')}
}
return Response(data=return_data)
return Response({"message": "No data found"})并将序列化为，
class ArticleSerializer(serializers.ModelSerializer):
class Meta:
model = Article
fields = ('id', 'body')
def to_representation(self, instance):
data = super().to_representation(instance)
for input in self.context['request'].data.get('second'):
data['body'] = data['body'].replace(input, "")
return data页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/51715256
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