使用类和方法的Python SMS存储程序- has_been_viewed状态
使用类和方法的Python SMS存储程序- has_been_viewed状态
提问于 2013-04-27 00:15:02
from datetime import datetime
class sms_store:
store = []
read = []
def add_new_arrival(self,number,time,text):
sms_store.read.append(len(sms_store.store))
sms_store.store.append(("From: {}, Recieved: {}, Msg: {}".format(number,time,text)))
def delete(self,i):
try:
del sms_store.store[i]
except IndexError:
print("Index is out of range. Cannot delete")
def message_count(self):
return print("Amt of messages in inbox: {}".format(len(sms_store.store)))
def viewall(self):
print(sms_store.store)
def get_unread_indexes(self):
#### ###################################I need help for this method.
def get_message(self,i)
print(sms_store.store[i])
### tests ####
time = datetime.now().strftime('%H:%M:%S')
my_inbox = sms_store() #instantiate an object 'store' for class
my_inbox.add_new_arrival("12345",time,"Hello how are you?") #instance of store object
my_inbox.add_new_arrival("1111111",time,"BYE BYE BYE")
my_inbox.viewall()
my_inbox.msgcount()感谢您观看这篇文章。
这就是我需要做的：
my_inbox.add_new_arrival()添加新消息时，其has_been_viewed状态设置为False。
my_inbox.get_unread_indexes()返回所有未查看短信的索引列表
my_inbox.get_message(i)**messagei的Return (from_number，time_arrived，text_of_sms)也将其状态改为“已被查看”。如果位置i处没有消息，则返回None
请在上面的方法上帮助我！？
非常感谢!
回答 3
Stack Overflow用户
回答已采纳
发布于 2013-04-27 00:37:14
为什么不向您的类添加另一个名为unread的列表。更改add_new_arrival以将邮件添加到未读。
然后，在get_message方法下，将指定的消息从unread移动到read。
最后，get_unread方法只列出未读列表的索引。
Stack Overflow用户
发布于 2016-03-20 04:30:17
嗨，我对你的代码做了一些调整，我想我以前在“如何像计算机科学家一样思考”一书中这样做过，希望它能为你工作。
from datetime import datetime和
class SMS_store:然后
def __init__(self):
self.store = []
def __str__(self):
return ("{0}".format(self))
def add_new_arrival(self, number, time, text ):
self.store.append(("Read: False", "From: "+number, "Recieved: "+time, "Msg: "+text))
def message_count(self):
return (len(self.store))
def get_unread_indexes(self):
result = []
for (i, v) in enumerate(self.store):
if v[0] == "Read: False":
result.append(i)
return (result)
def get_message(self, i):
msg = self.store[i]
msg = ("Read: True",) + msg[1:]
self.store[i] = (msg)
return (self.store[i][1:])
def delete(self, i):
del self.store[i]
def clear(self):
self.store = []Stack Overflow用户
发布于 2018-08-01 06:05:50
使用类和方法的Python SMS存储程序- has_been_viewed状态
import time
class SMS_store:
def __init__(self):
self.inbox = []
def add_new_arrival(self, from_number, text_of_sms,read_status = False):
number = str(from_number)
time_received = time.strftime("%D %T")
self.inbox.append([time_received, number, text_of_sms, read_status])
def message_count(self):
return "There are {0} messages in your Inbox".format(len(self.inbox))
def get_unread_indexes(self):
unread = []
for index, message in enumerate(self.inbox):
if False in message:
unread.append(index)
return "Unread Messages in:", unread
def get_message(self, index):
message = self.inbox[index]
message[3] = "Read"
return message[ : 3]
def delete(self, index):
del self.inbox[index]
return "Deleted Message", index
def clear(self):
self.inbox = []
return "Empty Inbox"页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/16240858
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