我正在尝试将我的测试框架与我的日志文件相关联,以找出哪些实例通过,哪些实例失败。为了更好地解释,这里有一个例子:我有一个列表:
data = ['F','P'] # first test pass, second test fail
下面是我的日志文件:
USER INPUT : “clear” ------
SYSTEM RESPONSE: “Hello! How are you?” | Fail
USER INPUT : “Good thank you” |
SYSTEM RESPONSE: "Okay" ------
USER INPUT : “clear” ------
SYSTEM RESPONSE: “Hello! How are you?” |
USER INPUT : “I am good, Thank you!” | Pass
SYSTEM RESPONSE: "Great!" |
USER INPUT : “Good” ------
因此," clear“的每个实例都会显示一个新的日志,因此,我希望第一个"clear”与P相关联,我使用html来构建代码,每当P出现时,它将是绿色的,而每当F出现时,代码将是红色的
到目前为止,我所拥有的是:
for line in lines :
for i in cc:
if (data[i]== 'P'):
n = """<p style="color:green;>""" + line + '</p>'
else:
n = """<p style="color:red;>""" + line + '</p>'
我对它的结构真的不太确定。如何在每次出现"clear“时查找,并为其分配特定的颜色,直到下一个实例出现。请随时问我任何关于这方面的问题或进一步澄清!非常感谢!
发布于 2018-07-31 03:15:56
您可以根据USER INPUT : "clear"
使用re
来拆分日志文件
log_file = """USER INPUT : “clear”
SYSTEM RESPONSE: “Hello! How are you?”
USER INPUT : “Good thank you”
SYSTEM RESPONSE: "Okay"
USER INPUT : “clear”
SYSTEM RESPONSE: “Hello! How are you?”
USER INPUT : “I am good, Thank you!”
SYSTEM RESPONSE: "Great!"
USER INPUT : “Good”"""
import re
from pprint import pprint
groups = re.findall(r'USER INPUT.*?clear.*?(?:(?=USER INPUT :\s+\Wclear\W)|(?=\Z))', log_file, flags=re.DOTALL)
data = ['F','P']
style = {'P': '<p style="color:green;>', 'F': '<p style="color:red;>'}
html = ''
for d, g in zip(data, groups):
for line in g.splitlines():
html += style[d] + line + '</p>\n'
pprint(html)
这将打印:
('<p style="color:red;>USER INPUT : “clear”</p>\n'
'<p style="color:red;>SYSTEM RESPONSE: “Hello! How are you?”</p>\n'
'<p style="color:red;>USER INPUT : “Good thank you”</p>\n'
'<p style="color:red;>SYSTEM RESPONSE: "Okay"</p>\n'
'<p style="color:green;>USER INPUT : “clear”</p>\n'
'<p style="color:green;>SYSTEM RESPONSE: “Hello! How are you?”</p>\n'
'<p style="color:green;>USER INPUT : “I am good, Thank you!”</p>\n'
'<p style="color:green;>SYSTEM RESPONSE: "Great!"</p>\n'
'<p style="color:green;>USER INPUT : “Good”</p>\n')
编辑:
我在网上做了一个例子regex works here是如何。
发布于 2018-07-31 02:37:07
最快捷的方法是一次读取所有文本,然后在USER INPUT : "clear"
上拆分。
# skip the first line since it's a clear, but not a separator
text = "\n".join(lines[1:])
split_on = 'USER INPUT : "clear" ------\n'
blocks = text.split(split_on)
html_lines = []
for pf, block in zip(data, blocks):
html_lines.append("<pre style='color:{};'>{}</pre>".format("green" if pf == "P" else "red", split_on + block))
with open("out.html", "w+") as outfile:
outfile.writelines(html_lines)
https://stackoverflow.com/questions/51600182
复制相似问题