Tac Tac Toe嵌套列表问题
Tac Tac Toe嵌套列表问题
提问于 2018-06-07 03:23:23
我的Tic tac toe代码运行良好，除了一些问题。当在板上标记一个点时，用户可以覆盖并将他们自己的标记放在同一个点上。即使我有修复这个问题的代码。这是我的代码。请按照您认为合适的方式修复任何其他错误。在这方面我几乎不能通过一门课。
board = [['-','-','-']
,['-','-','-']
,['-','-','-']]
player1 = 'X'
player2 = 'O'
win = False
turns = 0
player1= str(input("Whats ur name+"))
player2= str(input("Whats ur name"))
def checkwin(player):
for c in range(0,3):
if board[c][0] == player and board[c][1] == player and board[c][2] == player:
print "*********\n\n%s wins\n\n*********" % player
playerwin = True
return playerwin
elif board[0][c] == player and board[1][c] == player and board[2][c] == player:
print "*********\n\n%s wins\n\n*********" % player
playerwin = True
return playerwin
#check for diagonal win
elif board[0][0] == player and board[1][1] == player and board[2][2] == player:
print "*********\n\n%s wins\n\n*********" % player
playerwin = True
return playerwin
#check for diagonal win (right to left)
elif board[0][2] == player and board[1][1] == player and board[2][0] == player:
print "*********\n\n%s wins\n\n*********" % player
playerwin = True
return playerwin
else:
playerwin = False
return playerwin
def playerturn(player):
print "%s's turn" % player
turn = 1
while(turn):
print "Select column [1-3]: ",
col = int(raw_input()) - 1
print "Select row [1-3]: ",
row = int(raw_input()) - 1
if board[row][col] == "X" or board[row][col] == "O":
print "Already taken!"
else:
board[row][col] = player
turn = 0
def printboard():
print board[0]
print board[1]
print board[2]
printboard()
while(win == False):
playerturn(player1)
turns += 1
printboard()
if checkwin(player1) == True: break
if turns == 9:
print "This game is a draw!"
break
playerturn(player2)
turns += 1
printboard()
checkwin(player2)
if checkwin(player2) == True: break回答 1
Stack Overflow用户
发布于 2018-06-07 03:49:32
您的问题是，您已经将玩家名称放入数组中，并检查数组中是否有"X“或"O”。一个简单的解决方案是将if条件更改为... == player1而不是"X“。如果这样做，您还必须调整绘图函数。
board = [['-','-','-']
,['-','-','-']
, ['-','-','-']]
#player1 = 'X'
#player2 = 'O'
win = False
turns = 0
player1= raw_input("Whats ur name+")
player2= raw_input("Whats ur name")
def checkwin(player):
for c in range(0,3):
if board[c][0] == player and board[c][1] == player and board[c][2] == player:
print "*********\n\n%s wins\n\n*********" % player
playerwin = True
return playerwin
elif board[0][c] == player and board[1][c] == player and board[2][c] == player:
print "*********\n\n%s wins\n\n*********" % player
playerwin = True
return playerwin
#check for diagonal win
elif board[0][0] == player and board[1][1] == player and board[2][2] == player:
print "*********\n\n%s wins\n\n*********" % player
playerwin = True
return playerwin
#check for diagonal win (right to left)
elif board[0][2] == player and board[1][1] == player and board[2][0] == player:
print "*********\n\n%s wins\n\n*********" % player
playerwin = True
return playerwin
else:
playerwin = False
return playerwin
def playerturn(player):
print "%s's turn" % player
turn = 1
while(turn):
print "Select column [1-3]: ",
col = int(raw_input()) - 1
print "Select row [1-3]: ",
row = int(raw_input()) - 1
if board[row][col] == player1 or board[row][col] == player2:
print "Already taken!"
else:
board[row][col] = player
turn = 0
def printboard():
print ["X" if x == player1 else "O" if x == player2 else "-" for x in board[0]]
print ["X" if x == player1 else "O" if x == player2 else "-" for x in board[1]]
print ["X" if x == player1 else "O" if x == player2 else "-" for x in board[2]]
printboard()
while(win == False):
playerturn(player1)
turns += 1
printboard()
if checkwin(player1) == True: break
if turns == 9:
print "This game is a draw!"
break
playerturn(player2)
turns += 1
printboard()
checkwin(player2)
if checkwin(player2) == True: break我还将raw_input()的str(input())替换为允许字符串作为名称。
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原文链接：
https://stackoverflow.com/questions/50728085
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