php回显函数不打印结果
php回显函数不打印结果
提问于 2018-08-27 06:46:03
我有一个脚本来计算每天票打开的时间，但只有几个小时我们是开放的。函数的细节并不重要，但我已经将其全部粘贴在这里，因为这可能是失败的原因。
下面是函数：
function getTime($o, $now, $total) {
//One Day in seconds
$oneDay = 86400;
//One Business day (12 hours, 7am-7pm)
$oneBDay = 43200;
//Get the timestamp of 7am/7pm for time given
$sevenAM = mktime('7', '0', '0', m($o), d($o), y($o));
$sevenPM = mktime('19', '0', '0', m($o), d($o), y($o));
//If Ticket Start Time is before 7am, we only count from 7am after
if ($o < $sevenAM) {
$o = $sevenAM;
} else {
$o = $o;
}
//Debug to get today
$today = date('Y-m-d h:i:s a', $o);
//See if we are within the same business day
$diff = $now - $o;
//Debug
//echo $today.",".$timeSpent.",".$total."\n";
//If we are not within 1 business day, do this again
if ($diff > $oneBDay) {
//Total Time spent for the day
$timeSpent = $sevenPM - $o;
//Add todays time to total time
$total = $total + $timeSpent;
//Move to tomorrow
$o = $sevenAM + $oneDay;
getTime($o, $now, $total);
}
//If we are within 1 business day, count the time for today and return our result
if ($diff < $oneBDay) {
$time = $diff;
$total = $total + $time; //for example $total = 123456
return $total;
}
}当我这样做的时候
echo getTime($o,$now,0); 我预计会看到123456。但我什么都没打印出来。
函数运行，我知道total有一个值(我已经将其静态设置为debug)。
--请注意，如果需要，该函数会调用自身
其他功能：
function y($o){
$y = date('Y',$o);
return $y;
}
function m($o){
$m = date('m',$o);
return $m;
}
function d($o){
$d = date('d',$o);
return $d;
}编辑：
如果我这样做了：
if ($diff < $oneBDay) {
$time = $diff;
$total = $total + $time; //for example $total = 123456
echo "My Total:".$total;
return $total;
}我将看到我的总数:123456
回答 2
Stack Overflow用户
回答已采纳
发布于 2018-08-27 07:17:10
指出你的函数由于结构缺陷而很难调试，这并不是徒劳的。我建议您为您的函数创建一个Unit Test，然后进行重构，这样您就能够确保保留所需的行为。
也就是说，您的函数打印任何内容，因为它没有到达任何显式的return指令。所以它返回null。如果没有命中最后一个if，您将错过返回值的最后一次机会。
我不确定你的函数应该做什么，但看起来如果你递归地调用它，你可能想要返回它的值，或者至少重新赋值给一个变量。为这个结账。
<?php
function y($o){ $y = date('Y',$o); return $y; }
function m($o){ $m = date('m',$o); return $m; }
function d($o){ $d = date('d',$o); return $d; }
function getTime($o,$now,$total){
//One Day in seconds
$oneDay = 86400;
//One Business day (12 hours, 7am-7pm)
$oneBDay = 43200;
//Get the timestamp of 7am/7pm for time given
$sevenAM = mktime('7','0','0',m($o),d($o),y($o));
$sevenPM = mktime('19','0','0',m($o),d($o),y($o));
//If Ticket Start Time is before 7am, we only count from 7am after
if ($o < $sevenAM){
$o = $sevenAM;
}else{
$o = $o;
}
//Debug to get today
$today = date('Y-m-d h:i:s a',$o);
//See if we are within the same business day
$diff = $now - $o;
//Debug
//echo $today.",".$timeSpent.",".$total."\n";
//If we are not within 1 business day, do this again
if ($diff > $oneBDay){
//Total Time spent for the day
$timeSpent = $sevenPM - $o;
//Add todays time to total time
$total = $total+$timeSpent;
//Move to tomorrow
$o = $sevenAM+$oneDay;
return getTime($o,$now,$total); // LOOKS LIKE YOU WANT TO RETURN VALUE HERE
}
//If we are within 1 business day, count the time for today and return our result
if($diff < $oneBDay){
$time = $diff;
$total = $total+$time; // FIXED MISSING SEMICOLON HERE TO AVOID SYNTAX ERROR
return $total;
}
}
$test = getTime(1534964212, date('U'), 0);
echo "$test"; // 144885
?>Stack Overflow用户
发布于 2018-08-27 07:18:03
虽然我不太清楚您想用这个函数做什么，但我已经更正了一些语法错误，并为缺少的情况添加了一些返回。(在if ($diff > $oneBDay) {内部，并将if ($diff < $oneBDay) {更改为if ($diff <= $oneBDay) {)
<?php
function getTime($o, $now, $total) {
//One Day in seconds
$oneDay = 86400;
//One Business day (12 hours, 7am-7pm)
$oneBDay = 43200;
//Get the timestamp of 7am/7pm for time given
$sevenAM = mktime('7', '0', '0', m($o), d($o), y($o));
$sevenPM = mktime('19', '0', '0', m($o), d($o), y($o));
//If Ticket Start Time is before 7am, we only count from 7am after
if ($o < $sevenAM) {
$o = $sevenAM;
}
//See if we are within the same business day
$diff = $now - $o;
//If we are not within 1 business day, do this again
if ($diff > $oneBDay) {
//Total Time spent for the day
$timeSpent = $sevenPM - $o;
//Add todays time to total time
$total = $total + $timeSpent;
//Move to tomorrow
$o = $sevenAM + $oneDay;
return getTime($o, $now, $total);
}
//If we are within 1 business day, count the time for today and return our result
if ($diff <= $oneBDay) {
$time = $diff;
$total = $total + $time; //for example $total = 123456;
return $total;
}
}
function y($o){ $y = date('Y',$o); return $y; }
function m($o){ $y = date('m',$o); return $y; }
function d($o){ $y = date('d',$o); return $y; }
$o = 1534964212;
$now = date('U');
echo getTime($o,$now,0);现在它返回类似于145111的内容
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/52030794
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