PHP。更改数组的数组中的值无效
PHP。更改数组的数组中的值无效
提问于 2018-06-30 05:03:57
非常奇怪的问题:我尝试使用json_encode和json_decode更改json字符串。我将json字符串转换为数组(实际上是数组的数组)，并尝试更改其中的一些数据。但不知何故，我无法在内部数组中更改数据。
$jsondata = ' {
"Id": "0400006",
"LastName": "Lincoln",
"FirstName": "Abraham",
"PreferredName": "Mr. Abraham Lincoln",
"BirthDate": "1992-06-20T00:00:00",
"PreferredEmailAddress": null,
"Addresses": [
{
"AddressId": "297143",
"Type": "Home",
"AddressLines": [
"201 S Grant Ave"
],
"AddressModifier": "",
"City": "Columbus",
"State": "OH",
"PostalCode": "43215",
"County": "049",
"Country": "",
"RouteCode": "",
"PhoneNumbers": [
{
"Number": "614-555-6666",
"Extension": "",
"TypeCode": "HOME"
}
],
"AddressLabel": [
"201 S Grant Ave",
"Columbus, OH 43215"
],
"PersonId": "0400006",
"EffectiveStartDate": "2008-06-13T00:00:00",
"EffectiveEndDate": null,
"IsPreferredAddress": true,
"IsPreferredResidence": true,
"TypeCode": "H",
"CountryCode": ""
},
{
"AddressId": "727032",
"Type": "Web Address",
"AddressLines": [
"285 E. Main Ave",
"Apt B"
],
"AddressModifier": "",
"City": "Columbus",
"State": "OH",
"PostalCode": "43215",
"County": "049",
"Country": "",
"RouteCode": "",
"PhoneNumbers": [
{
"Number": "614-555-6666",
"Extension": "",
"TypeCode": "HOME"
}
],
"AddressLabel": [
"285 E. Main Ave",
"Apt B",
"Columbus, OH 43215"
],
"PersonId": "0400006",
"EffectiveStartDate": "2018-06-25T00:00:00",
"EffectiveEndDate": null,
"IsPreferredAddress": false,
"IsPreferredResidence": false,
"TypeCode": "WEB",
"CountryCode": ""
}
],
"EmailAddresses": [],
"Phones": [
{
"Number": "614-555-6666",
"Extension": "",
"TypeCode": "HOME"
}
],
"AddressConfirmationDateTime": null,
"EmailAddressConfirmationDateTime": null,
"PhoneConfirmationDateTime": null,
"LastChangedDateTime": "2018-06-27T20:42:22Z",
"ChosenFirstName": "",
"ChosenMiddleName": "",
"ChosenLastName": "",
"PersonalPronounCode": "",
"IsDeceased": false
}
';
$newAddressData = [
"address1" => "5857 Newbridge Dr.",
"address2" => "Apt D",
"city" => "Chicago",
"state" => "Illions",
"postalcode" => "23456"
];
public function modifyData($jsonStr, $newAddressData){
$personInfoData = json_decode($jsonStr, true);
$addressArray = $personInfoData['Addresses'];
$webAddressObj = null;
foreach($addressArray as $address){
if($address['Type'] == 'Web Address' ){
$webAddressObj = &$address;
break;
}
}
if($webAddressObj != null){
echo("update it!");
$webAddressObj['AddressId'] ='';
$webAddressObj['PhoneNumbers']=[];
$webAddressObj['AddressLabel'] =[];
$webAddressObj['AddressLines'] =[$newAddressData['address1'], $newAddressData['address2']];
$webAddressObj['EffectiveStartDate']='';//2018-06-25T00:00:00
$webAddressObj['City']=$newAddressData['city'];
$webAddressObj['State']=$newAddressData['state'];
$webAddressObj['PostalCode']=$newAddressData['postalcode'];
}else{
echo("new address");
$newAddress = new AddressInfo();
$newAddress->Type = "Web Address";
$newAddress->TypeCode = "WEB";
$newAddress->AddressLines =[$newAddressData['address1'], $newAddressData['address2']];
$newAddress->EffectiveStartDate ='';
$newAddress->City = $newAddressData['city'];
$newAddress->State=$newAddressData['state'];
$newAddress->PostalCode=$newAddressData['postalcode'];
$newAddressJson = json_encode($newAddress);
$addressArray[] = $newAddressJson;
}
print_r($webAddressObj);
echo "<p>";
print_r($addressArray);
echo "<p>";
return $personInfoData;
}
$personalInfoData = modifyData($jsondata, $newAddressData);
echo json_encode($personalInfoData);========================================你会发现$personalInfoData并没有改变。
回答 1
Stack Overflow用户
回答已采纳
发布于 2018-06-30 05:12:27
这一点：$webAddressObj = &$address;不会创建对原始数组元素的引用。它创建对foreach创建的元素的临时副本的引用。在您跳出循环后，对该副本的引用将保持不变，但对其进行更改不会影响原始数组。
如果您希望引用原始元素，则还需要首先按引用分配$addressArray。
$addressArray = &$personInfoData['Addresses'];您需要在foreach循环中维护引用，例如
foreach($addressArray as &$address){而且你仍然需要像现在一样在循环中通过引用赋值。
$webAddressObj = &$address;与跟踪所有引用相比，如果直接通过键引用原始数组可能更容易。
$webAddressKey = null;
foreach($addressArray as $key => $address){
if($address['Type'] == 'Web Address' ){
$webAddressKey = $key;
break;
}
}
if($webAddressKey != null){
echo("update it!");
$personInfoData['Addresses'][$webAddressKey]['AddressId'] ='';
...
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/51109382
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