PHP -当语句为true时隐藏元素
PHP -当语句为true时隐藏元素
提问于 2018-06-21 01:15:20
我有这段代码来隐藏元素，但是第一部分是隐藏的，第二部分总是显示出来，不管我是以用户还是管理员身份登录。我不明白那里出了什么问题。
我希望当我像用户登录时显示第一下拉内容，当我像管理员登录时显示第二下拉内容，但当我像用户或管理员登录时只显示第二下拉内容。
代码：
<?php
if($parola == $data['parola'] && $data['admin'] == '0'){?>
<div class="dropdown">
<button class="dropbtn"><?php echo $_SESSION['mail']; ?></button>
<div class="dropdown-content">
<a href="adauga.php">Adauga anunt</a>
<a href="anunturi.php">Anunturile mele</a>
<a href="edit.php">Editeaza profil</a>
<a href="logout.php">Delogeaza-te</a>
</div>
</div>
<?php } else { ?>
<div class="dropdown">
<button class="dropbtn"><?php echo $_SESSION['mail']; ?></button>
<div class="dropdown-content">
<a href="/admin/index.php">Control Panel</a>
<a href="logout.php">Delogeaza-te</a>
</div>
</div>
<?php } ?>
用户、管理员和禁用用户的登录。
<?php
require 'config.php';
if(isset($_POST['login'])) {
$errMsg = '';
// Get data from FORM
$mail = $_POST['mail'];
$parola = $_POST['parola'];
if($mail == '')
$errMsg = 'Introduceti adresa de mail.';
if($parola == '')
$errMsg = 'Introduceti parola.';
if($errMsg == '') {
try {
$stmt = $connect->prepare('SELECT mail, parola, admin, banned FROM acc_table WHERE mail = :mail');
$stmt->execute(array(
':mail' => $mail
));
$data = $stmt->fetch(PDO::FETCH_ASSOC);
if($data == false){
$errMsg = "Contul asociat cu mail-ul $mail nu a fost gasit.";
}
else {
if($parola == $data['parola'] and $data['admin'] == '1') {
$_SESSION['mail'] = $data['mail'];
$_SESSION['parola'] = $data['parola'];
$_SESSION['admin'] = $data['admin'];
header('Location: ../admin/index.php');
exit;
}
else
$errMsg = 'Parola nu este buna.';
}
if($parola == $data['parola'] and $data['banned'] == '1') {
$_SESSION['mail'] = $data['mail'];
$_SESSION['parola'] = $data['parola'];
$_SESSION['banned'] = $data['banned'];
header('Location: ban.html');
exit;
}
else
$errMsg = 'Parola nu este buna.';
if($parola == $data['parola'] and $data['admin'] == '0') {
$_SESSION['mail'] = $data['mail'];
$_SESSION['parola'] = $data['parola'];
$_SESSION['admin'] = $data['admin'];
header('Location: profile.php');
exit;
}
else
$errMsg = 'Parola nu este buna.';
}
catch(PDOException $e) {
$errMsg = $e->getMessage();
}
}
}
回答 3
Stack Overflow用户
回答已采纳
发布于 2018-06-21 14:31:07
我得到了我的问题的解决方案。
他没有使用头重定向，而是使用JavaScript。我使用以下命令强制用户停留在页面上：
<?php
if(['admin'] == '1')?>
<script>
window.location = 'admin/index.php';
</script>
感谢您为帮助我解决这个问题所做的贡献。
Stack Overflow用户
发布于 2018-06-21 02:13:28
尝试以下代码，看看这是否适用于您。
如果这不起作用，请让我知道你得到了什么错误。
<?php
require 'config.php';
if (isset($_POST['login'])) {
$errMsg = '';
// Get data from FORM
$mail = $_POST['mail'];
$parola = $_POST['parola'];
if ($mail == '') {
$errMsg = 'Introduceti adresa de mail.';
} else if ($parola == '') {
$errMsg = 'Introduceti parola.';
} else {
if ($errMsg == '') {
try {
$stmt = $connect->prepare("SELECT mail, parola, admin, banned FROM acc_table WHERE mail = :mail");
$stmt->bindParam(':mail', $var_mail);
$var_mail = $_POST['mail'];
$stmt->execute();
if ($data = $stmt->fetch()) {
if ($parola == $data['parola'] and $data['admin'] == '0') {
$_SESSION['mail'] = $data['mail'];
$_SESSION['parola'] = $data['parola'];
$_SESSION['admin'] = $data['admin'];
header('Location: profile.php');
exit;
} else if ($parola == $data['parola'] && $data['admin'] == '1') {
$_SESSION['mail'] = $data['mail'];
$_SESSION['parola'] = $data['parola'];
$_SESSION['admin'] = $data['admin'];
header('Location: ../admin/index.php');
exit;
} else if ($parola == $data['parola'] && $data['banned'] == '1') {
$_SESSION['mail'] = $data['mail'];
$_SESSION['parola'] = $data['parola'];
$_SESSION['banned'] = $data['banned'];
header('Location: ban.html');
exit;
} else {
$errMsg = 'Parola nu este buna.';
}
} else {
$errMsg = "Contul asociat cu mail-ul ".$var_mail." nu a fost gasit.";
}
}
catch(PDOException $e) {
$errMsg = $e->getMessage();
}
}
}
}Stack Overflow用户
发布于 2018-06-21 08:41:37
将if条件如下:-
if($data['admin'] === '0'){
//The rest code runs here
}让我知道这是否有效。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50953711
复制相关文章
相似问题
腾讯云开发者
