我正在尝试用python编写一个脚本来访问以下页面的内容:
https://authors.aps.org/Submissions/status/
到目前为止,我尝试通过以下方式使用urllib.urlopen:
import urllib
access_code = 'XXXXXXX'
author = 'xxxxxxx'
url = 'https://authors.aps.org/Submissions/status/'
login_data = {
'accode':access_code,
'author':author,
'submit':'Submit'
}
login_data = urllib.parse.urlencode(login_data).encode('utf-8')
urllib.request.urlopen(url, login_data)
但我总是得到
HTTP Error 404: Not Found
你有什么意见建议?
非常感谢!
发布于 2018-07-09 00:34:52
你可能想要这样的东西:
import urllib.request
import urllib.parse
access_code = 'XXXXXXX'
author = 'xxxxxxx'
login_data = urllib.parse.urlencode({
'accode': access_code,
'author': author
})
url = 'https://authors.aps.org/Submissions/status?utf8=%E2%9C%93&commit=Submit&{login_data}'.format(login_data=login_data)
with urllib.request.urlopen(url) as f:
print(f.read().decode('utf-8'))
https://stackoverflow.com/questions/51233792
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