从string python中删除时间戳和url
从string python中删除时间戳和url
提问于 2018-08-22 04:36:17
我有一个字符串，我必须删除其中的时间戳和标点符号。我还必须去掉所有的数字，但responseCode的值必须保持不变，例如本例中的400。无论400来自哪里，它都不应该被移除。并且我想删除所有以tar.gz结尾的url和文件名。
mystr="sun aug 19 13:02:09 2018 I_am.98189: hello please connect to the local host:8080
sun aug 19 13:02:10 2018 hey.94289: hello not able to find the file
sun aug 19 13:02:10 2018 I_am.94289: Base url for file_transfer is: abc/vd/filename.tar.gz
mon aug 19 13:02:10 2018 how_94289: $var1={
'responseCode' = '400',
'responseDate' = 'Sun, 19 Aug 2018 13:02:08 ET',
'responseContent' = 'ABC' }
mon aug 20 13:02:10 2018 hello!94289: Error performing action, failed with error code [400]
"预期结果：
"I_am hello please connect to the local host
hello not able to find the file
Base url for file_transfer
var1
responseCode = 400
responseDate
responseContent = ABC
Error performing action, failed with error code 400
"我的解决方案是删除标点符号：
punctuations = '''!=()-[]{};:'"\,<>.?@#$%^&*_~'''
no_punct = ""
for char in mystr:
if char not in punctuations:
no_punct = no_punct + char
# display the unpunctuated string
print(no_punct)回答 1
Stack Overflow用户
回答已采纳
发布于 2018-08-22 06:02:52
也许：
patterns = [r"\w{3} \w{3} \d{2} \d{2}:\d{2}:\d{2} \d{4}\s*", #sun aug 19 13:02:10 2018
r"\w{3}, \d{2} \w{3} \d{4} \d{2}:\d{2}:\d{2} \w{2}\s*", #Sun, 19 Aug 2018 13:02:08 ET
r":\s*([\da-zA_Z]+\/)+([a-zA-Z0-9\.]+)", #URL
r"([a-zA-Z_!]+)[\.!_]\d+:\s*", #word[._!]number:>=0space
r":\d+",
"[/':,${}\[\]]" #punctuations
]
s = mystr
for p in patterns:
s = re.sub(p,'', s)
s = s.strip()
print(s)输出：
hello please connect to the local host
hello not able to find the file
Base url for file_transfer is
var1=
responseCode = 400
responseDate =
responseContent = ABC
Error performing action failed with error code 400页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/51956359
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