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社区首页 >问答首页 >clflush通过C函数使缓存线无效

clflush通过C函数使缓存线无效
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Stack Overflow用户
提问于 2018-08-13 16:58:56
回答 1查看 3.1K关注 0票数 7

我正在尝试使用clflush手动清除缓存线,以便确定缓存和线的大小。我没有找到任何关于如何使用该指令的指南。我所看到的,都是一些使用高级函数来达到这个目的的代码。

有一个内核函数void clflush_cache_range(void *vaddr, unsigned int size),但我仍然不知道在我的代码中包含什么以及如何使用它。我不知道该函数中的size是什么。

更重要的是,为了验证代码的正确性,我如何确定这行代码被逐出了呢?

更新:

这是我想要做的事情的初始代码。

代码语言:javascript
复制
#include <immintrin.h>
#include <stdint.h>
#include <x86intrin.h>
#include <stdio.h>
int main()
{
  int array[ 100 ];
  /* will bring array in the cache */
  for ( int i = 0; i < 100; i++ )
    array[ i ] = i;

  /* FLUSH A LINE */
  /* each element is 4 bytes */
  /* assuming that cache line size is 64 bytes */
  /* array[0] till array[15] is flushed */
  /* even if line size is less than 64 bytes */
  /* we are sure that array[0] has been flushed */
  _mm_clflush( &array[ 0 ] );



  int tm = 0;
  register uint64_t time1, time2, time3;


  time1 = __rdtscp( &tm ); /* set timer */
  time2 = __rdtscp( &array[ 0 ] ) - time1; /* array[0] is a cache miss */
  printf( "miss latency = %lu \n", time2 );

  time3 = __rdtscp( &array[ 0 ] ) - time2; /* array[0] is a cache hit */
  printf( "hit latency = %lu \n", time3 );
  return 0;
}

在运行代码之前,我想手动验证它是正确的代码。我走的路对吗?我是否正确使用了_mm_clflush

更新:

多亏了Peter的评论,我将代码修复如下

代码语言:javascript
复制
  time1 = __rdtscp( &tm ); /* set timer */
  time2 = __rdtscp( &array[ 0 ] ) - time1; /* array[0] is a cache miss */
  printf( "miss latency = %lu \n", time2 );
  time1 = __rdtscp( &tm ); /* set timer */
  time2 = __rdtscp( &array[ 0 ] ) - time1; /* array[0] is a cache hit */
  printf( "hit latency = %lu \n", time1 );

通过多次运行代码,我得到了以下输出

代码语言:javascript
复制
$ ./flush
miss latency = 238
hit latency = 168
$ ./flush
miss latency = 154
hit latency = 140
$ ./flush
miss latency = 252
hit latency = 140
$ ./flush
miss latency = 266
hit latency = 252

第一次运行似乎是合理的。但第二次运行看起来很奇怪。通过从命令行运行代码,每次使用值初始化数组,然后我显式地逐出第一行。

UPDATE4:

我尝试了Hadi-Brais代码,下面是输出

代码语言:javascript
复制
naderan@webshub:~$ ./flush3
address = 0x7ffec7a92220
array[ 0 ] = 0
miss section latency = 378
array[ 0 ] = 0
hit section latency = 175
overhead latency = 161
Measured L1 hit latency = 14 TSC cycles
Measured main memory latency = 217 TSC cycles
naderan@webshub:~$ ./flush3
address = 0x7ffedbe0af40
array[ 0 ] = 0
miss section latency = 392
array[ 0 ] = 0
hit section latency = 231
overhead latency = 168
Measured L1 hit latency = 63 TSC cycles
Measured main memory latency = 224 TSC cycles
naderan@webshub:~$ ./flush3
address = 0x7ffead7fdc90
array[ 0 ] = 0
miss section latency = 399
array[ 0 ] = 0
hit section latency = 161
overhead latency = 147
Measured L1 hit latency = 14 TSC cycles
Measured main memory latency = 252 TSC cycles
naderan@webshub:~$ ./flush3
address = 0x7ffe51a77310
array[ 0 ] = 0
miss section latency = 364
array[ 0 ] = 0
hit section latency = 182
overhead latency = 161
Measured L1 hit latency = 21 TSC cycles
Measured main memory latency = 203 TSC cycles

