Flask文件上载未保存文件
Flask文件上载未保存文件
提问于 2018-08-08 02:39:49
我一直在关注一个Flask文件上传脚本的教程，如下所示：
app.py
from flask import Flask, url_for, render_template, request, flash, redirect
from werkzeug.utils import secure_filename
from datetime import datetime
import json
import subprocess
import os
import sys
UPLOAD_FOLDER = '/tmp/'
ALLOWED_EXTENSIONS = set(['txt'])
app = Flask('author_script')
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
app.debug = True
def allowed_file(filename):
return '.' in filename and \
filename.rsplit('.', 1)[1] in ALLOWED_EXTENSIONS
@app.route("/", methods=['GET', 'POST'])
def upload():
if request.method == 'POST':
if 'file' not in request.files:
flash("No file part")
return redirect(request.url)
file = request.files['file']
if file.filename == '':
flash('No selected file')
return redirect(request.url)
if file and allowed_file(file.filename):
filename = secure_filename(file.filename)
file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
flash('File uploaded!', 'success')
proc = subprocess.Popen('python author_script.py {}{} -p n -s n -m num'.format(UPLOAD_FOLDER, file.filename), shell=True, stdout=subprocess.PIPE)
return redirect(url_for('results'))
return render_template('upload.html')
# This could redirect the user to the stepfunctions page for their AWS account so they can monitor
# the pipeline progress.
@app.route('/results')
def results():
return render_template('results.html'). upload.html:
<!doctype html>
<title>Upload Authors List</title>
<h1>Upload Authors List</h1>
<form action="" method=post enctype=multipart/form-data>
<p><input type=file name=file>
<input type=submit value=Upload>
</form>当我上传一个合适的.txt文件并点击“上传”时，它可以工作，但是当我检查目标文件夹时，.txt文件并没有保存在那里。你知道哪里出问题了吗？
回答 2
Stack Overflow用户
回答已采纳
发布于 2018-08-08 03:25:14
你如何相信你的代码可以工作?你能得到一个成功的消息吗？我只是运行你的代码，做了一些修改，并成功了。
也许你不确定你的临时文件夹在哪里？如何设置UPLOAD_FOLDER = "."，以便可以检查.py文件目录中的文件。
这是我的dest文件夹，里面有两个上传的文件：
下面是我的python文件(E：\python_project\test)：
from flask import Flask, url_for, render_template, request, flash, redirect
from werkzeug.utils import secure_filename
from datetime import datetime
import json
import subprocess
import os
import sys
UPLOAD_FOLDER = '/tmp/'
ALLOWED_EXTENSIONS = set(['txt','jpg'])
app = Flask('author_script')
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
app.debug = True
def allowed_file(filename):
return '.' in filename and \
filename.rsplit('.', 1)[1] in ALLOWED_EXTENSIONS
@app.route("/", methods=['GET', 'POST'])
def upload():
if request.method == 'POST':
if 'file' not in request.files:
flash("No file part")
return redirect(request.url)
file = request.files['file']
if file.filename == '':
flash('No selected file')
return redirect(request.url)
if file and allowed_file(file.filename):
filename = secure_filename(file.filename)
file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
# flash('File uploaded!', 'success')
proc = subprocess.Popen('python author_script.py {}{} -p n -s n -m num'.format(UPLOAD_FOLDER, file.filename), shell=True, stdout=subprocess.PIPE)
return render_template('upload.html')
# This could redirect the user to the stepfunctions page for their AWS account so they can monitor
# the pipeline progress.
@app.route('/results')
def results():
return render_template('results.html')
app.run("localhost","8080")Stack Overflow用户
发布于 2020-12-05 14:40:07
只需确保添加".“如果保存在当前目录中，则在路径之前。
UPLOAD_FOLDER = './tmp/'这将会起作用！
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原文链接：
https://stackoverflow.com/questions/51733419
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