如何检测到用户浏览器中的JavaScript或Cookie被禁用,并通知他任何帮助?
发布于 2011-01-05 19:01:44
用于检查cookies,您可以使用:
function checkCookie(){
var cookieEnabled = navigator.cookieEnabled;
if (!cookieEnabled){
document.cookie = "testcookie";
cookieEnabled = document.cookie.indexOf("testcookie")!=-1;
}
return cookieEnabled || showCookieFail();
}
function showCookieFail(){
// do something here
}
// within a window load,dom ready or something like that place your:
checkCookie();
为了检查JavaScript,请使用内部带有某种消息的<noscript>
标记
发布于 2018-01-30 20:11:07
由于cookie检测在IE 11中不起作用,我建议使用现代方法:
function areCookiesEnabled() {
try {
document.cookie = 'cookietest=1';
var cookiesEnabled = document.cookie.indexOf('cookietest=') !== -1;
document.cookie = 'cookietest=1; expires=Thu, 01-Jan-1970 00:00:01 GMT';
return cookiesEnabled;
} catch (e) {
return false;
}
}
https://github.com/Modernizr/Modernizr/blob/master/feature-detects/cookies.js
发布于 2015-11-02 02:30:04
// Example[1]: if ( hasCookies() )
/**
* @hasCookies: Check if cookie's are Enabled
* @param {none} ''
* @return {BOOLEAN} true|false
*/
function hasCookies() {
return (navigator.cookieEnabled);
}
// Example[2]: if ( JLS.TEST.COOKIE() )
// Java Pattern ( How to write usable JS)
/** @namespace JLS classes and functions. */
var JLS = JLS || {};
/**
* TEST utility
* @namespace JLS
* @class TEST
*/
JLS.TEST = {
/**
* @public-method COOKIE
* @COOKIE Check if cookie's are Enabled
* @return {BOOLEAN} true|false
*/
COOKIE: function () {
//Change this (library). Not main.js (Algorithm)
return (navigator.cookieEnabled);
}
};
https://stackoverflow.com/questions/4603289
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