稍有不同的延迟是可以接受的。然而,与21和14相比,63的命中延迟也是可以观察到的。

UPDATE5:

当我检查Ubuntu时,没有启用省电功能。可能在bios中禁用了频率更改,或者缺少配置。

代码语言:javascript
复制
$ cat /proc/cpuinfo  | grep -E "(model|MHz)"
model           : 79
model name      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
cpu MHz         : 2097.571
model           : 79
model name      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz  
cpu MHz         : 2097.571
$ lscpu | grep MHz
CPU MHz:             2097.571

无论如何,这意味着频率被设置为它的最大值,这是我所关心的。通过多次运行,我看到了一些不同的值。这些是正常的吗?

代码语言:javascript
复制
$ taskset -c 0 ./flush3
address = 0x7ffe30c57dd0
array[ 0 ] = 0
miss section latency = 602
array[ 0 ] = 0
hit section latency = 161
overhead latency = 147
Measured L1 hit latency = 14 TSC cycles
Measured main memory latency = 455 TSC cycles
$ taskset -c 0 ./flush3
address = 0x7ffd16932fd0
array[ 0 ] = 0
miss section latency = 399
array[ 0 ] = 0
hit section latency = 168
overhead latency = 147
Measured L1 hit latency = 21 TSC cycles
Measured main memory latency = 252 TSC cycles
$ taskset -c 0 ./flush3
address = 0x7ffeafb96580
array[ 0 ] = 0
miss section latency = 364
array[ 0 ] = 0
hit section latency = 161
overhead latency = 140
Measured L1 hit latency = 21 TSC cycles
Measured main memory latency = 224 TSC cycles
$ taskset -c 0 ./flush3
address = 0x7ffe58291de0
array[ 0 ] = 0
miss section latency = 357
array[ 0 ] = 0
hit section latency = 168
overhead latency = 140
Measured L1 hit latency = 28 TSC cycles
Measured main memory latency = 217 TSC cycles
$ taskset -c 0 ./flush3
address = 0x7fffa76d20b0
array[ 0 ] = 0
miss section latency = 371
array[ 0 ] = 0
hit section latency = 161
overhead latency = 147
Measured L1 hit latency = 14 TSC cycles
Measured main memory latency = 224 TSC cycles
$ taskset -c 0 ./flush3
address = 0x7ffdec791580
array[ 0 ] = 0
miss section latency = 357
array[ 0 ] = 0
hit section latency = 189
overhead latency = 147
Measured L1 hit latency = 42 TSC cycles
Measured main memory latency = 210 TSC cycles
EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2018-08-14 05:41:36

您的代码中存在多个错误,这些错误可能导致您看到的无意义的测量结果。我已经修复了错误,你可以在下面的评论中找到解释。

代码语言:javascript
复制
/* compile with gcc at optimization level -O3 */
/* set the minimum and maximum CPU frequency for all cores using cpupower to get meaningful results */ 
/* run using "sudo nice -n -20 ./a.out" to minimize possible context switches, or at least use "taskset -c 0 ./a.out" */
/* you can optionally use a p-state scaling driver other than intel_pstate to get more reproducable results */
/* This code still needs improvement to obtain more accurate measurements,
   and a lot of effort is required to do that—argh! */
/* Specifically, there is no single constant latency for the L1 because of
   the way it's designed, and more so for main memory. */
/* Things such as virtual addresses, physical addresses, TLB contents,
   code addresses, and interrupts may have an impact that needs to be
   investigated */
/* The instructions that GCC puts unnecessarily in the timed section are annoying AF */
/* This code is written to run on Intel processors! */

#include <stdint.h>
#include <x86intrin.h>
#include <stdio.h>
int main()
{
  int array[ 100 ];

  /* this is optional */
  /* will bring array in the cache */
  for ( int i = 0; i < 100; i++ )
    array[ i ] = i;

  printf( "address = %p \n", &array[ 0 ] ); /* guaranteed to be aligned within a single cache line */

