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社区首页 >问答首页 >由不同的逻辑列名表示的DuplicateMappingException

由不同的逻辑列名表示的DuplicateMappingException
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Stack Overflow用户
提问于 2014-07-29 23:15:56
回答 1查看 10.4K关注 0票数 4

我对两个类MasavNew和MasavRow使用OneToMany映射:

代码语言:javascript
复制
@Entity
@Table(name = "ArgoCHFileHdr")
public class MasavNew  {


@OneToMany(fetch = FetchType.LAZY, mappedBy = "msv",cascade = CascadeType.ALL)
@ElementCollection(targetClass=MasavRow.class)
private List<MasavRow> rows;

@Id
@Column(name = "[Arg.CH.F.Key]", nullable = false)
@GeneratedValue(strategy=GenerationType.IDENTITY)
protected Integer argCHFKey;

}


@Entity
@Table(name = "ArgoCHFileRow")
@DynamicUpdate
public class MasavRow extends IModel {


@ManyToOne(fetch = FetchType.LAZY,optional=true)
@JoinColumn(name="[Arg.CH.F.Key]")
private MasavNew msv;


@Id
@Column(name = "[Arg.CH.F.Key]", nullable = false)
private int argCHFKey;


@Id
@Column(name = "[Arg.CH.L.MNB]", nullable = false)
@GeneratedValue(strategy=GenerationType.IDENTITY)
private Integer argCHLMNB;


@Column(name = "[Erp.Clnt]", nullable = true)
private String erpClnt;


}

然后在运行过程中,我收到了下一个异常:

代码语言:javascript
复制
Caused by: org.hibernate.DuplicateMappingException:  Table [ArgoCHFileRow] contains physical column name [`Arg.CH.F.Key`] represented by different logical column names: [`Arg.CH.F.Key`], [Arg.CH.F.Key]
    at org.hibernate.cfg.Configuration$MappingsImpl$TableColumnNameBinding.bindPhysicalToLogical(Configuration.java:3185)
    at org.hibernate.cfg.Configuration$MappingsImpl$TableColumnNameBinding.addBinding(Configuration.java:3158)
    at org.hibernate.cfg.Configuration$MappingsImpl.addColumnBinding(Configuration.java:3202)
    at org.hibernate.cfg.Ejb3JoinColumn.addColumnBinding(Ejb3JoinColumn.java:532)
    at org.hibernate.cfg.Ejb3Column.linkWithValue(Ejb3Column.java:364)
    at org.hibernate.cfg.annotations.TableBinder.linkJoinColumnWithValueOverridingNameIfImplicit(TableBinder.java:523)
    at org.hibernate.cfg.annotations.TableBinder.bindFk(TableBinder.java:457)
    at org.hibernate.cfg.ToOneFkSecondPass.doSecondPass(ToOneFkSecondPass.java:117)
    at org.hibernate.cfg.Configuration.processEndOfQueue(Configuration.java:1596)
    at org.hibernate.cfg.Configuration.processFkSecondPassInOrder(Configuration.java:1519)
    at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1420)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1844)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1928)
    at org.springframework.orm.hibernate4.LocalSessionFactoryBuilder.buildSessionFactory(LocalSessionFactoryBuilder.java:343)
    at org.springframework.orm.hibernate4.LocalSessionFactoryBean.buildSessionFactory(LocalSessionFactoryBean.java:431)
    at org.springframework.orm.hibernate4.LocalSessionFactoryBean.afterPropertiesSet(LocalSessionFactoryBean.java:416)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1612)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1549)

我该如何解决这个问题呢?

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回答 1

Stack Overflow用户

发布于 2014-07-29 23:21:54

删除

代码语言:javascript
复制
@Id
@Column(name = "[Arg.CH.F.Key]", nullable = false)
private int argCHFKey;

因为您可以从msv对象中获取密钥。

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/25018893

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