PHP PDO参数编号无效
PHP PDO参数编号无效
提问于 2018-06-22 17:14:40
下面是我的代码，我不能解决这个错误，我确实想把我的所有应用程序放在这里，但它太长了，我不能，所以我把它放在驱动器我只知道编程的基础知识，我的应用程序甚至不工作，所以没有什么可担心的https://drive.google.com/open?id=1n6q9PwPBXpJd1tmgR3nfXg_Caeba8g_g，这是我的完整应用程序我知道你不需要所有的代码，只是相关的，但我不知道什么是错的，所以我不知道什么是相关的，我会删除这个当你的帮助，如果它是必要的，谢谢大家。
<?php
//link files
require 'db.php';
$message = '';
//get user input from the form
if (isset ($_POST['placa']) && isset ($_POST['serialcarroria']) && isset ($_POST['serialchasis']) && isset ($_POST['serialmotor']) &&
isset ($_POST['marca']) && isset ($_POST['modelo']) && isset ($_POST['year']) &&
isset ($_POST['color']) && isset ($_POST['tipo']) && isset ($_POST['uso']) &&
isset ($_POST['nropuestos']) && isset ($_POST['nroejes']) && isset ($_POST['capcarga']) &&
isset ($_POST['servicio']) ) {
$placa = $_POST['placa'];
$serialcarroria = $_POST['serialcarroria'];
$serialchasis = $_POST['serialchasis'];
$serialmotor = $_POST['serialmotor'];
$marca = $_POST['marca'];
$modelo = $_POST['modelo'];
$year = $_POST['year'];
$color = $_POST['color'];
$tipo = $_POST['tipo'];
$uso = $_POST['uso'];
$nropuestos = $_POST['nropuestos'];
$nroejes = $_POST['nroejes'];
$capcarga = $_POST['capcarga'];
$servicio = $_POST['servicio'];
//SQL - add data to database
$sql = 'INSERT INTO vehiculo(placa,serialcarroria,serialchasis,serialmotor,marca,modelo,year,color,tipo,uso,nropuestos,nroejes,capcarga,servicio) VALUES(:placa,:serialcarroria,:serialchasis,:serialmotor,:marca,:modelo,:year,:color,:tipo,:uso,:nropuestos,:nroejes,:capcarga,:servicio)';
$statement = $connection->prepare($sql); //////<-PROBLEM ON THIS LINE//////
if ($statement->execute([':placa' => $placa, ':serialcarroria' => $serialcarroria , ':serialchasis' => $serialchasis , ':serialmotor' => $serialmotor, ':marca' => $marca, ':modelo' => $modelo,':year' => $year, ':color' => $color, ':tipo ' => $tipo ,':uso ' => $uso , ':nropuestos ' => $nropuestos , ':nroejes ' => $nroejes , ':capcarga ' => $capcarga , ':servicio ' => $servicio])) {
$message = 'data inserted successfully';
}
else {
$message = 'Sorry, there has been a problem inserting your details..';
}
}回答 1
Stack Overflow用户
回答已采纳
发布于 2018-06-23 01:39:26
试试我下面的代码，看看它是否能工作。让我知道你得到了什么错误
在您的<form>中，只需放置一个名称为id的隐藏文本框，如下所示：
<form>
<input type="hidden" name="id">
</form>然后在PHP中执行以下操作：
<?php
$host = "localhost";
$user = "db_user";
$pass = "db_pass";
$db = "db_name";
$charset = 'utf8mb4';
$dsn = "mysql:host=$host;dbname=$db;charset=$charset";
try {
$opt = [ PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION, PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC, PDO::ATTR_EMULATE_PREPARES => false, ];
$connection = new PDO($dsn, $user, $pass, $opt);
if (isset($_POST['placa'])) {
//I don't see a reason to have all of those isset...just make it so that there's one field that
//is absolutely required and cannot be left empty and work from there.
$statement = $connection->prepare("INSERT INTO vehiculo (id, placa, serialcarroria, serialchasis, serialmotor, marca, modelo, year, color, tipo, uso, nropuestos, nroejes, capcarga, servicio)
VALUES (:id, :placa, :serialcarroria, :serialchasis, :serialmotor, :marca, :modelo, :year, :color, :tipo, :uso, :nropuestos, :nroejes, :capcarga, :servicio)");
$statement->bindParam(':id', $id);
$statement->bindParam(':placa', $placa);
$statement->bindParam(':serialcarroria', $serialcarroria);
$statement->bindParam(':serialchasis', $serialchasis);
$statement->bindParam(':serialmotor', $serialmotor);
$statement->bindParam(':marca', $marca);
$statement->bindParam(':modelo', $modelo);
$statement->bindParam(':year', $year);
$statement->bindParam(':color', $color);
$statement->bindParam(':tipo', $tipo);
$statement->bindParam(':uso', $uso);
$statement->bindParam(':nropuestos', $nropuestos);
$statement->bindParam(':nroejes', $nroejes);
$statement->bindParam(':capcarga', $capcarga);
$statement->bindParam(':servicio', $servicio);
$id = $_POST['id'];
$placa = $_POST['placa'];
$serialcarroria = $_POST['serialcarroria'];
$serialchasis = $_POST['serialchasis'];
$serialmotor = $_POST['serialmotor'];
$marca = $_POST['marca'];
$modelo = $_POST['modelo'];
$year = $_POST['year'];
$color = $_POST['color'];
$tipo = $_POST['tipo'];
$uso = $_POST['uso'];
$nropuestos = $_POST['nropuestos'];
$nroejes = $_POST['nroejes'];
$capcarga = $_POST['capcarga'];
$servicio = $_POST['servicio'];
if ($statement->execute()) {
echo 'data inserted successfully';
} else {
echo 'Sorry, there has been a problem inserting your details..';
}
}
}
catch(PDOException $e) {
echo "Error: " . $e->getMessage();
}
$connection = null;
?>页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50984618
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