  _mm_mfence();                      /* prevent clflush from being reordered by the CPU or the compiler in this direction */

  /* flush the line containing the element */
  _mm_clflush( &array[ 0 ] );

  //unsigned int aux;
  uint64_t time1, time2, msl, hsl, osl; /* initial values don't matter */

  /* You can generally use rdtsc or rdtscp.
     See: https://stackoverflow.com/questions/59759596/is-there-any-difference-in-between-rdtsc-lfence-rdtsc-and-rdtsc-rdtscp
     I AM NOT SURE THOUGH THAT THE SERIALIZATION PROERTIES OF
     RDTSCP ARE APPLICABLE AT THE COMPILER LEVEL WHEN USING THE
     __RDTSCP INTRINSIC. THIS IS TRUE FOR PURE FENCES SUCH AS LFENCE. */

  _mm_mfence();                      /* this properly orders both clflush and rdtsc*/
  _mm_lfence();                      /* mfence and lfence must be in this order + compiler barrier for rdtsc */
  time1 = __rdtsc();                 /* set timer */
  _mm_lfence();                      /* serialize __rdtsc with respect to trailing instructions + compiler barrier for rdtsc and the load */
  int temp = array[ 0 ];             /* array[0] is a cache miss */
  /* measring the write miss latency to array is not meaningful because it's an implementation detail and the next write may also miss */
  /* no need for mfence because there are no stores in between */
  _mm_lfence();                      /* mfence and lfence must be in this order + compiler barrier for rdtsc and the load*/
  time2 = __rdtsc();
  _mm_lfence();                      /* serialize __rdtsc with respect to trailing instructions */
  msl = time2 - time1;

  printf( "array[ 0 ] = %i \n", temp );             /* prevent the compiler from optimizing the load */
  printf( "miss section latency = %lu \n", msl );   /* the latency of everything in between the two rdtsc */

  _mm_mfence();                      /* this properly orders both clflush and rdtsc*/
  _mm_lfence();                      /* mfence and lfence must be in this order + compiler barrier for rdtsc */
  time1 = __rdtsc();                 /* set timer */
  _mm_lfence();                      /* serialize __rdtsc with respect to trailing instructions + compiler barrier for rdtsc and the load */
  temp = array[ 0 ];                 /* array[0] is a cache hit as long as the OS, a hardware prefetcher, or a speculative accesses to the L1D or lower level inclusive caches don't evict it */
  /* measring the write miss latency to array is not meaningful because it's an implementation detail and the next write may also miss */
  /* no need for mfence because there are no stores in between */
  _mm_lfence();                      /* mfence and lfence must be in this order + compiler barrier for rdtsc and the load */
  time2 = __rdtsc();
  _mm_lfence();                      /* serialize __rdtsc with respect to trailing instructions */
  hsl = time2 - time1;

  printf( "array[ 0 ] = %i \n", temp );            /* prevent the compiler from optimizing the load */
  printf( "hit section latency = %lu \n", hsl );   /* the latency of everything in between the two rdtsc */


  _mm_mfence();                      /* this properly orders both clflush and rdtsc */
  _mm_lfence();                      /* mfence and lfence must be in this order + compiler barrier for rdtsc */
  time1 = __rdtsc();                 /* set timer */
  _mm_lfence();                      /* serialize __rdtsc with respect to trailing instructions + compiler barrier for rdtsc */
  /* no need for mfence because there are no stores in between */
  _mm_lfence();                      /* mfence and lfence must be in this order + compiler barrier for rdtsc */
  time2 = __rdtsc();
  _mm_lfence();                      /* serialize __rdtsc with respect to trailing instructions */
  osl = time2 - time1;

  printf( "overhead latency = %lu \n", osl ); /* the latency of everything in between the two rdtsc */


  printf( "Measured L1 hit latency = %lu TSC cycles\n", hsl - osl ); /* hsl is always larger than osl */
  printf( "Measured main memory latency = %lu TSC cycles\n", msl - osl ); /* msl is always larger than osl and hsl */

  return 0;
}

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票数 7
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/51818655

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