SpringBoot不处理org.hibernate.exception.ConstraintViolationException
SpringBoot不处理org.hibernate.exception.ConstraintViolationException
提问于 2017-07-13 10:50:52
我在实体类中定义了一个用于验证电子邮件的模式。在我的验证异常处理程序类中，我为ConstraintViolationException添加了处理程序。我的应用程序使用SpringBoot 1.4.5。
Profile.java
@Entity
@EntityListeners(AuditingEntityListener.class)
@Table(name = "profile")
public class Profile extends AuditableEntity {
private static final long serialVersionUID = 8744243251433626827L;
@Column(name = "email", nullable = true, length = 250)
@NotNull
@Pattern(regexp = "^([^ @])+@([^ \\.@]+\\.)+([^ \\.@])+$")
@Size(max = 250)
private String email;
....
}ValidationExceptionHandler.java
@ControllerAdvice
public class ValidationExceptionHandler extends ResponseEntityExceptionHandler {
private MessageSource messageSource;
@Autowired
public ValidationExceptionHandler(MessageSource messageSource) {
this.messageSource = messageSource;
}
@ExceptionHandler(ConstraintViolationException.class)
public ResponseEntity<Object> handleConstraintViolation(ConstraintViolationException ex,
WebRequest request) {
List<String> errors = new ArrayList<String>();
....
}
} 当我运行我的代码并传递无效的电子邮件地址时，我得到以下异常。handleConstraintViolation中的代码永远不会执行。异常中返回的http状态是500，但我想返回400。你知道我该怎么做吗？
2017-07-12 22:15:07.078 ERROR 55627 --- [nio-9000-exec-2] o.h.c.s.u.c.UserProfileController : Validation failed for classes [org.xxxx.common.service.user.domain.Profile] during persist time for groups [javax.validation.groups.Default, ]
List of constraint violations:[
ConstraintViolationImpl{interpolatedMessage='must match "^([^ @])+@([^ \.@]+\.)+([^ \.@])+$"', propertyPath=email, rootBeanClass=class org.xxxx.common.service.user.domain.Profile, messageTemplate='{javax.validation.constraints.Pattern.message}'}]
javax.validation.ConstraintViolationException: Validation failed for classes [org.xxxx.common.service.user.domain.Profile] during persist time for groups [javax.validation.groups.Default, ]
List of constraint violations:[
ConstraintViolationImpl{interpolatedMessage='must match "^([^ @])+@([^ \.@]+\.)+([^ \.@])+$"', propertyPath=email, rootBeanClass=class org.xxxx.common.service.user.domain.Profile, messageTemplate='{javax.validation.constraints.Pattern.message}'}]
at org.hibernate.cfg.beanvalidation.BeanValidationEventListener.validate(BeanValidationEventListener.java:138)
at org.hibernate.cfg.beanvalidation.BeanValidationEventListener.onPreInsert(BeanValidationEventListener.java:78) 回答 11
Stack Overflow用户
发布于 2017-09-21 20:47:42
你不能捕获ConstraintViolationException.class，因为它没有传播到代码的那一层，它被较低的层捕获，被包装在另一个类型下并重新抛出。因此，命中web层的异常不是ConstraintViolationException。
在我的例子中，它是一个TransactionSystemException。我在JpaTransactionManager中使用了来自Spring的@Transactional注释。当事务中出现错误时，EntityManager抛出回滚异常，该异常由JpaTransactionManager转换为TransactionSystemException。
所以你可以这样做：
@ExceptionHandler({ TransactionSystemException.class })
public ResponseEntity<RestResponseErrorMessage> handleConstraintViolation(Exception ex, WebRequest request) {
Throwable cause = ((TransactionSystemException) ex).getRootCause();
if (cause instanceof ConstraintViolationException) {
Set<ConstraintViolation<?>> constraintViolations = ((ConstraintViolationException) cause).getConstraintViolations();
// do something here
}
}Stack Overflow用户
发布于 2018-12-10 23:10:08
我只想加点东西。我也在试着做同样的事情，验证实体。然后我意识到，如果你验证控制器的输入，Spring已经拥有了所有的东西。
@RequestMapping(value = "/profile", method = RequestMethod.POST)
public ProfileDto createProfile(@Valid ProfileDto profile){
...
}@Valid注解将触发带有javax.validation注解的验证。
假设您的配置文件用户名上有一个模式注释，其中regexp不允许使用空格。
Spring将构建一个状态为400 (错误请求)的响应和如下所示的主体：
{
"timestamp": 1544453370570,
"status": 400,
"error": "Bad Request",
"errors": [
{
"codes": [
"Pattern.ProfileDto.username",
"Pattern.username",
"Pattern.java.lang.String",
"Pattern"
],
"arguments": [
{
"codes": [
"profileDto.username",
"username"
],
"arguments": null,
"defaultMessage": "username",
"code": "username"
},
[],
{
"defaultMessage": "^[A-Za-z0-9_\\-.]+$",
"arguments": null,
"codes": [
"^[A-Za-z0-9_\\-.]+$"
]
}
],
"defaultMessage": "must match \"^[A-Za-z0-9_\\-.]+$\"",
"objectName": "profileDto",
"field": "username",
"rejectedValue": "Wr Ong",
"bindingFailure": false,
"code": "Pattern"
}
],
"message": "Validation failed for object='profileDto'. Error count: 1",
"path": "/profile"
}Stack Overflow用户
发布于 2019-07-27 20:53:26
你不能捕获ConstraintViolationException.class，因为它没有传播到代码的那一层，它被较低的层捕获，被包装在另一个类型下并重新抛出。因此，命中web层的异常不是ConstraintViolationException。所以你可以这样做：
@ExceptionHandler({TransactionSystemException.class})
protected ResponseEntity<Object> handlePersistenceException(final Exception ex, final WebRequest request) {
logger.info(ex.getClass().getName());
//
Throwable cause = ((TransactionSystemException) ex).getRootCause();
if (cause instanceof ConstraintViolationException) {
ConstraintViolationException consEx= (ConstraintViolationException) cause;
final List<String> errors = new ArrayList<String>();
for (final ConstraintViolation<?> violation : consEx.getConstraintViolations()) {
errors.add(violation.getPropertyPath() + ": " + violation.getMessage());
}
final ApiError apiError = new ApiError(HttpStatus.BAD_REQUEST, consEx.getLocalizedMessage(), errors);
return new ResponseEntity<Object>(apiError, new HttpHeaders(), apiError.getStatus());
}
final ApiError apiError = new ApiError(HttpStatus.INTERNAL_SERVER_ERROR, ex.getLocalizedMessage(), "error occurred");
return new ResponseEntity<Object>(apiError, new HttpHeaders(), apiError.getStatus());
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/45070642
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