HTTP状态500 - org.apache.jasper.JasperException: java.lang.ClassNotFoundException: org.apache.jsp.register_jsp
HTTP状态500 - org.apache.jasper.JasperException: java.lang.ClassNotFoundException: org.apache.jsp.register_jsp
提问于 2012-08-02 17:06:37
我在显示Tomcat Server中的register.jsp网页时遇到问题。类位于WEB-INF/jsp和webapps/ register.jsp文件夹中，而类位于WEB-INF/ RegisterController.class中。我在两个地方放置了register.jsp，因为我正在尝试让register.jsp工作，但最终register.jsp将驻留在WEB-INF/jsp中。问题似乎出在web.xml或register-servlet.xml中。我使用的是Tomcat 7.0.21，Spring MVC 3.0。
web.xml文件
<?xml version="1.0" encoding="UTF-8"?>
<web-app
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="
http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>Snap Fires</display-name>
<servlet>
<servlet-name>register</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet-mapping>
<servlet-name>register</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
</web-app>register-servlet.xml文件
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd">
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value> /WEB-INF/jsp/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
<bean name="/register.jsp" class="snapFires.controller.RegisterController"/>
</beans>错误代码：
HTTP Status 500 -
type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: java.lang.ClassNotFoundException: org.apache.jsp.register_jsp
org.apache.jasper.servlet.JspServletWrapper.getServlet(JspServletWrapper.java:178)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:370)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:389)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:333)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
root cause
java.lang.ClassNotFoundException: org.apache.jsp.register_jsp
java.net.URLClassLoader$1.run(URLClassLoader.java:366)
java.net.URLClassLoader$1.run(URLClassLoader.java:355)
java.security.AccessController.doPrivileged(Native Method)
java.net.URLClassLoader.findClass(URLClassLoader.java:354)
org.apache.jasper.servlet.JasperLoader.loadClass(JasperLoader.java:132)
org.apache.jasper.servlet.JasperLoader.loadClass(JasperLoader.java:63)
org.apache.jasper.servlet.JspServletWrapper.getServlet(JspServletWrapper.java:172)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:370)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:389)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:333)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
note The full stack trace of the root cause is available in the Apache Tomcat/7.0.21 logs.
Apache Tomcat/7.0.21register.jsp文件
<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %>
<%@ taglib uri="http://www.springframework.org/tags/form" prefix="form" %>
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Registration Page</title>
</head>
<body>
<h1>Create New Person</h1>
<form:form action="/jsp/registerOut.html" commandName="register">
<table>
<tr>
<td><form:label path="firstName">First Name:</form:label></td>
<td><form:input path="firstName"/></td>
</tr>
<tr>
<td><form:label path="lastName">Last Name</form:label></td>
<td><form:input path="lastName"/></td>
</tr>
</table>
<input type="submit" value="Save" />
</form:form>
</body>
</html>RegisterController.java类
package snapFires.controller;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.ServletException;
//import javax.annotation.Resource;
import org.apache.log4j.Logger;
//import org.springframework.ui.ModelMap;
import org.springframework.ui.Model;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ModelAttribute;
//import org.springframework.web.bind.annotation.RequestMapping;
//import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.multiaction.MultiActionController;
//import org.springframework.web.servlet.mvc.SimpleFormController;
import java.io.IOException;
//import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import snapFires.domain.Name;
import snapFires.service.RegisterImpl;
@Controller
@RequestMapping("/register")
public class RegisterController extends MultiActionController {
public ModelAndView handleRequest (HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
return new ModelAndView("register.jsp");
}
//@Resource(name="register")
//private RegisterImpl registerImpl;
protected static Logger logger = Logger.getLogger("controller");
@RequestMapping(value="/jsp/register.html", method=RequestMethod.GET)
public void simpleForm(Model model){
model.addAttribute(new RegisterImpl());
}
@RequestMapping(value="/jsp/registerOut.html", method=RequestMethod.POST)
public void simple(@ModelAttribute RegisterImpl registerImpl, Model model){
model.addAttribute("register", registerImpl);
}
}回答 1
Stack Overflow用户
发布于 2012-08-02 21:41:17
在RegisterController类中返回ModelAndView时只返回寄存器。由于您使用的是带有后缀和前缀的内部视图解析器，它将添加WEB-INF/jsp和.jsp来注册和获取路径。
另请参阅https://github.com/SpringSource/spring-mvc-showcase，了解带有pdf格式的春季mvc3展示案例。请阅读http://duckranger.com/2011/07/spring-mvc-3-0-with-sts-tutorial-part-i/
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原文链接：
https://stackoverflow.com/questions/11774302
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