blocks|key|321351|text|import+re
m+=+re.search("Your+number+is+(\d%2B)",
++++++"xxx+Your+number+is+123++fdjsk")
if+m:
++++print+m.groups()[0]|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|321352|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import re
m = re.search("Your number is &lt;b&gt;(\d+)&lt;/b&gt;",
 "xxx Your number is &lt;b&gt;123&lt;/b&gt; fdjsk")
if m:
 print m.groups()[0]
</code></pre>

blocks|key|538233|text|import+re
x+=+'Your+number+is+123'
re.search('(?<=Your+number+is+)(\d%2B)',x).group(0)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|538234|这将搜索'Your+number+is‘字符串后面的数字|unstyled|538235|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>import re
x = 'Your number is &lt;b&gt;123&lt;/b&gt;'
re.search('(?&lt;=Your number is )&lt;b&gt;(\d+)&lt;/b&gt;',x).group(0)
</code></pre>

this searches for the number that follows the 'Your number is' string

blocks|key|321374|text|import+re
print+re.search(r'(\d%2B)',+'Your+number+is+123').group(0)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|321375|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import re
print re.search(r'(\d+)', 'Your number is &lt;b&gt;123&lt;/b&gt;').group(0)
</code></pre>

blocks|key|538298|text|最简单的方法就是提取数字(Number)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|538299|re.search(r"\d%2B",text)|code-block|syntax|javascript|538300|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The simplest way is just extract digit(number) 

<pre><code>re.search(r"\d+",text)
</code></pre>

blocks|key|538246|text|val="Your+number+is+123"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|538247|选项:1|unstyled|538248|m=re.search(r'(<.*?>)(\d%2B)(<.*?>)',val)

m.group(2)|538249|选项:2|538250|re.sub(r'([\s\S]%2B)(<.*?>)(\d%2B)(<.*?>)',r'\3',val)|538251|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|P|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|M|3|-4|5|F|7|T|8|@]|9|@]|A|$]]]|N|$]]

<pre><code>val="Your number is &lt;b&gt;123&lt;/b&gt;"
</code></pre>

<h3>Option : 1</h3>

<pre><code>m=re.search(r'(&lt;.*?&gt;)(\d+)(&lt;.*?&gt;)',val)

m.group(2)
</code></pre>

<h3>Option : 2</h3>

<pre><code>re.sub(r'([\s\S]+)(&lt;.*?&gt;)(\d+)(&lt;.*?&gt;)',r'\3',val)
</code></pre>

blocks|key|321446|text|import+re
found+=+re.search("your+number+is+(\d%2B)",+"something....+Your+number+is+123+something...")

if+found:
++++print+found.group()[0]|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|321447|这里(\d%2B)是分组，因为只使用了一个组[0]。当有多个分组时，应该使用[grouping+index]。|unstyled|offset|length|style|CODE|321448|entityMap^0|0|K|3|10|G|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]|$G|Q|H|R|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|S|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>import re
found = re.search("your number is &lt;b&gt;(\d+)&lt;/b&gt;", "something.... Your number is &lt;b&gt;123&lt;/b&gt; something...")

if found:
 print found.group()[0]
</code></pre>

Here (\d+) is the grouping, since there is only one group <code>[0]</code> is used. When there are several groupings <code>[grouping index]</code> should be used.

blocks|key|321470|text|您可以使用以下示例来解决您的问题：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|321471|import+re

search+=+re.search(r"\d%2B",text).group(0)+#returns+the+number+that+is+matched+in+the+text

print("Starting+Index+Of+Digit",+search.start())

print("Ending+Index+Of+Digit:",+search.end())|code-block|syntax|javascript|321472|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use the following example to solve your problem:

<pre><code>import re

search = re.search(r"\d+",text).group(0) #returns the number that is matched in the text

print("Starting Index Of Digit", search.start())

print("Ending Index Of Digit:", search.end())
</code></pre>

blocks|key|538413|text|要提取为python列表，可以使用findall|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|538414|>>>+import+re
>>>+string+=+'Your+number+is+123'
>>>+pattern+=+'\d%2B'
>>>+re.findall(pattern,string)
['123']
>>>|code-block|syntax|javascript|538415|entityMap^0|H|7|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

To extract as python list you can use <code>findall</code>

<pre><code>&gt;&gt;&gt; import re
&gt;&gt;&gt; string = 'Your number is &lt;b&gt;123&lt;/b&gt;'
&gt;&gt;&gt; pattern = '\d+'
&gt;&gt;&gt; re.findall(pattern,string)
['123']
&gt;&gt;&gt;
</code></pre>

blocks|key|538429|text|import+re
x+=+'Your+number+is+123'
output+=+re.search('(?<=Your+number+is+)(\d%2B)',x).group(1)
print(output)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|538430|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import re
x = 'Your number is &lt;b&gt;123&lt;/b&gt;'
output = re.search('(?&lt;=Your number is )&lt;b&gt;(\d+)&lt;/b&gt;',x).group(1)
print(output)
</code></pre>

I want to write a simple regular expression in Python that extracts a number from HTML. The HTML sample is as follows:
<pre><code>Your number is &lt;b&gt;123&lt;/b&gt;
</code></pre>
Now, how can I extract &quot;123&quot;, i.e. the contents of the first bold text after the string &quot;Your number is&quot;?

How to use regex to parse a number from HTML?

Python

我想用Python编写一个简单的正则表达式，从HTML中提取一个数字。HTML示例如下所示：Your number is 123现在，我如何提取"123"，即字符串"Your number is“之后的第一个粗体文本的内容？

问如何使用正则表达式从HTML中解析数字？
EN

回答 9

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问如何使用正则表达式从HTML中解析数字？
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